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- 7-15 A certain reaction is exothermic by 9 kcal/mol and has an activation energy of 14 kcal/mol. Draw an energy diagram for this reaction and label the transition state.E (kJ-mol") s/d/e/1FAlpQLSSGCE8gt218c6JoHMWME1A8Nydt8M4g1yG93D-2LPpoMij_g/formResponse Question 39: Select the reactions in Figure 39 that can be represented by the accompanying energy diagram? * Reaction A Reaction B Reaction C Figure 39 t (s) CH-C-NH-CH D + HN-H + HO-O HO-H HO HCI CH-CH-CH3 oH + 20° LIFE DigitalEnergy 7. Consider the following energy diagram: (CH3)3C-OH (CH3)3C-ÕH₂ + HI + r a) Write the overall balanced chemical equation. Reaction coordinate (CH3)3C+ + H₂O + F b) How many steps are in the reaction mechanism? c) How many intermediates are in the reaction mechanism? d) Which step requires the most energy? (say step "X", where "X" is a number) e) CIRCLE ONE ANSWER. The overall reaction is an example of: substitution addition elimination (CH3)3C-I rearrangement
- Draw a structural formula for the intermediate in the following reaction: 0 Cl₂ CH₂Cl₂ You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. • Do not include counter-ions, e.g., Na+, I, in your answer. n [ ]# ?Which of the following mechanisms is consistent with the energy diagram shown below: Energy Progress of the reaction A+B ---> C O 2A---> C (fast) B+C -> D (slow) A+B ---> C (slow) C---> D (fast A---> B (slow) B ---> C (fast) C---> D (fast)A hypothetical reaction is shown with the reaction coordinate diagram. How many steps are in the reaction mechanism? VI Reaction Progress O6
- Consider the following reaction mechanism. Step 1: 2 X + Y- W + 2 Z fast Step 2: Z- U+ V slow Step 3: V +Z-2 W + Y fast Which of the following is/are the intermediate/s in the given reaction mechanism? O Y only O V only O Z and V O V and YConsider the following hypothetical reaction coordinate diagram with stages represented by I, II, and III, and choose the true statement about the steps in the forward and reverse mechanisms. Which is a TRUE statement? a) Step II --> III is faster and less energetically favorable than step II -->I b) Step II --> III is faster and more energetically favorable than step II -->I c) Step II --> III is slower and less energetically favorable than step II -->I --> Ill is slower and more energetically favorable than | || ||| d) Step II step II -->IConsider the reaction. H CH3 X FC H Add curved arrows for the first step. H CH3 14 H H H-Br: ↑ : H :Br: # H-C- -C-CH3 H H Draw both the organic and inorganic intermediate species. Include nonbonding electrons and charges, where applicable. Include hydrogen atoms. H: Br Incorrect H HI CIH —99 H H CH3
- Consider this reaction: Br CH₂OH + Br-Br H₂CO The mechanism proceeds through a first cationic intermediate, intermediate 1. Nucleophilic attack leads to intermediate 2, which goes on to form final product. In cases that involve a negatively charged nucleophile, the attack of the nucleophile leads directly to the product. Year Hot Br + CH₂OH Br Intermediate 1 Intermediate 2 (product) In a similar fashion, draw intermediate 1 and intermediate 2 (final product) for the following reaction. Br H Br₂ + NaBr + H2O H H H NaOH . Pay attention to the reactants, they may differ from the examples. In some reactions, one part of the molecule acts as the nucleophile. Structures are provided for you to modify in the sketchers below. . • You do not have to consider stereochemistry. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate intermediate 1 and intermediate 2 using the symbol from the dropdown menu. Sn [F H On [F I Br -OH HH…Select the correct Reaction Energy Diagram for 4NO(g) + 6H,0(g) --> 4 NH,(g) + 50,(g) A C D Ep E,1 E,1 Ep R R P P P R 지 Reaction Path Reaction Path Reaction Path Reaction Path A OB Oc ufKetoprofen is a non-steroid anti-inflammatory drug. о OH What would happen to the equilibrium of ketoprofen in water when nitric acid ( HNO3) is added to the system? Rate < Rate and the equilibrium would shift to reactants (to the left) Ref Rate and the equilibrium would shift to products (to the right) Rate Rate and the equilibrium would shift to reactants (to the left) Rate Rate and the equilibrium would shift to products (to the right)