All strings having even a’s and odd b’s All strings that start and end with different letters anbn anbman
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Write Context Free Grammers for:
- All strings having even a’s and odd b’s
- All strings that start and end with different letters
- anbn
- anbman
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- Write in C Language Spilitology Yosef is a peculiar fellow. He introduced the idea to study a string by splitting it into two, and he called it Splitology. Why split a string? We do not know. Didn’t we say that Yosef is a weird one? Yosef is interested in one particular type of string, a palindrome. A palindrome is a string that is the same for both forwards and backwards. Example of palindrome strings are “ada”, “taat”, and “radar”. On the other hand, string such as “taman” is not a palindrome; notice that “taman” becomes “namat” if read backwardsand it’s not the same as “taman”. As the idea of Splitology is still new, Yosef is investigating whether a string can be split into two non-empty strings such that each string is a palindrome. For example, the string “malamini” can be split into “malam” and “ini” while both of them are palindrome. Another example is “ababab”. It can be split into “aba” and “bab”, and both of them are palindrome. Note that “ababab” can also be split into…The following two languages over {0,1} L1: All strings that begin in '00' L2: All strings that have the substring '1' embedded.Implement the following function which accepts a string as parameter and reverses it, without using any function from the string library. void strReverse(char *str)
- Count all bad elements present in the string taken as input, a character is bad if that character is a vowel and placed between two consonants, or if the character is a consonant and placed between two vowels. Input: aretpfigu Output: 4 Language: CPPCorrect answer will be upvoted else Multiple Downvoted. Computer science. You are given a string s, consisting of brackets of two types: '(', ')', '[' and ']'. A string is called a regular bracket sequence (RBS) if it's of one of the following type empty strin '(' + RBS + ')' '[' + RBS + ']' RBS + RBS where plus is a concatenation of two strings In one move you can choose a non-empty subsequence of the string s (not necessarily consecutive) that is an RBS, remove it from the string and concatenate the remaining parts without changing the order What is the maximum number of moves you can perfor Input The first line contains a single integer t (1≤t≤1000) — the number of testcases Each of the next t lines contains a non-empty string, consisting only of characters '(', ')', '[' and ']'. The total length of the strings over all testcases doesn't exceed 2⋅10 Output For each testcase print a single integer — the maximum number of moves you can perform on a given string…TAKE A LIST OF STRING FROM THE USER AND COUNT THE NUMBER OF UNIQUE ELEMENTS WITHOUT USING THE FOR, WHILE, Do-WHILE LOOPS. PREFERRED PROGRAMMING LANGUAGE: JAVA/C++
- Design strings {0,1} NFA such that it does not have 011 and 101.Please draw with the computer Draw a standard trie for the following set of strings: { banana, banner, ban, banned, banger, bank}public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…
- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string. This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is, str = new StringBuilder(str).reverse().tostring(); A bit convoluted, but does what is needed without fuss or muss. Maybe one day the Java strings will come with the reverse method built in, just like the string data types of all sensible…StretchWith2Vowels Specification: Read sentences from the user until * is entered. Show the number of words in each sentence that contain a stretch of non-z characters with exactly 2 vowels. A stretch starts from the start of the word or after a 'z'. A stretch terminates just before another 'z' or at the end of the word. Examples: 1. Matching words: zoo, azozooza, GONZALEZ 2. Non-matching words: ozo, azoooza The sentences contain no punctuation, the words are separated by one or more spaces, and the characters may be upper or lower case. Keep reading sentences until the user enters "*". Sample I/O: Sentence: azoooza azooza zoo azo0 Matching words = 3 Sentence: GONZALEZ passes the ball to VAZQUEZ Matching words = 3 Sentence: azozototzeti Matching words = 1 Sentence: * DoneR-> SIST S->asb| bb T-> bTa | aTb | a Which of the following is not a valid string in the leftmost reduction of string Lütfen birini seçin: O A. Sabaab O B. SabTab O C.babTab O D. ST