Build a DFA that accepts the set of string over {a,b} in which the number of a’s is divisible by three.
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Q: Build a DFA that accepts the set of string over {a,b} that do not begin with the substring aaa
A: According to the Question below the Solution:
Build a DFA that accepts the set of string over {a,b} in which the
number of a’s is divisible by three.
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- Build a DFA that accepts the set of string over {a,b} that do not contain the substring aaa.1. Let L = {w {a, b}* : w contains bba as a substring that starts in an odd numbered position in the string (where numbering starts at 1)}. For example, bbbbaaaab L, while bbbaaaab L. Show an NDFSM that accepts LLet L = { w ∈ { a, b, c }*| w contains bc once in the string}. Construct an FSA that recognizes L
- DescriptionA researcher is analyzing DNA. A DNA can be represented as a string composed of the characters A, G, C, or T.One day, researchers found a strange DNA, which is Smooth Repeated DNA. The DNA is represented by a string that has infinite length. The string has a repeating pattern, i.e. the DNA string 0 is repeated an infinite number of times. For example, if0 = "????", then = "???????????? . . . ".According to researchers, a DNA is said to be special if it contains substrings . Determine whetheris a substring of . Squad FormatA line containing the two strings 0 and . Output FormatA line that determines whether it is a substring of . Issue “YES” ifis a substring of . Output “NO” otherwise. Example Input and Output Input Example Example Output AGCT GC YES AGCT TA YES AGCT GT No AGCT TAGCTAGCT YES AGGACCTA CTAA YES Explanation ExampleIn the first to fourth test case examples, is worth "???????????? . . . ". The part in bold is one of the…Convert NFA L2 = {set of all strings over (a, b) that starts with ‘a’ and ends with ‘b’ to its equivalent DFA.write the following as a function that takes in a string and returns a string. for (int i=0; i != user_string. size(); i++){ if (islower(user_string[i])){ user_string[i]=toupper(user_string[i]); } elseif(isupper(user_string[i])){ user_string[i]=tolower(user_string[i]); } } cout<<user_string; return0; }
- Draw NFA that accepts the set of strings over {a, b} such that there should be at least one substring which starts and ends with a b and the number of symbols between these two b’s is divisible by 4. Example: abababaaaababab, babbaa (since 0 is divisible by 4), ababababbaa.lWrite in C Language Spilitology Yosef is a peculiar fellow. He introduced the idea to study a string by splitting it into two, and he called it Splitology. Why split a string? We do not know. Didn’t we say that Yosef is a weird one? Yosef is interested in one particular type of string, a palindrome. A palindrome is a string that is the same for both forwards and backwards. Example of palindrome strings are “ada”, “taat”, and “radar”. On the other hand, string such as “taman” is not a palindrome; notice that “taman” becomes “namat” if read backwardsand it’s not the same as “taman”. As the idea of Splitology is still new, Yosef is investigating whether a string can be split into two non-empty strings such that each string is a palindrome. For example, the string “malamini” can be split into “malam” and “ini” while both of them are palindrome. Another example is “ababab”. It can be split into “aba” and “bab”, and both of them are palindrome. Note that “ababab” can also be split into…Construct dfas that accept the followings: a. Set of all strings on {0,1} that do not contain two consecutive 0s b. Set of all stings on {0,1} that end with two 0s
- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string. This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is, str = new StringBuilder(str).reverse().tostring(); A bit convoluted, but does what is needed without fuss or muss. Maybe one day the Java strings will come with the reverse method built in, just like the string data types of all sensible…C Programming Code only Space X is planning to start Star link. Programmers at SpaceX are having trouble to implement wildcard pattern matching supporting only the wildcard '?'. The wildcard character '?' can be substituted by any single lower case English letter for matching. He has two strings X and Y of equal length, made up of lower case letters and the character '?'. He wants to know whether the strings X and Y can be matched or not. The first line of input contain an integer T denoting the number of test cases. Each test case consists of two lines, the first line contains the string X and the second contains the string Y. For each test case, output a single line with the word Elon if the strings can be matched, otherwise output Musk. Input: Output: Elon 2 s?or? Musk sco?? stor? sco??