• Consider the selfed offspring of a AaBbCcDd individual: •What is the probability that offspring will have the following genotypes: • AABBCCDD • AaBbCCDd - A_B_C_D_ BbCCDd 1/4 x 1/4 x 1/4 x 1/4= 1/256 1/2 x 1/2 x 1/4 x 1/2= 1/32 3/4 x 3/4 x 3/4 x 3/4= 81/256 1 x 1/2 x 1/4 x 1/2= 1/16 - Same genotype as the parent? - Same phenotype as the parent?

• Consider the selfed offspring of a AaBbCcDd individual: •What is the probability that offspring will have the following genotypes: • AABBCCDD • AaBbCCDd - A_B_C_D_ BbCCDd 1/4 x 1/4 x 1/4 x 1/4= 1/256 1/2 x 1/2 x 1/4 x 1/2= 1/32 3/4 x 3/4 x 3/4 x 3/4= 81/256 1 x 1/2 x 1/4 x 1/2= 1/16 - Same genotype as the parent? - Same phenotype as the parent?

Name: ●●●●●●Consider the selfed offspring of a AaBbCcDd individual:What is
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Description: ●●●●●●Consider the selfed offspring of a AaBbCcDd individual:What is the probability that offspring will have thefollowing genotypes:AABBCCDDAaBbCCDdA_B_C_D_BbCCDd1/4 x 1/4 x 1/4 x 1/4= 1/2561/2 x 1/2 x 1/4 x 1/2= 1/323/4 x 3/4 x 3/4 x 3/4= 81/2561

Curren'S Math For Meds: Dosages & Sol

11th Edition

ISBN:9781305143531

Author:CURREN

Publisher:CURREN

Chapter9: Parenteral Medication Labels And Dosage Calculation

Section: Chapter Questions

Problem 2.2P

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