When performing a forward genetic screen, it is helpful to start with a _______ population Question 10 options: isogenic heterogeneous epigenetic pleiotropic small wild heterozygous dioecious dimorphic
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When performing a forward genetic screen, it is helpful to start with a _______ population
Question 10 options:
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isogenic |
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heterogeneous |
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epigenetic |
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pleiotropic |
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small |
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wild |
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heterozygous |
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dioecious |
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dimorphic |
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- The Meeting Sarah stared blankly at the blue paisley wallpaper. Her husband Mike sat by her side, bending and unbending a small paper clip. “Sarah and Michael, it’s good to meet you,” welcomed the genetic counselor, as she entered the room. “I apologize for being late, but I was just meeting with another couple. Let’s see, you’d like to have a child, but you’re concerned because of your family history of cystic fibrosis.” “Yes,” Sarah replied softly. “Mike and I met at a CF support group meeting a few years ago. He had a younger brother who died of cystic fibrosis, and I had a younger sister. We saw the painful lives they had—difficulty breathing, the constant respiratory infections. Although the treatments for CF are better now, we just don’t know if we can…” she trailed off. “I can certainly understand your concern,” the genetic counselor responded sympathetically. “That’s where I hope to help, by providing as much information and advice as I can. I’m glad that you came to see me…Below is a pedigree showing transmission of a disease; affected individuals are indicated by solid circles or boxes. Represented below the pedigree are two nylon membranes; DNA samples from each individual in the pedigree were spotted in identical fashion on each membrane. Each individual's DNA appears directly below his or her position in the pedigree. Each membrane was hybridized with allele specific oligonucleotides that detect the two alternative alleles of a single SNP locus (ASO 1 and ASO 2). Positive hybridization is represented as a filled circle and lack of hybridization is represented as an open circle. I 11 III IV V ASO 1 ASO 2 To 1 2 3 4 5 6 a. What is the mode of transmission of this disease? 12 b. Which SNP allele (ASO1 or ASO2) is originally linked to the disease gene? c. Draw a diagram of the event that gave rise to the genotype of individual IV-5. d. Individual V-1 is an unborn fetus. If the SNP locus is 10 CM from the disease locus, what is the likelihood that he will…Use keyboard only to enter your answer below. ALL WORKING MUST BE SHOWN Problem 1) mutation in a gene on chromosome 15 that codes for an enzyme. The disease is an inherited autosomal recessive condition which is Tay-Sachs disease is caused by loss of function found amongst Ashkenazi Jews of Central European origin. In this population, 3 in 5,200 children are born with the disease. What proportion of the population are carriers (heterozygotes) for this disease?
- The purpose of this assignment is to understand the principles of Mendelian and human genetics and the structure of DNA and how genetic code is converted to protein. After completing the three Unit 6 Labs on Connect (above), apply critical thinking to answer the following:1. Fruit Flies and Genetics Research: Imagine you are working in a genetics lab with the fruit fly Drosophila melanogaster, a model organism for genetics research. You want to determine whether a trait you have discovered in fruit flies is dominant or recessive.• Explain how you would design an experiment to answer this question.• Predict what types of outcomes are possible. Which would indicate that the trait is dominant? Which would indicate that it is recessive?2. Model Genetic Organisms: Why are fruit flies considered a model genetic organism? Would humans fit this description?Name Addie weal Bikini Bottom Genetics Scientists at Bikini Bottoms have been investigating the genetic makeup of the organisms in this community. Use the information provided and your knowledge of genetics to answer each question. 1. For each genotype below, indicate whether it is a heterozygous (He) OR homozygous (Ho). TT Bb DD Dd ff Tt Which of the genotypes in #1 would be considered purebred? Which of the genotypes in #1 would be hybrids?. Ff bb Yy Square shape is dominant to round. SS Ss yy tt 2. Determine the phenotype for each genotype using the information provided about SpongeBob. Yellow body color is dominant to blue. YY SS BB 3. For each phenotype, give the genotypes that are possible for Patrick. A tall head (T) is dominant to short (t). Tall= Short = Pink body color (P) is dominant to yellow (p). Pink body= Yellow body = dd FF 4. SpongeBob SquarePants recently met SpongeSusie Roundpants at a dance. SpongeBob is heterozygous for his square shape, but SpongeSusie is round.…Question 1 During nucleic acid hybridization, the probe is labelled for DNA stability to increase probe-test DNA binding to identify the location of probe and the test DNA binding for amplification Question 2 10 IV 8 10 11 12 13 14 Which of the following best describes the trait in the pedigree? Question 2 options: X-linked dominant X-linked recessive autosomal domiant autosomal recessive
- The picture shows a gel of PCR products for the loci SRY, AMELX/Y and ZFX/Y, for three controls and five test human individuals (1-5). Below the gel is the phenotypic sex of each individual, their fertility status, and the number of Barr bodies seen in the nucleus of a somatic cell in each case. The diagram to the right shows the positions of the tested loci on the human sex chromosomes, and also the positions of the PRKX and PRKYgenes. Which sample carries a derived X chromosome with a translocation due to ectopic crossover between the loci PRKX and PRKY: 46,X,derX,t(X,Y); ? 1 2 3 4 5A proband female with an unidentified disease seeks the advice of a genetic counselor before starting a family. Based on the following data, the counselor constructs a pedigree encompassing three generations: (1) The maternal grandfather of the proband has the disease. (2) The mother of the proband is unaffected and is the youngest of five children, the three oldest being male. (3) The proband has an affected older sister, but the youngest siblings are unaffected twins (boy and girl). (4) All the individuals who have the disease have been revealed. Duplicate the counselors featIl-- Results from a single locus probe DNA fingerprint analysis for a man and woman and their four children are shown in the autoradiograph below. Which child is least likely to be the biological offspring of this couple? Explain Why? mother child 2 fathe child 4 child 3 child 1 1 2 3 4 5 6
- This question has two parts. Below is a Manhattan plot from a GWAS investigating microcirculation (circulation of blood through the smallest blood vessels). Changes in microcirculation can be correlated to increased risk of cardiovascular events. For our purposes we will consider the -log10(P) of about 7 as the significance threshold. 15 10 - log10 (P) 2 Part 1 3 8 chromosome 6 - OL ·LL Į Image available for use under Creative Commons Attribution 2.5 Generic License. Sourced from: https://commons.wikimedia.org/wiki/File:Manhattan Plot.png Attribution: Ikram MK et al (2010) Four Novel Loci (19q13, 6q24, 12q24, and 5q14) Influence the Microcirculation In Vivo. PLoS Genet. 2010 Oct 28;6(10):e1001184. doi:10.1371/journal.pgen.1001184.g001A couple enters your genetic counseling clinic for some family planning advice. The woman’s father was color blind, but her own vision is normal. The man has no family history of color blindness. Neither the man nor woman have any known history of hemophilia, but their first child (a boy) has hemophilia. They ask you to calculate the chance that their nextchild will be affected by one or both conditions. You remember from your genetics training that these are both X-linked recessive conditions and that they are closely linked: in fact, their genetic loci are separated by only 10cM! During the interview with this couple, you draw the following pedigree to represent their information. Given what you know, determine for this couple what chance they have of each of the following (in the table).Using figure 1 and the following background information answer the following questions. Identification of the genetic cause of hornlessness in cattle has been the subject of intensive genetic and genomic research, culminating in the nomination of two different candidate neomutations on cattle chromosome 1 that are predicted to have arisen 500-1,000 years ago: a complex allele of Friesian origin (PF), an 80,128 base pair (bp) duplication (1909352–1989480 bp), and a second, simple allele of Celtic origin (PC) corresponding to a duplication of 212 bp (chromosome 1 positions 1705834–1706045) in place of a 10-bp deletion (1706051–1706060)We report the use of genome editing using transcription activator-like effector nucleases (TALENs) to introgress the putative PC POLLED allele into the genome of bovine embryo fibroblasts to try and produce a genotype identical to what is achievable using natural mating, but without the attendant genetic drag and admixture. In our previous studies, we…
