Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
Question
Book Icon
Chapter 2, Problem 2.41QE
Interpretation Introduction

Interpretation:

Partial columns has to be filled in the table given in problem statement.

Concept Introduction:

Each and every element present in the Periodic table has a unique name.  Some of the elements are named considering their atomic number.  In order to represent the elements in a short form, atomic symbols are used.  Generally the first two letters of the element name will be used as symbol where the first letter is in upper case.

Chemical names are represented as atomic symbols.  In the symbols, the mass number and atomic number are shown.  The complete symbol for an element can be represented as shown below.

Chemistry: Principles and Practice, Chapter 2, Problem 2.41QE

Atomic number is the total number of protons present in the atom of an element.  Mass number is the total number of protons and neutrons present in nucleus of an atom.

Expert Solution & Answer
Check Mark

Explanation of Solution

For entry 1:

Atomic number is given as 11, number of electrons is given as 10, and number of neutrons is given as 12.  Total number of protons present in the nucleus is the atomic number.  Therefore, the number of protons present is 11.

Mass number is the sum of number of protons and number of neutrons.  This can be calculated as shown below.

    A=Z+n=11+12=23

Charge can be calculated by finding the difference between the number of protons and electrons as shown below.

    Charge=NumberofprotonsNumberofelectrons=1110=+1

Atomic number is given as 11.  The element with atomic number 11 is found to be sodium which has a symbol as Na.

For entry 2:

Symbol is given as 40Ca2+.  As the given ion is a calcium ion, the atomic number is found to be 20.  This in turn means that the total number of protons is 20.

Mass number is the sum of number of protons and number of neutrons.  From the mass number given as 40 in the symbol, the number of neutrons can be calculated as shown below.

    A=Z+nn=AZ=4020=20

Charge is given as 2+ in the symbol.  This means the number of electrons is 2 less than that of the protons.

    Charge=NumberofprotonsNumberofelectrons2=20NumberofelectronsNumberofelectrons=202=18

For entry 3:

Number of protons is given as 35.  This means that the atomic number of the species is 35.  The element with atomic number 35 is found to be bromine with the symbol of Br.

Mass number is the sum of number of protons and number of neutrons.  From the mass number given as 81, the number of neutrons can be calculated as shown below.

    A=Z+nn=AZ=8135=46

Charge is given as 1.  This means the number of electrons is 1 more than that of the protons.

    Charge=NumberofprotonsNumberofelectrons1=35NumberofelectronsNumberofelectrons=35+1=36

For entry 4:

Number of protons is given as 52.  This means that the atomic number of the species is 52.  The element with atomic number 52 is found to be tellurium with the symbol of Te.

Mass number is the sum of number of protons and number of neutrons.  This can be calculated as shown below.

    A=Z+n=52+76=128

Charge is given as 2.  This means the number of electrons is 2 more than that of the protons.

    Charge=NumberofprotonsNumberofelectrons2=52NumberofelectronsNumberofelectrons=52+2=54

Complete table can be given as shown below.

Symbol23Na+40Ca2+81Br128Te2
Atomic number11203552
Mass number234081128
Charge+1+212
Number of protons11203552
Number of electrons10183654
Number of neutrons12204676

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
A compound is 32.88% C, 4.14% H, 19.18% N and 43.80% O by mass, and it has a molar mass of 219 g/mol. What is the molecular formula of this compound? When entering the formula place the elements in the following order: C, H, N, O. For subscripts, write the number after the element it corresponds to. For example, H2O should be written as H2O.

Chapter 2 Solutions

Chemistry: Principles and Practice

Ch. 2 - A mass spectrometer determines isotopic masses to...Ch. 2 - Prob. 2.12QECh. 2 - Prob. 2.13QECh. 2 - Prob. 2.14QECh. 2 - Prob. 2.15QECh. 2 - Prob. 2.16QECh. 2 - Sulfur dioxide, SO2, is a molecular compound that...Ch. 2 - Prob. 2.18QECh. 2 - Prob. 2.19QECh. 2 - Prob. 2.20QECh. 2 - Prob. 2.21QECh. 2 - Prob. 2.22QECh. 2 - Prob. 2.23QECh. 2 - Prob. 2.24QECh. 2 - Prob. 2.25QECh. 2 - Prob. 2.26QECh. 2 - Prob. 2.27QECh. 2 - Prob. 2.28QECh. 2 - Prob. 2.29QECh. 2 - Give the complete symbol (XZA), including atomic...Ch. 2 - Prob. 2.31QECh. 2 - Prob. 2.32QECh. 2 - Prob. 2.33QECh. 2 - Prob. 2.34QECh. 2 - Prob. 2.35QECh. 2 - Prob. 2.36QECh. 2 - Prob. 2.37QECh. 2 - Prob. 2.38QECh. 2 - Prob. 2.39QECh. 2 - Prob. 2.40QECh. 2 - Prob. 2.41QECh. 2 - Prob. 2.42QECh. 2 - Prob. 2.43QECh. 2 - Prob. 2.44QECh. 2 - Prob. 2.45QECh. 2 - Prob. 2.46QECh. 2 - Prob. 2.47QECh. 2 - Prob. 2.48QECh. 2 - Prob. 2.49QECh. 2 - Prob. 2.50QECh. 2 - Prob. 2.51QECh. 2 - Prob. 2.52QECh. 2 - Prob. 2.53QECh. 2 - Prob. 2.54QECh. 2 - Prob. 2.55QECh. 2 - Prob. 2.56QECh. 2 - Prob. 2.57QECh. 2 - Prob. 2.58QECh. 2 - Prob. 2.59QECh. 2 - Prob. 2.60QECh. 2 - Prob. 2.61QECh. 2 - Prob. 2.62QECh. 2 - Prob. 2.63QECh. 2 - Prob. 2.64QECh. 2 - Prob. 2.65QECh. 2 - Prob. 2.66QECh. 2 - Prob. 2.67QECh. 2 - Prob. 2.68QECh. 2 - Prob. 2.69QECh. 2 - Prob. 2.70QECh. 2 - Prob. 2.71QECh. 2 - Prob. 2.72QECh. 2 - Prob. 2.73QECh. 2 - Prob. 2.74QECh. 2 - Prob. 2.75QECh. 2 - Prob. 2.76QECh. 2 - Prob. 2.77QECh. 2 - Prob. 2.78QECh. 2 - Prob. 2.79QECh. 2 - Prob. 2.80QECh. 2 - Prob. 2.81QECh. 2 - Prob. 2.82QECh. 2 - Prob. 2.83QECh. 2 - Prob. 2.84QECh. 2 - Prob. 2.85QECh. 2 - Prob. 2.86QECh. 2 - Prob. 2.87QECh. 2 - Prob. 2.88QECh. 2 - Prob. 2.89QECh. 2 - Prob. 2.90QECh. 2 - Prob. 2.91QECh. 2 - Prob. 2.92QECh. 2 - Prob. 2.93QECh. 2 - Prob. 2.94QECh. 2 - Prob. 2.95QECh. 2 - Prob. 2.96QECh. 2 - Write the formula of (a) manganese(III) sulfide....Ch. 2 - Prob. 2.98QECh. 2 - Prob. 2.99QECh. 2 - Prob. 2.100QECh. 2 - Prob. 2.101QECh. 2 - Prob. 2.102QECh. 2 - Prob. 2.103QECh. 2 - Prob. 2.104QECh. 2 - Prob. 2.105QECh. 2 - Prob. 2.106QECh. 2 - Prob. 2.107QECh. 2 - Prob. 2.108QECh. 2 - Prob. 2.109QECh. 2 - Prob. 2.110QECh. 2 - Prob. 2.111QECh. 2 - Prob. 2.112QECh. 2 - Prob. 2.113QECh. 2 - Prob. 2.114QECh. 2 - Prob. 2.115QECh. 2 - Prob. 2.116QECh. 2 - Prob. 2.117QECh. 2 - Prob. 2.118QECh. 2 - Prob. 2.119QECh. 2 - Prob. 2.120QECh. 2 - Prob. 2.121QECh. 2 - Prob. 2.122QECh. 2 - Prob. 2.123QECh. 2 - Prob. 2.124QECh. 2 - Prob. 2.125QECh. 2 - Prob. 2.126QECh. 2 - Prob. 2.127QECh. 2 - Prob. 2.128QECh. 2 - Prob. 2.129QECh. 2 - Prob. 2.130QECh. 2 - Prob. 2.131QECh. 2 - Prob. 2.132QECh. 2 - Prob. 2.133QECh. 2 - Prob. 2.134QECh. 2 - Prob. 2.135QECh. 2 - Prob. 2.136QE
Knowledge Booster
Background pattern image
Similar questions
Recommended textbooks for you
Text book image
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Text book image
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning
Text book image
General, Organic, and Biological Chemistry
Chemistry
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:Cengage Learning
Text book image
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Text book image
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning