1. A man with a rare genetic trait marries an unaffected woman and they have four children (first two girls and then two boys). Draw a pedigree for each condition showing the distribution of affected (shaded), carrier and unaffected children in relation to the probability of each event. Distribute the affected offspring according to their probability of being affected (for example, equal numbers, only one sex). Also, provide a brief explanation for the pattern of affected and unaffected children. autosomal dominant (father is heterozygous) sex-linked dominant autosomal recessive sex-linked recessive Y-linked mtDNA-linked

1. A man with a rare genetic trait marries an unaffected woman and they have four children (first two girls and then two boys). Draw a pedigree for each condition showing the distribution of affected (shaded), carrier and unaffected children in relation to the probability of each event. Distribute the affected offspring according to their probability of being affected (for example, equal numbers, only one sex). Also, provide a brief explanation for the pattern of affected and unaffected children. autosomal dominant (father is heterozygous) sex-linked dominant autosomal recessive sex-linked recessive Y-linked mtDNA-linked

Biology: The Unity and Diversity of Life (MindTap Course List)

14th Edition

ISBN:9781305073951

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter13: Observing Patterns In Inherited Traits

Section: Chapter Questions

Problem 1SQ: A heterozygous individual has a _______ for a trait being studied. a. pair of identical alleles b....

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| 3 4 |IL 1 I Section 5: Trihybrid cross and Laws of probability For a trihybrid cross, in which inheritance of alleles for three genes is tracked, drawing a Punnett square that combines all three genes may not be practical. Instead the laws of probability may be used. The product law of probabilities says that when alleles for separate genes segregate independently, we can figure out the probability of a particular combined genotype by multiplying the probability of the alleles for each gene. 13. We cross a homozygous tall pea plant with yellow, round seeds to a homozygous dwarf pea plant with green, wrinkled seeds. All the F1 offspring are all tall plants with yellow, round seeds. a. What are the expected F2 ratios (use fractions) of tall and dwarf plants? b. What are the expected F2 ratios (use fractions) of yellow and green seeds? C. What are the expected F2 ratios (use fractions) of round and wrinkled seeds? d. What are the possible F2 combined phenotypes and their expected ratios…
1 A B C 5 D 6 7 8 9 10 11 Which of the following best describes the genotype of parents in the pedigree? Female with Long Hair Female with Short Hair Male with Long Hair Male with Short Hair The mother is heterozygous for the long-hair allele, and the father is homozygous for the long-hair allele. The mother is heterozygous for the long-hair allele, and the father is heterozygous for the long-hair allele. The mother is homozygous for the long-hair allele, and the father is homozygous for the long-hair allele. The mother is homozygous for the long-hair allele, and the father is heterozygous for the long-hair allele. Submit
1. Use the below pedigree chart to answer the following questions about dimples. The Dimple gene controls whether a person has dimples or doesn't have dimples. Dimples is dominant to no dimples. Place the genotypes of each individual below its symbol. male female 7 10 11 male femake Dimples gene (D) Dimples is dominant to no dimples 12 13 14 A) How many family members have Dimples? B) What is the genotype of individual #3 and 4? C) Can either individual #8 or 9 be homozygous? C) Explain the family relationship that #12 has with # 2.
2) 0,0 0,0 1 The most likely inheritance pattern in the pedigree abolve s:
1. Mendel crossed a plant that was heterozygous for height and heterozygous for pea shape with a plant that was homozygous dominant for height and heterozygous for shape. What are the possible genotypes and phenotypes of the offspring? Dominant for height= T (tall) Recessive for height =t (short) pea Dominant for pea shape = R (round) %3D Recessive for pea shape =r(wrinkled) P1:
Assumptions: . If the parent expresses the trait, they are homozygous dominant If the child/children express the trait but the parents do not, the parents are heterozygous. Traits selected: Brown Hair/Eyes And Widows Peak Write the Letters you will be using n the Punnet square for each trait: _Ww Bb_and_ww Bb_ Father Genotype: WW Bb Mother Genotype: ww Bb Parent Gametes possible gametes: possible gametes: Do you have the phenotype of either of the traits in the cross? If you do, which one? Are there any other offspring with either trait? Which trait? Which phenotypic probability did you fall into? Which phenotypic probability did other offspring fall into? I
Match the non-Mendelian genetic terms with their descriptor. Genetic and environmental factors collectively influence a phenotypic expression 1. Pleiotropy Two or more genes have a cumulative effect on a 2. Epitasis single phenotype 3. Polygenic Inheritance A single gene has more than one phenotypic effect 4. Multifactorial Effect A gene at one locus has an effect on a gene at another locus
A. Consider this cross before answering the following questions:A pea plant heterozygous for the first trait and recessive for the second trait is crossed with a pea plant heterozygous for the first trait and homozygous-dominant for the second trait. 1. If the first gene is demonstrating dominant epistasis to the second gene, what is the probability that the F1 progeny will expressa. the dominant feature for the second trait?b. the recessive feature for the second trait?c. Neither dominant nor recessive features for the second trait?
A. Consider this cross before answering the following questions:A pea plant heterozygous for the first trait and recessive for the second trait is crossed with a pea plant heterozygous for the first trait and homozygous-dominant for the second trait. 1. If the first gene is demonstrating recessive epistasis to the second gene, what is the probability that the F1 progeny will express a. the dominant feature for the second trait?b. the recessive feature for the second trait?c. neither dominant nor recessive features for the second trait?
Dimples (D) are a dominant trait genetic trait. Complete a Punnett Square to determine the possible phenotypes and genotypes of a cross between a man who is homozygous dominant and a heterozygous woman. Choose the percentages correctly below. Dimples: 0% 25% 50% 75% 100% No dimples: 0% 25% 50% 75% 100% DD: 0% 25% 50% 75% 100% Dd: 0% 25% 50% 75% 100% dd: 0% 25% 50% 75% 100%
● ● ● ● ● ● Consider the selfed offspring of a AaBbCcDd individual: What is the probability that offspring will have the following genotypes: AABBCCDD AaBbCCDd A_B_C_D_ BbCCDd 1/4 x 1/4 x 1/4 x 1/4= 1/256 1/2 x 1/2 x 1/4 x 1/2= 1/32 3/4 x 3/4 x 3/4 x 3/4= 81/256 1 x 1/2 x 1/4 x 1/2= 1/16 Same genotype as the parent? Same phenotype as the parent? A.1 B.1/16 C.1/32 D.1/256 E.81/256
Consider the following cross examining four gene in two parental lines: Parent 1: A/a; B/b; D/d; e/e Parent 2: a/a; b/b; d/d; E/e Assuming independent assortment for the four genes, what fraction of progeny will have the same genotype as that of parent 2? O 1/2 O 1/4 1/8 O 1/16