Your lazy labmate needs your help! They set up a 10-ml culture of the slow-growing Myxococcus xanthus yesterday, but then they decided to stay up late playing videogames and won't be in until next Monday to recover. Whoops! They call you in lab that Friday and ask you to take an OD reading for them. You do this favor for them, and helpfully do the conversion into cells/mL, finding that their culture is currently sitting at about 3.0 x108 cells per mL. Your labmate is horrified: they won't be back in time before the cells hit stationary phase, since M. xanthus doubles every 5 hours. They beg you to make a new culture using these cells and set it up to reach the same cell density Monday morning. That's 59 hours away. If the cells usually lag for three hours upon dilution into fresh medium, what cell density should you dilute the culture to? About 1.3 x 107 cells/ml
Your lazy labmate needs your help! They set up a 10-ml culture of the slow-growing Myxococcus xanthus yesterday, but then they decided to stay up late playing videogames and won't be in until next Monday to recover. Whoops! They call you in lab that Friday and ask you to take an OD reading for them. You do this favor for them, and helpfully do the conversion into cells/mL, finding that their culture is currently sitting at about 3.0 x108 cells per mL. Your labmate is horrified: they won't be back in time before the cells hit stationary phase, since M. xanthus doubles every 5 hours. They beg you to make a new culture using these cells and set it up to reach the same cell density Monday morning. That's 59 hours away. If the cells usually lag for three hours upon dilution into fresh medium, what cell density should you dilute the culture to? About 1.3 x 107 cells/ml
Chapter10: Reconstitution Of Powdered Drugs
Section: Chapter Questions
Problem 4.2P
Related questions
Question
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Recommended textbooks for you