Biology 2e
2nd Edition
ISBN: 9781947172517
Author: Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher: OpenStax
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Textbook Question
Chapter 12, Problem 18RQ
The forked line and probability methods make use of what probability rule?
- test cross
- product rule
- monohybrid rule
- sum rule
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Chapter 12 Solutions
Biology 2e
Ch. 12 - Figure 12.5 In pea plants, round peas (R) are...Ch. 12 - Figure 12.6 What are the genotypes of the...Ch. 12 - Figure 12.12 What ratio of offspring would result...Ch. 12 - Figure 12.16 In pea plants, purple flowers (P) are...Ch. 12 - Mendel performed hybridizations by transferring...Ch. 12 - Which is one of the seven characteristics that...Ch. 12 - Imagine you are performing a cross involving seed...Ch. 12 - Consider a cross to investigate the pea pod...Ch. 12 - A scientist pollinates a true-breeding pea plant...Ch. 12 - The observable traits expressed by an organism are...
Ch. 12 - A recessive trait will be observed in individuals...Ch. 12 - If black and white true-breeding mice are mated...Ch. 12 - The ABO blood groups in humans are expressed as...Ch. 12 - In a mating between two individuals that are...Ch. 12 - If the allele encoding polydactyly (six fingers)...Ch. 12 - A farmer raises black and white chickens. To his...Ch. 12 - Assuming no gene linkage, in a dihybrid cross of...Ch. 12 - The forked line and probability methods make use...Ch. 12 - How many different offspring genotypes are...Ch. 12 - Labrador retriever's fur color is controlled by...Ch. 12 - Which of the following situations does not follow...Ch. 12 - Describe one of the reasons why the garden pea was...Ch. 12 - How would you perform a reciprocal cross for the...Ch. 12 - Mendel performs a cross using a true-breeding pea...Ch. 12 - Calculate the probability of selecting a heart or...Ch. 12 - The gene for flower position in pea plants exists...Ch. 12 - Use a Punnett square to predict the offspring in a...Ch. 12 - Can a human male be a carrier of red-green color...Ch. 12 - Why is it more efficient to perform a test cross...Ch. 12 - Use the probability method to calculate the...Ch. 12 - Explain epistatis in terms of its Greek-language...Ch. 12 - In Section 12.3, ''Laws of Inheritance," an...Ch. 12 - People with trisomy 21 develop Down’s syndrome....Ch. 12 - A heterozygous pea plant produces violet flowers...
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- The forked line and probability methods make use of what probability rule? a. test cross b. product rule c. monohybrid rule d. sum rulearrow_forwardWhen a chi square test is applied to solve a linkage problem, explain why an independent assortment hypothesis is proposed.arrow_forwardGive typing answer with explanation and conclusion Directions: For the following problem, calculate the probability of the offspring between the cross using the sum and product rule. The parent generation has genotypes of Aa Bb Cc and AA Bb CC. What is the probability the F1 generation would be AA bb cc?arrow_forward
- Suppose we have the following table in our goodness of fit test results: Variable/Condition Value p-value 0.077 Significance level 0.05 Conclusion then what do we write in the cell corresponding to "Conclusion"? Suppose we have the following table in our goodness of fit test results: Variable/Condition Value p-value 0.077 Significance level 0.05 Conclusion then what do we write in the cell corresponding to "Conclusion"? We change the significance level to 0.95. We accept the null hypothesis that the disease possibly follows the specified mode of inheritance at the given gene. We reject the null hypothesis that the disease possibly follows the specified mode of inheritance at the given gene. We accept the null hypothesis that the disease almost certainly follows the specified mode of inheritance at the given gene. We collect more data.arrow_forwardYou have determined that the gene order for three linked genes being studied is A B C. The number of recombinants resulting from crossover between genes A and BC are 44 and 48, respectively, while the double-crossover progeny total 4 and 6. What is the recombination frequency between genes A and B if the total progeny from the cross is 1000? Show all of your work.arrow_forwardUse the forkline method to derive the gametic ratio of cross AabbDD x AABbDd. The cross are segregated independently.arrow_forward
- In a monohybrid cross of two heterozygous parents (Pp), what would the expected genotypes of the offspring be? show your solutionarrow_forwardWhat would justify the following ratio appearing after phenotyping the outcome of a crossing trial: 8.9: 2.9: 3.2:1? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a b C d Obviously this represents independent assortment based on crossing dihybrid heterozygotes. Obviously this represents gene linkage based on test crossing a dihybrid heterozygote. Obviously this represents the results of a trihybrid test cross. Obviously this represents independent assortment based on crossing monohybrid heterozygotes.arrow_forwardWhat disorder is shown in the following karyotype? Explain your reasoning and describe any other information that the karyotype shows. %3D 2 3 4 5 11 6 7 8 9 10 %3D %3D 11 12 13 14 15 16 17 18 19 20 21 22arrow_forward
- In a series of three experiments, M. G. Addo sought to use chi-square test to determine the goodness of fit at 5% for each of his results below. Carry out the calculations and determine whether the results obtained in each case are consistent with the 3:1 or 1:1:1:1 ratio he predicted in his hypothesis. Comment on your results. CROSS Tall x short Purple x white Round yellow (F1) x Wrinkled green (F1) RESULTS HΥΡΟΤHESIS 712:352 3:1 705 : 224 3:1 31:26:27:26 1:1:1:1arrow_forwardThe gel image above shows 7 alleles, let's call them 1-7 in order of size, with 1 being the largest and 7 being the smallest. What is the approximate size in Kbp of allele 4? Please type your answer as a number, please do not add units. ANSWER: The approximate size of allele 4 in the gel image below is Blank 1 Kbp Photograph of UV illuminated 1 % agarose TBE gel run for 40 minutes at 120 V, showing the result of PCR from a variable number tandem repeat region in 11 different individuals (A-K) 2000 1650 1000 850 600 500 Key: Lane 1: Lanes 2-12: A B C D E F G H I J K DNA ladder, see image for fragment sizes in base pairs (bp) PCR Products from the same variable number tandem repeat (VNTR) autosomal region of DNA from 11 different individuals (A-K)arrow_forwardWhat is the mis-application of probability or the simple but incorrect solution?arrow_forward
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