L1={All strings that having prefix containing first 3 letters of your name separated by + or -, such that if there exits a vowel then there is + in between the letters and if there exists two consonants then there is - sign between them e.g. for the name ASM the string accepted will be A+S-M ] L2 =[ ending with last three letters of your name ] Note : My name is sufyan Make a suitable machine for the language L1∩L2'
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L1={All strings that having prefix containing first 3 letters of your name separated by + or -, such that if there exits a vowel then there is + in between the letters and if there exists two consonants then there is - sign between them e.g. for the name ASM the string accepted will be A+S-M ]
L2 =[ ending with last three letters of your name ]
Note : My name is sufyan
Make a suitable machine for the language L1∩L2'
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- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string. This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is, str = new StringBuilder(str).reverse().tostring(); A bit convoluted, but does what is needed without fuss or muss. Maybe one day the Java strings will come with the reverse method built in, just like the string data types of all sensible…Implement the following function which accepts a string as parameter and reverses it, without using any function from the string library. void strReverse(char *str)
- Let L = {ab, aa, baa}. Which of the following strings are in L* and L4: abaabaaabaa , aaaabaaaa , baaaaabaaaab , baaaaabaapublic static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current stringQ: Write regular expression for the following languages. All strings in which b is never tripled. It means that no words contain the substring bb. All the strings accepting b as second letter. Regular expression that accept only prime numbers. All the strings that start with aa, end with bb, and have alternating substrings ba in between. Language of all those strings with length greater than 3
- DescriptionA researcher is analyzing DNA. A DNA can be represented as a string composed of the characters A, G, C, or T.One day, researchers found a strange DNA, which is Smooth Repeated DNA. The DNA is represented by a string that has infinite length. The string has a repeating pattern, i.e. the DNA string 0 is repeated an infinite number of times. For example, if0 = "????", then = "???????????? . . . ".According to researchers, a DNA is said to be special if it contains substrings . Determine whetheris a substring of . Squad FormatA line containing the two strings 0 and . Output FormatA line that determines whether it is a substring of . Issue “YES” ifis a substring of . Output “NO” otherwise. Example Input and Output Input Example Example Output AGCT GC YES AGCT TA YES AGCT GT No AGCT TAGCTAGCT YES AGGACCTA CTAA YES Explanation ExampleIn the first to fourth test case examples, is worth "???????????? . . . ". The part in bold is one of the…Write in C Language Spilitology Yosef is a peculiar fellow. He introduced the idea to study a string by splitting it into two, and he called it Splitology. Why split a string? We do not know. Didn’t we say that Yosef is a weird one? Yosef is interested in one particular type of string, a palindrome. A palindrome is a string that is the same for both forwards and backwards. Example of palindrome strings are “ada”, “taat”, and “radar”. On the other hand, string such as “taman” is not a palindrome; notice that “taman” becomes “namat” if read backwardsand it’s not the same as “taman”. As the idea of Splitology is still new, Yosef is investigating whether a string can be split into two non-empty strings such that each string is a palindrome. For example, the string “malamini” can be split into “malam” and “ini” while both of them are palindrome. Another example is “ababab”. It can be split into “aba” and “bab”, and both of them are palindrome. Note that “ababab” can also be split into…please code in python Write a function that receives a string and a number (n) as parameters and returns a new string that contains only every nth letter from the given string. print(everyNth('banana', 2)) # should return aaaprint(everyNth('carrot', 3)) # should return rtprint(everyNth('pear', 1)) # should return pear
- Palindromes - “A palindrome” is a string that reads the same from both directions. For example: the word "mom" is a palindrome. Also, the string "Murder for a jar of red rum" is a palindrome. - So, you need to implement a Boolean function that takes as input a string and its return is true (1) in case the string is a palindrome and false (0) otherwise. - There are many ways to detect if a phrase is a palindrome. The method that you will implement in this task is by using two stacks. This works as follows. Push the left half of the characters to one stack (from left to right) and push the second half of the characters (from right to left) to another stack. Pop from both stacks and return false if at any time the two popped characters are different. Otherwise, you return true after comparing all the elements. Phrases of odd length have to be treated by skipping the middle element like the word "mom", your halves are "m" and "m". - Hint: (without using STL)Here is a function that is supposed to return True if word (any string) ends with "s" and False otherwise: def ends_with_s(word):if len(word) < 1:return False return word[-1] == "s" Here is the test function I am using to test ends_with_s: def test_ends_with_s(): assert(ends_with_s("cats")) # option 1 assert(ends_with_s("") is False) # option 2 assert(ends_with_s("apple") is False) # option 3 assert(ends_with_s("S")) # option 4 Rewrite ends_with_s so that the test passesCorrect answer will be upvoted else Multiple Downvoted. Computer science. You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'. A string is called a regular bracket sequence (RBS) if it's of one of the following type empty strin '(' + RBS + ')' '[' + RBS + ']' RBS + RBS where plus is a concatenation of two strings In one move you can choose a non-empty subsequence of the string s (not necessarily consecutive) that is an RBS, remove it from the string and concatenate the remaining parts without changing the order What is the maximum number of moves you can perfor Input The first line contains a single integer t (1≤t≤1000) — the number of testcases Each of the next t lines contains a non-empty string, consisting only of characters '(', ')', '[' and ']'. The total length of the strings over all testcases doesn't exceed 2⋅10 Output For each testcase print a single integer — the maximum number of moves you can perform on a given string…