Assume Mendelian inheritance laws apply, and a trait is either completely dominant or recessive. Eye color: Br* – dominant brown bl – recessive blue Hair color Br" -- dominant brown bl" – recessive blonde A male with brown eyes and brown hair (genotype Br"Br"Br"bl") is planning on having a child with a female who has blue eyes and brown hair (genotype bl*bl*Br"bl*). A) Fill in all blanks (8 total to complete the two-trait Punnett Square 1) 2)
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- Albinism is a recessive autosomal trait for skin pigmentation. Hemophilia is a sex-linked recessivedisorder of the blood. assign alleles to the traitsA – normal skin pigmentation X H – normal blooda – albino X h - hemophilia A double heterozygous woman marries a non-hemophilic man and heterozygous for skinpigmentation. Double heterozygous means heterozygous for both traits. Aa for skin pigmentation andX H X h for blood trait. Therefore, the genotype of the woman is AaX H X h . Non-hemophilic man is X H Y and heterozygous for skin pigmentation is Aa. The genotype,therefore, of the man is AaX H Y. What is the probability that they will have:a. a child with normal skin? _____________________b. a child with normal blood? _____________________c. an albino girl? _____________________d. A hemophilic boy? _____________________a. The ability to taste the chemical phenylthiocarbamideis an autosomal dominant phenotype, and the inabilityto taste it is recessive. If a taster woman with a nontasterfather marries a taster man who in a previous marriagehad a nontaster daughter, what is the probability thattheir first child will be(1) A nontaster girl(2) A taster girl(3) A taster boyb. What is the probability that their first two childrenwill be tasters of either sex?Having freckles is determined by a dominant allele (F); no freckles is determined by a recessive allele (f). Bijal is heterozygous for the F gene. What is Bijal's GENOTYPE? O FF O Freckled skin O Skin with no freckles
- ! I 7 l 8 / Using the pedigree you have constructed, complete the following Punnett square using A/a. 1) Show the cross between Braxton and his non-albino wife who had an Mother's Alleles albino father: Mother's genotype: Father's genotype: Genotype %: Phenotype %: Click to add speaker notes Father's AllelesFrank and Susan both have freckles but they're firstborn son Lawrence does not demonstrate the characteristics. What are the most likely genotype of Frank Susan and Lawrence?Identify the type(s) of trait in the pedigree below autosomal recessive autosomal dominant X-linked dominant X-linked recessive Y-inked
- young couple is planning to have children. The male is heterozygous for Huntington’s disease and homozygous dominant for Tay-Sachs. The female is homozygous recessive for Huntington’s disease and heterozygous for Tay-Sachs. The couple is curious about the possibility and probability of their offspring inheriting Tay-Sachs and/or Huntington’s. For humans, Huntington’s disease is dominant (H) over the “normal” condition (h), and the “normal” condition is dominant (T) over Tay-Sachs (t). Complete a Punnett square for this cross and record the percent probabilities for genotypes and phenotypes of the offspring.Pigeon color coat is determined by one autosomal gene with two alleles Y and y. Where Y is blue coated and y is gray. If a blue pigeon (Y,y) and gray (y,Y0 have babies What percentage % of the babies will have blue coats and be boys?Ⓒ Macmillan Ann's family has a history of cystic fibrosis, a recessive genetic disease. In the pedigree, family members who are afflicted with the disease are shown in red. Members who are unafflicted may or may not be carriers. Which of the given family members can be identified definitively as unafflicted carriers of cystic fibrosis? Ann (n 2 grandmother Incorrect Unafflicted carriers female cousin aunt's husband father Answer Bank uncle
- In addition to the allelic pair determining pattern baldness in man (B,b), consider early baldness to be due to another autosomal allele (E) on a different pair of chromosomes and also dominant in males but recessive in females. The phenotype for ee may be late or nonbaldness depending on sex and the genotype for B, b alleles. Two doubly heterozygous persons marry. What is the phenotype of the male parent? What is the phenotype of the female parent? Give the phenotypic ratio expected among male children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio. Give the phenotypic ratio expected among female children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio.a couple whose genotype for eye color is bb plans to have a child. What are the possible genotypes and phenotypes of the child in terms of eye color? Note that brown eyes (B) are dominant over blue eyes(b).(a) Enter the parent phenotypes and complete the Punnett square Inheritance of sex linked recessive tralts Example: Hemophilia Female paront phenotype Inheritance of hemophilia is sex linked. Males with the recessive (hemophilia) allele, are affected. Females can be carriers. (normal female) Xxh (carrier female) ben-N werxhxh (hemophiliac female) leizobXY (normal male) xhy (hemophiliac male) Male parent phenotype: Using the codes: XX eggs (a) Enter the parent phenotypes and complete the Punnett square for a cross between a normal male and a carrier female. sperm (b) Give the ratios for the phenotypes from this cross. Phenotype ratios: Inheritance of sex linked dominant traits Example: Sex linked form of rickets A rare form of rickets is inherited on the X chromosome. Using the codes: XX Female parent phenotype: alvo eo (normal female); XY (normal male) (affected heterozygote female) XRXR (affected female) XRY Male parent phenotype: XRX eggs (affected male) Nor a cross between an…