Trait Fis the Mendelian trait for freckles. The allele for freckles (F) is dominant over the allele for no freckles (f). What is the genotype of an individual who is homozygous dominant for freckles?
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- Monozygotic (MZ) twins have a concordance value of 44% for a specific trait, whereas dizygotic twins have a concordance value of less than 5% for the same trait. What could explain why the value for MZ twins is significantly less than 100%?Having freckles is determined by a dominant allele (F); no freckles is determined by a recessive allele (f). Bijal is heterozygous for the F gene. What is Bijal's GENOTYPE? O FF O Freckled skin O Skin with no frecklesHaving freckles is determined by a dominant allele (F); no freckles is determined by a recessive allele (f). Bijal is heterozygous for the F gene. What is Bijal's PHENOTYPE? FF OFf O Freckled skin O Skin with no freckles
- Assume Mendelian inheritance laws apply, and a trait is either completely dominant or recessive. Еye color: Br – dominant brown bl – recessive blue Hair color Br" -- dominant brown bl" – recessive blonde A male with brown eyes and brown hair (genotype Br"Br"Br"bl") is planning on having a child with a female who has blue eyes and brown hair (genotype bl"bl*Br"bl"). A) Fill in all blanks (8 total to complete the two-trait Punnett Square 1). 2) Possible allelic combinations in male gametes 5) 6) 7) 8).Albinism is a recessive autosomal trait for skin pigmentation. Hemophilia is a sex-linked recessivedisorder of the blood. assign alleles to the traitsA – normal skin pigmentation X H – normal blooda – albino X h - hemophilia A double heterozygous woman marries a non-hemophilic man and heterozygous for skinpigmentation. Double heterozygous means heterozygous for both traits. Aa for skin pigmentation andX H X h for blood trait. Therefore, the genotype of the woman is AaX H X h . Non-hemophilic man is X H Y and heterozygous for skin pigmentation is Aa. The genotype,therefore, of the man is AaX H Y. What is the probability that they will have:a. a child with normal skin? _____________________b. a child with normal blood? _____________________c. an albino girl? _____________________d. A hemophilic boy? _____________________Mendel's P1 Dihybrid Cross First parental (P1) generation WWGG wWgg Gametes WG Wg First filial (F1) generation Genotype Phenotype g bns es WwGg round and yellow- seeded plants Figure 1.3 Activity 4. SELF-CHECK 1. Based on the reșults of the dihybrid cross, can you tell which traits are dominant? Recessive? The P1 dihybrid cross is illustrated in Figure 1.3. Study it carefully. Capital letter W represents round pea seed which is dominant over wrinkled pea seed (w). Second parental (P2) generation (F1 self-pollinated) Ww Gg WwGg WG riWg WG of WG Gametes wG wG wg wg Second filial (F1) generation WG Wg wG to vitnsb Male wg Female WwGg 4 8 WWGg 2 wwgg 6 WwGg 10 14 WG WWGG 1 WWGG 3 Wg wG wWGg 5 WwGg 9 WwGg 13 WwGg 7 wwGg 11 wwGg 15 Wwgg wwGg 12 16 Wg Wwgg wwgg 2WwGg 4WwGg 2Wwgg Genotypic ratio 1 WWGG 2 WWG9 1WWgg 1wwGG 2wwGg 1wwgg
- Having a widows peak is dominant W to not having one (ww)Having attached earlobes is a recessive trait (ee)- Jack and Jill are heterozygous for both traits.What's the probability of them having a child with a widow's peak and attachedearlobes?Frank and Susan both have freckles but they're firstborn son Lawrence does not demonstrate the characteristics. What are the most likely genotype of Frank Susan and Lawrence?According to Mendel's second law, when the different alleles for one trait separate into gametes, their separation O is independent of how different alleles for other traits separate. O occurs so as to prevent recessive alleles of two different genes from occupying the same gamete. O occurs so that recessive alleles of different genes always occupy the same gamete. O is dependent on how different alleles for other traits separate. O All of these are what Mendel meant.
- a family, genotype of mother is AaBb,allele A is connected with allel b and allele a is connected with allele B while the father is aabb. distance between A and B is 20 cM, what is the probability that a child born to this couple will have genotype AaBb "Gregor Mendel's first step was to isolate True breeding Parents. What were the Genotypes of the True Breeding Parents? O All Homozygous Dominant O All Homozygous Recessive All Heterozygous O All Homozygous MMatch the exception to Mendel's rules to its example. if there are three genes that determine freckledness v and the more dominant alleles a person has the more freckles they exhibit if there were FR and FD and f alleles for freckles where FR codes for red freckles and FB codes for brown freckles and when FR and FB are both present the individual has as many red freckles as an FRER individual and as many brown freckles as an FBFB individual A. incomplete dominance B. polygenic trait C. sex-linkage if a homozygous dominant individual has freckles, a homozygous individual has no freckles and a heterozygote has half as many freckles as a homozygous dominant D. pleiotropy E. epistasis if the freckle gene also codes for curly eyelashes and F. environmental effects on gene expression arched eyebrows G. codominance if a person has their freckles removed by a medical procedure H. trait follows Mendel's Rules v if only males can exhibit freckles if FF and Ff have the same amount of freckles and…