Karyotype 1Karyotype 23910111314161719202122Karyotype 3Karyotype 4Karyotype 1|- v Karyotype 2- vKaryotype 3A. normal femaleB. normal maleC. female with Down Syndrome- Karyotype 4D. male with the wrong number of sex chromosomes QUESTION 11Match the karyotype with its correct interpretation.Karyotype 1Karyotype 23101112

Karyotype is pictorial or diagrammatical representation of collection of chromosome within an…

Answered: QUESTION Match the karyotype with its…

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Biology

QUESTION Match the karyotype with its correct interpretation. N7H 第 Karyotype 1 Karyotype 2 10 11

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter13: Modern Understandings Of Inheritance

Section: Chapter Questions

Problem 11RQ: The genotype XXY corresponds to Klinefelter syndrome Turner syndrome Triplo-X Jacob syndrome

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A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?
I. Give the chromosome number and chromosome configuration if the following mutations occurred in rice, a diploid organism wherein the number of chromosomes per set is 12. 1. Trisomy-11 2. Double Monosomy 3. Triploidy 4. Nullisomy-12 5. Tetraploid II. Give the chromosome number for the following: 6. 311+ 21 7. 4||+3||| 8. 2n=4 treated with colchicine to produce an autotetraploid 9. Monoploid maize (2n=20) 10, 51|^+ 51|B
2 3 4 5 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 ху Which chromosome set has an extra What diagnosis would you give this patient?. Finish the notation for this patient's karyotype: What causes a dark band on the chromosome? What is a centromere?
What types of chromosome mutations are required to change this chromosome into the following chromosomes? (In some cases, more than one chromosome mutation may be required.) Q. A B • C F E D G
40 Below is a pedigree of a family, some of whom have the autosomal dominant condition Huntington's disease. Affected individuals are indicated by a dark square or circle. The male in generation I (indicated by the arrow) is heterozygous for the Huntington's disease mutation. The following two questions relate to this pedigree. Generation II II If H represents the disease allele, and h the wild type allele, what is the genotype of the individual indicated by the *? Select one alternative: O hh O Hh O hH O HH
1. The figure below represents a karyotype performed on a somatic cell of an unknown organism. Answer the following questions using the figure. a. Circle (and label) 3 different sets of homologous chromosomes? b. This individual is heterozygote for gene A (Aa), Homozygote recessive for gene B (bb) and gene homozygote dominant for gene c (CC). Also, gene B and gene C are linked. Using the homologous chromosomes you circled in part a), provide a representation of the location of the A, B and C, genes and alleles on the homologous chromosomes and sister chromatids in such a way that is consistent with the scenario described above in part b). Choose the chromosomes of your liking to show an appropriate representation. TMIID IL MI
Considering the following chromosome which is represented as a series of genes on each arm separated by the centromere. Describe the type of mutation required to produce each of the mutant chromosomes below. ABCDEFG*HIJKLMN
A young couple is planning to have children. Knowing that there have been a substantial number of stillbirths, miscarriages, and fertility problems on the husband’s side of the family, they see a genetic counselor. A chromosome analysis reveals that, whereas the woman has a normal karyotype, the man possesses only 45 chromosomes and is a carrier of a Robertsonian translocation between chromosomes 22 and 13. Q. If trisomies and monosomies entailing chromosomes 13 and 22 are lethal, approximately what proportion of the surviving offspring are expected to be carriers of the translocation?
(X^X^) and one male (X"). 12. The following are the gene order on the chromosomes of an individual who is heterozygous for this translocation. translocations (a.unbalanced breciprocal C. Robertsonian MN OP QR N067 89 34 5P QR 3 4 5 6 7 8 9 a. 0 LMNOP QR LMN067 89 345P QR 3456789 hmm Draw the synapsis (Prophase/Metaphase I) configuration dark spots b. What type of translocation is depicted by these chromosomes and what are the consequences of this chromosome rearrangement to the individual? this type of translocation is unbalanced and the major consequence here is that the chromosome number is not reciprocated leading to all sorts of problems with non-disjunction.
For questions 22 through 30, please refer to the pictures below: Normal B B B C D D D D' E E 22 23 24 B D G. Y D M H. B C E 25 26 27 28 B D Break through centromere B B A D 29 30 Identify the type of chromosomal aberration in each number above. Please refer to the choices below. Reciprocal translocation Robertsonian translocation Isochromosome Terminal deletion Interstitial deletion Duplication Pericentric inversion Ring chromosome Marker chromosome Paracentric inversion
Why is 26 incorrect