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- Using the following lung volumes, calculate this persons FEV1 / FVC ratio. What this person's pulmonary function be clinically classified: normal, obstructive, or restricted? TLC = 5.2 L FVC = 3.8 TV = 0.5 L ERV = 1.1 L IRV = 2.2 L This person forcefully expired 2.4 L in one second. according to reference material, normal VC for this person is 3.6 L.Which option best describes the following figure? Y (fraction saturation) 1.0 0.8 0.6 0.4 0.2 0.0 0 20 Oxygen Binding plot 40 60 p02 (torr) 80 100 A) Curve x = adult haemoglobin, curve y = fetal haemoglobin B) Curve x = myoglobin, curve y = haemoglobin C) Curve x = fetal haemoglobin, curve y = adult haemoglobin D) Curve x = fetal haemoglobin, curve y = myoglobin E) Curve x = adult haemoglobin, curve y - myoglobinA female patient has presented with the following results for spirometry and plasma Po2. What is your diagnosis? Parameter Vital Capacity FEV₁ FVC Arterial Po2 Venous Po2 COPD O Pulmonary fibrosis Pulmonary oedema Value 3160 ml 2420 ml 3020 ml 100 mmHg 53 mmHg O Methemoglobinaemia (causes a leftward shift in the oxygen-haemoglobin dissociation curve)
- A child weighing 22 lbs, has an infection and the doctor orders erythromycin drops 2.0 mLp.o. q6h. The bottle states that the usual dosage is 20.0-40.0 mg/kg/day, and there are35.0 mg per 1.5 mL. Find the min and max dosage per day in mL. Is the order within therecommended dosage?A female patient has presented with the following results for spirometry and plasma Po2. What is your diagnosis? (You may need to look up the normal ranges for a female). Parameter Vital Capacity FEV₁ FVC Arterial Po2 Venous Po2 COPD Value 2120 ml 1450 ml 1810 ml 87 mmHg 34 mmHg Pulmonary fibrosis O Pulmonary oedema O Methemoglobinaemia (causes a leftward shift in the oxygen-haemoglobin dissociation curve)Approximately 0.3 mL of O2 is physically dissolved in each 100 mL of blood for every PaO2 increase of 100 mm Hg. is True or False explain
- The arterial O₂ concentration is given by the following expression [0₂] = 0.003 P0₂ + (PO₂)².8 +(26) 2.8 1. ЗЧНЬ (Рог ) 2-8 Where Poz is the alveolar O₂ pressure and Hb is the hemoglobin concentration in g/dL, respectively A subject who is at 0-95 ATM (211-0₂) has an arterial O₂ concentration of 19ml/dL and and arterial CO₂ pressure of 38mm Hg. Also, VO₂ = 340mL/min.; VCD₂ = 289 mL/min. Therefore, your hemoglobine level is: A. 14.39 Idl 8. 14.8 g/dl C. 15.2 g/dl D. 15.7g/dL E. 16 g/dLBelow is an oxygen-binding curve for two hemoglobin variants. 1.0 0.8 0.6 B 0.4 0.2 20 40 60 80 100 O2 pressure (torr) Determine the p50 for variant A to the nearest 5 torr (i.e., if the p50 was 12, you would write 10). Determine the fraction of the hemoglobin B bound with O2 in the lungs (pO2 = 100 torr) that delivers oxygen to the tissues (pO2 = 20 torr)? Answer to the nearest 0.05 value (for example, 0.10 or 0.15). Which hemoglobin variant (write A or B or same) delivers more oxygen to tissues? Fraction bound with O2p02 Y O2 (mmHg) 0.5 0.161 1 0.277 0.434 3 0.535 4. 0.605 0.697 0.754 12 0.821 20 0.885 Using the data provided in the table, the estimated p50 for myoglobin is mmHg and the fraction saturation of myoglobin at 30mmHg is 6
- The so-called PCO2 respiratory drive breaking point during a dive is about55 mm Hg. is True or False and explainList the abbreviations and normal ranges of the following hemodynamic values directly measured by means of the pulmonary artery catheter: central venous pressure, right atrial pressure, mean pulmonary artery pressure, pulmonary capillary wedge pressure, and cardiac output.Following several days at high altitude the body responds to the decreased oxygen content of the atmosphere by increasing the amount of 2,3-bisphosphoglycerate it produces. Based on this information and refering to the graph below, identify the correct response from the options. Y (fraction saturation) 1.0 0.8 0.6 0.4 0.2 0.0 0 20 Oxygen Binding plot 40 60 p02 (torr) 80 100 A) Curve y=high altitude and gives a greater release of oxygen to the tissues B) Curve x = high altitude and gives a greater release of oxygen to the tissues C) Curve y=high altitude and allows more oxygen to be bound at low oxygen levels D) Curve x = high altitude and allows more oxygen to be bound at low levels
