The voltage differences (∆ε) for the following two half reactions are: Cu2+ + e- → Cu+ ∆ε = +0.34 V Fe3+ + e- → Fe 2+ ∆ε = +0.77 V In one aqueous solution, the concentrations of Cu2+, Cu+, Fe3+ and Fe 2+ are all 1 mol/L. Which of them acts as an oxidant
The voltage differences (∆ε) for the following two half reactions are: Cu2+ + e- → Cu+ ∆ε = +0.34 V Fe3+ + e- → Fe 2+ ∆ε = +0.77 V In one aqueous solution, the concentrations of Cu2+, Cu+, Fe3+ and Fe 2+ are all 1 mol/L. Which of them acts as an oxidant
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter19: Principles Of Chemical Reactivity: Electron Transfer Reactions
Section: Chapter Questions
Problem 88GQ
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The voltage differences (∆ε) for the following two half reactions are:
Cu2+ + e- → Cu+ ∆ε = +0.34 V
Fe3+ + e- → Fe 2+ ∆ε = +0.77 V
In one aqueous solution, the concentrations of Cu2+, Cu+, Fe3+ and Fe 2+ are all 1 mol/L. Which of them acts as an oxidant?
a.
Fe 2+
b.
Cu+
c.
Fe3+
d.
Cu2+
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