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- Question 2. An enzyme was found to convert Acetyl-coA to an acetyl-cysteine intermediate of the enzyme. The structure of cOA is: H H НО СН; HS — СH2— СH2 — N—C—CH,— CH2—N- С—С—С—CH;—0—Р- 0–CH2 Adenine н CH H H H Phosphopantetheine group of coenzyme A 2-O3PO ОН Draw a plausible chemical mechanism. Where is the acetyl-group in acetyl-coA? What is the reactive group of the protein? The reaction is enhanced at higher pH. How is this consistent with your mechanism? Is covalent catalysis involved?Question 6 of 19 Proteasomal proteases can be inhibited by compounds such as ixazomib (shown below). How does this compound inhibit protease activity? HO Ixazomib O Uncomptetitively O Competitively O NoncompetitivelyQuestion 10 Observe this structure, use the pK, table, and choose the CORRECT statement. H2N-CH-C-OH CH2 OH O Tyrosine's side chain is involved in hydrogen bonding typical of secondary structures O Tyrosine's alpha carboxyl group is the most acid of the three dissociable groups O Tyrosine's side chain is partially dissociated at physiological pH O All of these are correct
- QUESTION 1 Which of the following concepts in column A best fits the concept in column B. p-Nitrophenyl a-D-Glucoside Action of intracellular a-GLUCOSIDASE + NaHCO3 Boiling cells Tris-pH 5.0 A. Substance that act as molecular mimic of a maltose molecule B. Develops TT-Nitrophenyl into a yellow colour reagent for measurement at 400nm c. Breaks the a-linkages of p-Nitrophenyl a-D-Glucoside, leaving p-Nitrophenyl and a glucose molecule D. Allows transport of p-Nitrophenyl a-D-Glucoside across the membrane E. Stop the reaction and release internal p-NitrophenylQuestion 5 of 40 Side-by-Side Identify the charge states for aspartic acid (Asp), leucine (Leu) and Lysine (Lys) at pH 1, 7 and 12. Then calculate the isoelectric point (pI). Step 7: Determine the appropriate calculation for the pl of lysine. For lysine, the pKa of the amine is 8.95, while the pKa of the carboxylic acid is 2.18 and the pK, of the amine in the Strategy: First identify the sidechain on each amino acid. Then determine whether the side chain is acidic, basic or side chain is 10.53. neutral. Determine whether each functional group is Calculate the pI of lysine. charged or not at the pH indicated. Calculate the (pI) from the pKa values of the functional groups. pI MacBook ProQuestion 11 Observe the titration curve below and choose the CORRECT statement. 12 - pK2 10 8- PK, 2. 0.5 1.0 1.5 Equivalents of OHO 2.0 O Two of these are correct O At point A, both acidic groups are protonated O At point A, both acidic groups are deprotonated O Cis the end point of titration for the most acidic group O B is the end point of titration for the most acidic group « Previous N. LG rotein d (basic)Rgoup Jacidic) Rgroup ged Rgroup
- QUESTION 4 What TYPE of inhibition is observed in the following: S E Competitive Non-competitive Uncompetitive AllostericQuestion 3. Dihydrofolate reductase (DHFR) is capable of making one carbon moieties of various oxidation states (i.e., methanol, formaldehyde, formate). Folic acid, a B vitamin, provides the critical chemistry: R. This type of chemistry is utilized in the synthesis of nucleotides. Methotrexate has a significantly higher affinity (Kd - 50 pM) than folate for the enzyme and is used in cancer therapy to suppress DNA synthesis of rapidly dividing cancer cells. What is a tempting reason for methotrexate having such high affinity?Question 1: The overall process enabled by the glyoxylate cycle is: (2acetyl-CoA) + (NAD+) + (2H2O) → (succinate) + (2CoA) + (NADH) + (2H+) Dissect this process further by writing down all of the reactions that are actually involved in making one succinate from two acetyl-CoA units. Show chemical structure for all intermediates.
- Question 1 Which statement is TRUE in relation to amylose and amylopectin? O Amylopectin is highly branched and the main component of resistant starch. O Amylose is generally more resistant to enzymatic hydrolysis than amylopectin. O They both contain beta 1-4 glycosidic linkages between glucose molecules. O Amylose is a highly branched polymer that is more rapidly hydrolysed than amylopectin.Question 4. Diabetes mellitus possesses a serious health challenge worldwide and there has been an increased awareness for self-monitoring and point of care testing. The development of self- monitoring of blood glucose (SMBG) is probably the most important advance in controlling diabetes since the discovery of insulin. a) Dextrostix, the first glucose meter was invented by Ernie Adams. Briefly discuss. b) There are three principles of enzymatic reactions, utilized by current glucose meters. Compare and briefly discuss these three principles.Question 10 Which of the following statements is incorrect? O In delta notation of fatty acid nomenclature, the numbering starts at the a-carbon from the carboxylic acid end. O Glycerophospholipids are the most abundant lipids in cellular membranes. O Hormones, such as testosterone, estradiol and progesterone are examples of steroidal lipids. O The rigidity of a saturated fatty acid is based on the strong bonding between sp3-hybridized carbon chains.