Introduction to Genetic Analysis
11th Edition
ISBN: 9781464109485
Author: Anthony J.F. Griffiths, Susan R. Wessler, Sean B. Carroll, John Doebley
Publisher: W. H. Freeman
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 3, Problem 44P
Summary Introduction
To determine: The experimental approach used to distinguish between the phenomenon caused by chloroplast mutation or dominant nuclear mutation that inhibits chloroplast production.
Introduction: The mutation is the change in the
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Three haploid fungal mutants that require compound W for growth were isolated.
Each mutant contains a recessive allele in a single gene. Three compounds (A, B and
C) in the biosynthetic pathway to W are known, but their order in the pathway is
unknown. Each compound is tested for its ability to support the growth of each of
the three mutants. Phenotypes of all of the three mutants are shown in the following
table (“+" indicates growth, "-" indicates no growth).
A
C
W
Mutant 1
Mutant 2
Mutant 3
What would be the phenotype of a haploid mutant that contains both mutant alleles
in mutant 2 and 3? Phenotype refers to growth or absence of growth on compounds
A, B, C and WN.
O Like mutant 1
O Like mutant 2
Like mutant 3
O Like wild type
You have identified five genes in S. cerevisiae that are induced when the yeast are grown in a high-salt (NaCl) medium. To study the potential roles of these genes in acclimation to the growth in high-salt conditions, you wish to examine the phenotypes of loss- and gain-of-function alleles of each. How will you do this?
Schizosaccharomyces pombe, also known as "fission yeast," is a powerful model organism in molecular
and cell biology. While performing a genetic screen, you discover an auxotrophic S. pombe strain that
is unable to synthesize one or more vitamins. The following table represents the key experiments you
performed during your genetic screen. Fill in the table with the outcome of each experiment for your
mutant strain (using + for growth and - for no growth).
Medium
Rich media
Minimal media
Minimal media +
all vitamins
Minimal media +
all amino acids
Growth
Wild-type
+
+
+
+
Mutant
+
+
+
>
>
>
Chapter 3 Solutions
Introduction to Genetic Analysis
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 10PCh. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13P
Ch. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 31.1PCh. 3 - Prob. 31.2PCh. 3 - Prob. 31.3PCh. 3 - Prob. 31.4PCh. 3 - Prob. 31.5PCh. 3 - Prob. 31.6PCh. 3 - Prob. 31.7PCh. 3 - Prob. 31.8PCh. 3 - Prob. 31.9PCh. 3 - Prob. 31.10PCh. 3 - Prob. 31.11PCh. 3 - Prob. 31.12PCh. 3 - Prob. 31.13PCh. 3 - Prob. 31.14PCh. 3 - Prob. 31.15PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 57P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- You are a developmental geneticist studying flowering time variation in Arabidopsis. You perform a mutagenesis screen to identify mutants in the photoperiod pathway. Given what you know about photoperiodism in Arabidopsis, what phenotype are you looking for and under what photoperiodic conditions would you perform the experiment? delayed flowering in long days delayed flowering in short days same flowering in short days early flowering in short days same flowering in long days early flowering in long daysarrow_forwardAssume that diploid plant A has a cytoplasm genetically different from that of plant B. To study nuclear–cytoplasmic relations, you wish to obtain a plant with the cytoplasm of plant A and the nuclear genome predominantly of plant B. How would you go about producing such a plant?arrow_forwardIn roses, the synthesis of red pigment is produced by two steps in a pathway. gene O magenta intermediate - gene P colorless intermediate- red pigment What would the phenotype be of a plant homozygous for a null mutation of gene P? What would the phenotype be of a plant homozygous for a null mutation of gene Q? What would the phenotype be of a plant homozygous for null mutations of genes P and Q? magenta red Match a genotype to each strain. colorless Strain P locus Q locus homozygous null mutation of gene P homozygous null mutation of gene Q homozygous null mutations of genes P and Q Answer Bank plp PIP What F2 ratio is expected from crossing a plant that is homozygous for a null mutation of gene P with a plant that is homozygous for a null mutation of gene Q? Assume independent assortment. 9 colorless : 4 magenta : 3 red 9 red : 4 colorless : 3 magenta O 9 red : 4 magenta : 3 colorlessarrow_forward
- In a species of tree, seed color is determined by four independently assorting genes: A, B, C, and D. The recessive alleles of each of these genes (a, b, C, and d) produce abnormal enzymes that cannot catalyze a reaction in the biosynthetic pathway for seed pigment. This pathway is diagrammed as follows: A White precursor Yellow ----Orange----- Red --- Blue When both red and blue pigments are present, the seeds are purple. Trees with the genotypes Aa Bb Cc Dd and Aa Bb Cc dd were crossed. (a) What color are the seeds in these two parental genotypes? (b) What proportion of the offspring from the cross will have white seeds? (c) Determine the relative proportions of red, white, and blue offspring from the cross.arrow_forwardA mutation that breaks which of the following genes would be most likely to produce theanthocyanless phenotype of the green-stem Wisconsin Fast Plants (meaning no purple stems):PAL, CHS, C3H, FLS, or DFR? Explain your reasoning.arrow_forwardDuring the course of a research project you generate a gene knockout line in Arabidopsis thaliana to study the function of a gene you believe plays a crucial role in cellular metabolism. You note that the initial transformants are a bit smaller than normal. In subsequent crosses you are unable to isolate homozygotes for the knockout allele. Heterozygotes in subsequent generation are still a bit smaller than the homozygous wild type plants. Explain what is happening.arrow_forward
- Assume that diploid plant A has a cytoplasm genetically different from that of plant B. To study nuclear–cytoplasmic relations, you wish to obtain a plant with thecytoplasm of plant A and the nuclear genome predominantly of plant B. How would you go about producingsuch a plant?arrow_forwardCan you answer part a-c if its true or false a) the AP3 and PI show auto- and cross-regulatory interactions, as well as they form obligate heterodimers to carry out the B class gene function. Therefore, if there is no PI expression, AP3 expression alone is not sufficient for establishing the petal and stamen identities. b) Angiosperm is a group of plants whose seeds are borne within a mature ovary (fruit). c) The organ in different organisms under every variety of forms and functions due to evolutionary development from the same or a corresponding part in a common ancestor is homologous.arrow_forwardIn roses, the synthesis of red pigment is by two steps ina pathway, as follows:colorless intermediate gene Pmagenta intermediate red pigment gene Qa. What would the phenotype be of a plant homozygousfor a null mutation of gene P?b. What would the phenotype be of a plant homozygousfor a null mutation of gene Q?c. What would the phenotype be of a plant homozygousfor null mutations of genes P and Q?d. Write the genotypes of the three strains in parts a, b,and c.e. What F2 ratio is expected from crossing plants fromparts a and b? (Assume independent assortment.)arrow_forward
- In sweet peas the synthesis of purple anthocyanin pigment in the petals is controlled by two genes, B and D. The pathway is: Enzyme B →Blue Intermediate Enzyme D → White Intermediate Anthocyanin (purple) What color petals would you expect in a pure-breeding (homozygous) plant unable to catalyze the first reaction (white to blue)? [Select] What color petals would you expect in a pure-breeding plant unable to catalyze the second reaction (blue to purple)? [Select] If the plants in parts a and b are crossed, what color petals will the offspring have? [Select]arrow_forwardPlant breeders have long appreciated the phenomenon called hybrid vigor or heterosis, in which hybrids formed between two inbred strains have increased vigor and crop yield relative to the two parental strains. Starting in the 1930s, seed companies exploited the cytoplasmic male sterility (CMS) phenomenon in corn that was described in Problem 17 so that they could cheaply produce hybrid corn seed to sell to farmers. This type of CMS is caused by mutant mitochondrial genomes that prevent pollen formation. a. How would CMS aid seed companies in producing hybrid corn seed? Dominant Rf alleles of a nuclear gene called Restorer suppress the CMS phenotype, so that Rf- containing plants with mutant mitochondrial genomes are male fertile.arrow_forwardFigure 4 shows the hybridization process between plant P and Q. b) What is process A?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Anatomy & Physiology (11th Edition)BiologyISBN:9780134580999Author:Elaine N. Marieb, Katja N. HoehnPublisher:PEARSONBiology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStaxAnatomy & PhysiologyBiologyISBN:9781259398629Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa StouterPublisher:Mcgraw Hill Education,
- Molecular Biology of the Cell (Sixth Edition)BiologyISBN:9780815344322Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter WalterPublisher:W. W. Norton & CompanyLaboratory Manual For Human Anatomy & PhysiologyBiologyISBN:9781260159363Author:Martin, Terry R., Prentice-craver, CynthiaPublisher:McGraw-Hill Publishing Co.Inquiry Into Life (16th Edition)BiologyISBN:9781260231700Author:Sylvia S. Mader, Michael WindelspechtPublisher:McGraw Hill Education
Human Anatomy & Physiology (11th Edition)
Biology
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:PEARSON
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Anatomy & Physiology
Biology
ISBN:9781259398629
Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa Stouter
Publisher:Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)
Biology
ISBN:9780815344322
Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter
Publisher:W. W. Norton & Company
Laboratory Manual For Human Anatomy & Physiology
Biology
ISBN:9781260159363
Author:Martin, Terry R., Prentice-craver, Cynthia
Publisher:McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)
Biology
ISBN:9781260231700
Author:Sylvia S. Mader, Michael Windelspecht
Publisher:McGraw Hill Education
Mitochondrial mutations; Author: Useful Genetics;https://www.youtube.com/watch?v=GvgXe-3RJeU;License: CC-BY