Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 2, Problem D2.38P
To determine
To design: An op-amp circuit to give a desired output.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Consider the op amp circuit given below, where v₁ = -3 V, V3 = 5 V, R₁ = 10 k, R₂ = 20
kQ, and R3 = 43 k. Determine the value of v2 in order to make vo = -7.5 V.
50 ΚΩ
V₂0
R₁
www
R₂
R3
V30Mw
The value of V2 is
V.
Vo
Design an op-amp circuit to yield the relationship shown in each equation.
Vo = V1 + 10V2 – 30V3 – 100 V4a.) Rmin = 6kΩb.) Rin = 6kΩ
Vin
R₁
www
R₂
www
Vout
For the given op amp circuit, calculate Vout if R₁ = R2 = 100 2 and vin = 8 V.
The value of the output voltage is
* V.
Chapter 2 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 2.1 - Prob. 2.1ECh. 2.1 - Prob. 2.2ECh. 2.1 - Prob. 2.3ECh. 2.2 - Prob. D2.4ECh. 2.2 - Prob. 2.5ECh. 2.2 - Prob. 2.6ECh. 2.2 - Prob. D2.7ECh. 2.2 - Prob. D2.8ECh. 2.3 - Prob. 2.9ECh. 2.3 - Prob. 2.10E
Ch. 2.3 - Prob. D2.11ECh. 2.3 - Prob. 2.12ECh. 2.3 - Prob. 2.13ECh. 2.3 - Prob. 2.14ECh. 2.4 - Prob. 2.15ECh. 2.4 - Prob. D2.16ECh. 2.4 - Prob. 2.17ECh. 2.5 - Prob. 2.18ECh. 2.5 - Prob. D2.19ECh. 2.5 - Prob. D2.20ECh. 2.6 - Prob. 2.21ECh. 2.6 - Prob. 2.22ECh. 2.6 - Prob. 2.23ECh. 2.6 - Prob. 2.24ECh. 2.6 - Prob. 2.25ECh. 2.7 - Prob. 2.26ECh. 2.7 - Prob. 2.27ECh. 2.7 - Prob. 2.28ECh. 2.8 - Prob. 2.29ECh. 2.8 - Prob. 2.30ECh. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10PCh. 2 - Prob. 2.11PCh. 2 - Prob. D2.12PCh. 2 - Prob. D2.13PCh. 2 - Prob. D2.14PCh. 2 - Prob. 2.15PCh. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. D2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. D2.26PCh. 2 - Prob. 2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. D2.29PCh. 2 - Prob. 2.30PCh. 2 - Prob. 2.31PCh. 2 - Prob. 2.32PCh. 2 - Prob. D2.33PCh. 2 - Prob. D2.34PCh. 2 - Prob. D2.35PCh. 2 - Prob. 2.36PCh. 2 - Prob. D2.37PCh. 2 - Prob. D2.38PCh. 2 - Prob. D2.39PCh. 2 - Prob. D2.40PCh. 2 - Prob. D2.41PCh. 2 - Prob. D2.42PCh. 2 - Prob. 2.43PCh. 2 - Prob. D2.44PCh. 2 - Prob. D2.45PCh. 2 - Prob. D2.46PCh. 2 - Prob. D2.47PCh. 2 - Prob. D2.48PCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. D2.51PCh. 2 - Prob. D2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. D2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. D2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. D2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. D2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. D2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. D2.76PCh. 2 - Prob. 2.77PCh. 2 - Prob. 2.78PCh. 2 - Prob. 2.79PCh. 2 - Prob. D2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. D2.82PCh. 2 - Prob. D2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. D2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. D2.92PCh. 2 - Prob. D2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. D2.99PCh. 2 - Prob. D2.100PCh. 2 - Prob. 2.101PCh. 2 - Prob. 2.102PCh. 2 - Prob. 2.103PCh. 2 - Prob. 2.104PCh. 2 - Prob. 2.105PCh. 2 - Prob. 2.106PCh. 2 - Prob. 2.107PCh. 2 - Prob. 2.108PCh. 2 - Prob. 2.109PCh. 2 - Prob. 2.110PCh. 2 - Prob. 2.111PCh. 2 - Prob. 2.112PCh. 2 - Prob. 2.113PCh. 2 - Prob. 2.114PCh. 2 - Prob. 2.115PCh. 2 - Prob. D2.116PCh. 2 - Prob. D2.117PCh. 2 - Prob. D2.118PCh. 2 - Prob. 2.119PCh. 2 - Prob. 2.120PCh. 2 - Prob. 2.121PCh. 2 - Prob. 2.122PCh. 2 - Prob. 2.123PCh. 2 - Prob. 2.124PCh. 2 - Prob. 2.125PCh. 2 - Prob. 2.126PCh. 2 - Prob. D2.127P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- 3. DERIVE THE TIME AND FREQUENCY DOMAIN MODEL OF THE NON-INVERTING OP-AMP SHOWN IN THE SCHEMATIC DIAGRAM BELOW. NOTE: INPUT: v₂ (t) or V₁(s) OUTPUT: v(t) or V. (s) R₁ = 10kΩ C₁ = 1nF R₂ = 50kn C₂ = 1nF Vi(t) R1 C1 $ C2 R2 Vo(t) PLOT THE SYSTEM TIME RESPONE AND FREQUENCY RESPONSE.arrow_forwardHow to create a circuit that has three varying input voltages and one output voltage that is equal to the average of the three? Vin = V1, V2, V3Vout = (V1 + V2 + V3) / 3 Example:V1 = 750mV, V2 = 700mV, V3 = 800mVVo = 750mV You can only use resistors and OpAmps (operational amplifiers), show circuit schematic and computations/formulas usedarrow_forwardQ2) For the following ideal Op amp: a) What circuit configuration is shown in this figure? b) Find V if V₁ = 1V, Vb = 1.5 V, and Vc = -4 V. c) Use Multisim Live to verify the V, in part (b) and include a snapshot of the circuit and the resulting Vo 220 ΚΩ Va 44 ΚΩ 27.5 ΚΩ ww 80 ΚΩ ww vv vc + 10 V -10 V + 0 §3.3 ΚΩ Voarrow_forward
- R₁ 1kΩ +15 V R₂ 1 ΚΩ R3 1kΩ -15 V VREF VINO- Op-amp + - VOUT A comparator circuit is shown above. An output voltage is generated that is negative if VREF > VIN; otherwise, it is positive. The op-amp doesn't load either input. What is the range of VREF?arrow_forwardUse the given circuit diagram for answering the following questions (a) Identify the given op-amp circuit and explain its operation. (b) Derive an equation for its output voltage. (c) Write any two applications of this circuit. R1 R2 ½ a WW a R3 V3 o Ww Vo -1arrow_forwardConsider the op-amp circuit below. Given the input voltage V₁=0.2V, calculate the output voltages V₂ and V3. V₁=0.2 V 20 ΚΩ www 10 ΚΩ 200 ΚΩ www 200 k www V₂ V₂arrow_forward
- A inverting op amp circuit is shown. Find vo. a. b. What is the current in? c. What are the voltages v₂ and vp at the (-) and (+) inputs? 3 V 3 ΚΩ + Vn Up 12 ΚΩ 15 V -15 V C Carson Education, at highted + vo 6 kNarrow_forwardUse two ideal op amps and resistors to implement the function. Vo = V₁ + 3√₂-2√₂-524arrow_forwardFor the op amp circuit shown below, what is Vout for the V1 plot shown. Plot the results: (Provide your calculations and reasoning for your answer.) U1 Vout OUT OPAMP C1 R1 2u 10k V1 Input Voltage to Circuit 4 3.5 3 2.5 2 15 0.5 > -05 0 20 10 15 25 30 -1 -15 -2 -2.5 -3 -3.5 -4 Time (msec) %24 (A) TAarrow_forward
- 2. Calculate the value of vo in the circuit at right. The op amps are ideal. R, 10 k2 R1. 4.7 k2 2.5 mA 10 k2 1 k2arrow_forwardFor the circuit below, Assume constant-voltage model VD,on =800 mV and VB=1.4 V. In this circuit, Vin is increased from 0 to a finite value. At what value of Vin, does D1 starts to conduct? What is the current of resistor R1= 2kΩ, if Vin=5 V? What is the output voltage, Vout, if Vin=5 V? What is the voltage across R1 if Vin = 5 V? What is the current of resistor R1= 2kΩ, if Vin=1.8 V? What is the output voltage, Vout, if Vin=1.8 V?arrow_forwardConsider the following circuit where the Op Amp is ideal: Assuming VA = 0.39 V, VB = -0.20 V, and R₂ = 10k. Find the value of the resistor R₁ in k such that Vout VA R₁ www Previous VB Type your answer... R₂ ww +5 V + -5 V Vout 5ΚΩ : -3.8V =arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSONDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage LearningProgrammable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
- Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill EducationElectric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSONEngineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:9780078028229
Author:Charles K Alexander, Matthew Sadiku
Publisher:McGraw-Hill Education
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:9780134746968
Author:James W. Nilsson, Susan Riedel
Publisher:PEARSON
Engineering Electromagnetics
Electrical Engineering
ISBN:9780078028151
Author:Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:Mcgraw-hill Education,
Electrical Engineering: Ch 5: Operational Amp (2 of 28) Inverting Amplifier-Basic Operation; Author: Michel van Biezen;https://www.youtube.com/watch?v=x2xxOKOTwM4;License: Standard YouTube License, CC-BY