Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 2, Problem D2.52P
To determine
To design: A circuit based on the non-inverting configuration for the given gain.
The input resistance of the amplifier.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Suppose we have a resistive load that varies from 5 kΩ to 10 kΩ .We connect this load to an amplifier, and we need the voltage across the load to vary by less than 1 percent with variations in the load resistance. What parameter of the amplifier is important in this situation? What range of values is allowed for the parameter?
Note: 1Mega Ohms = 1000 Kilo Ohms
R1
ohms
R4
R2
ohms
ohms
R3
U1
ohms
Vout
V1
V2
V3
7. Summing Amplifier Rin is Equal.
Using the Circuit on #6. Find the output voltage of an op-amp
summing amplifier for the following sets of voltages and
resistors. Use Rf = 100 ohms.
VI = 1v, V2 = 2v, V3 = 3v, with a corresponding frequency of
60hz, R1 = R2 = R3 = 100k ohms, rail voltages of +15v and -15v.
Use UniversalOpAmp2. Take a Screenshot of your schematic
and the graph of the Vout.
5,
A+ A-
What output voltage results in the circuit below for an input of 0.5 V. Refer to the following for the values of Rf = 413981 ohms, R1 =
16788 ohms. Express your answer up to two decimal places.
...
V.
360 kQ
12 ko
Round your answer to 2 decimal places.
Chapter 2 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 2.1 - Prob. 2.1ECh. 2.1 - Prob. 2.2ECh. 2.1 - Prob. 2.3ECh. 2.2 - Prob. D2.4ECh. 2.2 - Prob. 2.5ECh. 2.2 - Prob. 2.6ECh. 2.2 - Prob. D2.7ECh. 2.2 - Prob. D2.8ECh. 2.3 - Prob. 2.9ECh. 2.3 - Prob. 2.10E
Ch. 2.3 - Prob. D2.11ECh. 2.3 - Prob. 2.12ECh. 2.3 - Prob. 2.13ECh. 2.3 - Prob. 2.14ECh. 2.4 - Prob. 2.15ECh. 2.4 - Prob. D2.16ECh. 2.4 - Prob. 2.17ECh. 2.5 - Prob. 2.18ECh. 2.5 - Prob. D2.19ECh. 2.5 - Prob. D2.20ECh. 2.6 - Prob. 2.21ECh. 2.6 - Prob. 2.22ECh. 2.6 - Prob. 2.23ECh. 2.6 - Prob. 2.24ECh. 2.6 - Prob. 2.25ECh. 2.7 - Prob. 2.26ECh. 2.7 - Prob. 2.27ECh. 2.7 - Prob. 2.28ECh. 2.8 - Prob. 2.29ECh. 2.8 - Prob. 2.30ECh. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10PCh. 2 - Prob. 2.11PCh. 2 - Prob. D2.12PCh. 2 - Prob. D2.13PCh. 2 - Prob. D2.14PCh. 2 - Prob. 2.15PCh. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. D2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. D2.26PCh. 2 - Prob. 2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. D2.29PCh. 2 - Prob. 2.30PCh. 2 - Prob. 2.31PCh. 2 - Prob. 2.32PCh. 2 - Prob. D2.33PCh. 2 - Prob. D2.34PCh. 2 - Prob. D2.35PCh. 2 - Prob. 2.36PCh. 2 - Prob. D2.37PCh. 2 - Prob. D2.38PCh. 2 - Prob. D2.39PCh. 2 - Prob. D2.40PCh. 2 - Prob. D2.41PCh. 2 - Prob. D2.42PCh. 2 - Prob. 2.43PCh. 2 - Prob. D2.44PCh. 2 - Prob. D2.45PCh. 2 - Prob. D2.46PCh. 2 - Prob. D2.47PCh. 2 - Prob. D2.48PCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. D2.51PCh. 2 - Prob. D2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. D2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. D2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. D2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. D2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. D2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. D2.76PCh. 2 - Prob. 2.77PCh. 2 - Prob. 2.78PCh. 2 - Prob. 2.79PCh. 2 - Prob. D2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. D2.82PCh. 2 - Prob. D2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. D2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. D2.92PCh. 2 - Prob. D2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. D2.99PCh. 2 - Prob. D2.100PCh. 2 - Prob. 2.101PCh. 2 - Prob. 2.102PCh. 2 - Prob. 2.103PCh. 2 - Prob. 2.104PCh. 2 - Prob. 2.105PCh. 2 - Prob. 2.106PCh. 2 - Prob. 2.107PCh. 2 - Prob. 2.108PCh. 2 - Prob. 2.109PCh. 2 - Prob. 2.110PCh. 2 - Prob. 2.111PCh. 2 - Prob. 2.112PCh. 2 - Prob. 2.113PCh. 2 - Prob. 2.114PCh. 2 - Prob. 2.115PCh. 2 - Prob. D2.116PCh. 2 - Prob. D2.117PCh. 2 - Prob. D2.118PCh. 2 - Prob. 2.119PCh. 2 - Prob. 2.120PCh. 2 - Prob. 2.121PCh. 2 - Prob. 2.122PCh. 2 - Prob. 2.123PCh. 2 - Prob. 2.124PCh. 2 - Prob. 2.125PCh. 2 - Prob. 2.126PCh. 2 - Prob. D2.127P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- 1. Calculate the voltage of an inverting op-amp summing amplifier for the following for the following sets of resistors. Use Rf = 1 M ohms in all cases.arrow_forwardFind the output voltage vO in the following figure if the op-amp is ideal and VZ = 12 V. Find the values of the emitter current and the total current supplied by the 15-V source. Assume βF = 62. Find the op-amp output voltage. Given that R1 = 53 kΩ and R2 = 104 kΩ.arrow_forwardFor this op amp, an equation needs to be made for V0 = Va + Vb. I thought it was -4(Va) + 4(Vb) as the difference, but that doesn't seem to be correct. The voltage limits for the output voltage are -0.8 V less than or equal to Vo less than or equal to 3.2 V. Can you show how to set up the equation for V0?arrow_forward
- In the difference amplifier circuit given in the figure, R1 = 8kQ, R2 = 80kQ,R3=4kQ, and R4 is given as 40kQ. a) vo output voltagevo and vi2 as appropriate for you. b) Find the value of the output voltage v0 for vı₁ = 4V and vı2 = 7V.arrow_forwardUse the figure below for the following questions. R = 10\OmegaR=10Ω and V_{in}Vin is a 5V DC source that can provide a maximum of 1 mA of current. The op-amp is ideal. What is I_{out}Iout in milliamps? If the buffer is removed and the source is connected directly to R, what is V_oVo in volts?arrow_forwarda) Design an inverting operational amplifier that has an adjustable voltage gain between v = -10 and v = ở using a 100 k potentiometer Ra and another resistor Re. Determine RE. %3D b) Repeat part a) for a voltage gain between v = -10 and v = -1. A suitable resistor Rz in series to the potentiometer is required so that the gain cannot go to zero. Find Rz and RE.arrow_forward
- 1. Use the figure below for the following questions. R = 10N and V is a 5V DC source that can provide a maximum of 1 mA of current. The op-amp is ideal. Vin R Vo What is V, in volts? Enter answer here 2. What is Iut in miliamps?arrow_forward2K The op amp used in the inverting amplifier circuit is not ideal. In fact, it is an LM741 with the following parameters: v W Rin = 2 MQ, AoL = 200 V/mV, Rout = 200 Q. Determine the gain vo/vi of the op amp circuit. If the gain computed in a is the actual gain, what is the percentage accuracy of the computed gain if the op amp is considered ideal? 4. 1K vo а. b.arrow_forwardVsource Rsource Rin ww 175V b) the voltage across the load resistor iin + Vin Avo i out w -Ro R₁oad + + Vload An amplifier has the following characteristics: Rin = 5 kn, Ro= 300 Q and Ayo = 35. If it is connected to a 0.2 V source with a series resistance of 100 2 at the input and a load resistor of 2 k at the output, determine a) the overall voltage gain, G,arrow_forward
- From Figure 3, write node-voltage equations: one for each input a. terminal of the op amp. b. The expression for the load current (i.) can be written as a function of the input voltage (V) and the load voltage (v.) iz = Avin + Bv, b.1. What is the expression for A? What should be the condition for R, R, R, and R4, so that B is b.2. zero? (NB: this condition will make i, depend only on v, and not on R.) R4 R3 OA1 R2 R1 RL Vin VL iL Figure 3arrow_forwardFor the op amp circuit, find the voltage gain vo/vs. assume R1= 100 ohms, R2= 150 ohms, Rf= 500 ohmsarrow_forwardThe exercise question is: find the voltage gain and input resistance to the following circuit. Second, explain why no current flows through the 20 kOhm resistor that is connected to ground.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning
Multistage Transistor Audio Amplifier Circuit; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=LJrL9N9uhkE;License: Standard Youtube License