A foot powder samplecontaining Zn was dissolvedon 200.00 mL water andwas titrated to the end pointcolor with 22.57 mL of 0.01639M EDTA at pH=4.(a4= 3.61x10-9, K ZnY²- = 3.2 ×1016). The pZn in the sample is:%3DPlease fill in the spacewith a numerical valuewith two digits ornumerical values withoutunitsAnswer:

The question is based on the concept of chemical equilibrium. we have to calculate pZn value for the…

A foot powder sample containing Zn was dissolved on 200.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (a4= 3.61×10-9, K ZnY²- = 3.2 x 1016). The pZn in the sample is: Please fill in the space with a numerical value with two digits or numerical values without units Answer:

A foot powder sample containing Zn was dissolved on 200.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (a4= 3.61×10-9, K ZnY²- = 3.2 x 1016). The pZn in the sample is: Please fill in the space with a numerical value with two digits or numerical values without units Answer:

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter16: Applications Of Neutralization Titrations

Section: Chapter Questions

Problem 16.40QAP

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