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CVA Biology
Unit 2 – Chemistry of Life
E2.03.1 Early Cells Cell Transport
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Introduc±on
In this lab you will use vinegar, a weak acid, to dissolve the shell off of the egg to expose the membrane. When you place the egg in water you will be able to observe osmosis in ac±on over a few days. The lab will be conducted in a video in lesson L2.03 page 6.
Learning Goals-
A²er comple±ng this assignment, students will:
Use the informa±on in Lesson L2.03 to help complete this assignment.
Go to page 6 of lesson L2.03 and watch the directed video.
Complete Lesson L2.03 and then watch the video observa±on lab. By watching the directed lab video on page 6 you should then answer the ques±ons below. Student Name:Camila Mendoza
Teacher Name:Mis. Brown QUESTION:
You do not need to do anything here.
How are cells affected by the movement of water?
If a cell is placed in a hypertonic solu±on, water will leave the cell, and the cell will shrink.
Develop models to show ac±ve and passive transport. ●
Inves±gate the process of cellular transport
●
Develop a plan (scien±fic inves±ga±on) that displays cellular transport using common household products.
●
CVA Biology
Unit 2 – Chemistry of Life
E2.03.1 Early Cells Cell Transport
PROCEDURE:
The procedures are listed in the Early Cell Cells Transport Virtual Lab Ac±vity. You do not need to include them here.
MATERIALS
HYPOTHESIS:
(What do you think will happen to the egg a²er the three days? Be sure to give a reason for your hypothesis.)
List your predic±ons for the lab here: The shell will be dissolved and the egg will be mushy.
DATA & OBSERVATIONS
Fill in the chart according to your observa±ons in the video lab:
Time (hrs)
Observa±ons
Circumference (cm)
0
1. Brown egg
18cm
2. Egg intact
24
1. Shell dissolved
17.5cm
2. White spots
48
1. White-ish color
18cm
2. Looks mushy
72
1. White and brown-
grayish
18.5cm
2. more round
ANALYSIS & CONCLUSION
QUESTION 1:
How much did the egg change in size? (answer should be in cen±meters) Use complete sentences to answer analysis & conclusion ques±on 1:
The egg became rounder and the circumference became larger.
At 0 hours the circumference was 18cm and at 72 hours it became 18.5cm.
ANALYSIS & CONCLUSION
QUESTION 2:
Was your hypothesis correct? Why or why not?
Use complete sentences to answer analysis & conclusion ques±on 2:
Yes my hypothesis was partly correct because I do not know the texture of the egg but the shell did dissolve. The Early Cells Cell Transport Virtual Lab Ac±vity
1.
Early Cells Cell Transport Lab Report
2.
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Oceanic uptake of carbon dioxide is thus described:CO2 (g) + H2O ⇔ H2CO3, K = [H2CO3]/PCO2 = 3 x 10-2 M atm-1 H2CO3 ⇔ HCO3- + H+, K = [HCO3-][H+]/[H2CO3] = 9 x 10-7 moles/LHCO3- ⇔ CO32 - + H+, K = [CO32 -][H+]/[HCO3-] = 7 x 10-10 moles/L
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Intestinal epithelial cells pump glucose into the cell against its concentration gradient using the Na+-glucose symporter.
Recall that the Na+ concentration is significantly higher outside the cell than inside the cell. The symporter couples the
"downhill" transport of two Na+ ions into the cell to the "uphill" transport of glucose into the cell.
If the Na* concentration outside the cell ([Na*lout) is 149 mM and that inside the cell ([Na*]in) is 21.0 mM, and the cell
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cell. Assume the temperature is 37 °C.
kJ
What is the maximum ratio of [glucose];n
[glucose]out
AGgluc =
mol
that could theoretically be produced if the energy coupling
were 100% efficient?
3.5 x 10–4
7.96
2900
1.13
O O O
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Carry out the given conversions from one metric unit of length to another.
83.5 Mm =
km
4.75 nm =
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You are supplied with the following: / Jy word voorsien van die volgende:
NaCl(Mr= 58,443 g /mol)
2.5MTris-Cl, pH 8 solution /oplossing (1 Litre)
EDTA,natriumsout(Mr= 380,2g/mol)
10% sodium dodecyl sulphate solution / natriumdodecyl sulfaat oplossing
Proteïnase K solution / oplossing (50 mg dissolved / opgelos in 1 ml ddH2O)
You need a digestion buffer consisting of the following: / Jy moet 'n verteringsbuffer op maak wat uit die volgende bestaan:
15m M NaCl
75 mM Tris-Cl,pH 8
16 mM EDTA,pH 8
0.8% sodium sulphate / natrium dodecyl sulfaat
0,75 mg/ml proteïnase K
How will you prepare 500 ml of the digestion buffer? Show all your steps and calculations. Remember to explain exactly how you will make it up.
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6. A 190 lb worker in a factory received an exposure to AB which has a molecular weight
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Soln. 1
Soln. 2
Soln. 3
Analysis of saturated Calcium lodate "Ca(103)2" solutions
Molarity of
103
Molarity of
Ca²+
(mol/L)
(mol/L)
7.34410-5
0.005
Moles of
S2032- used
4.406x10
-4
3.694×10
Average Ksp:
+4
3.204×10
Moles of 103
reacted
7.34×10
6.156 x 10-5
5.34410
5
= 0·0147
6.156X10-5
0.005
0.0123
5.34x10-5
0.005
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1) Listen
The Ksp value for calcium sulfate [CaSO4] is 2.40 X 10-5 and a professor made 1825
mL of a CaSO4(ag) solution but then one of his graduate student accidentally poured
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the additional volume coming from the Cag(PO4)2 solution to make the calculation
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common ion effect then which way will the chemical equilibrium shift?
need more information to be determined
at equilibrium
chemical equilibrium will shift to the right first and then to the left
chemical equilibrium will shift to the right
chemical equilibrium will shift to the left
201591..docx
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6.
Your body deals with excess nitrogen by excreting it in the form of urea, NH2CONH2. The reaction
producing it is the combination of arginine (C,H14N,O2) with water to give urea and ornithine
(C;H12N2O2).
OʻH + ?O*N*'H°Ɔ
Urea
O'NHO + HNOƆ'HN
Arginine
Ornithine
[Molar masses:
174.2
18.02
60.06
132.2]
If you excrete 95 mg of urea, what quantity of arginine must have been used? What quantity of
ornithine must have been produced?
3.
MacBook Air
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(b) What is the cell formula for this microorganism?
(c) Assuming 100% conversion, calculate the yield of cells from hexadecane (Yx/s) and from oxygen
(YX/0₂).
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What is the value of kcat?
2.86 x 10-3 M
0.25 M/s
4.0 s-1
2.86 x 104 s/M
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Solution 1 Solution 2
Solution 3
Solution 4
Solution 5
Concentration iron(III) nitrate
0.00200
0.00200
0.00200
0.00200
0.00200
[Fe(NO3)3] (M)
Concentration potassium thiocyanate
0.00200
0.00200
0.00200
0.00200
0.00200
[KSCN] (M)
Volume Fe(NO3)3 (mL)
5.00
5.00
5.00
5.00
5.00
Volume KSCN (mL)
5.00
4.00
3.00
2.00
1.00
Volume DI water (mL)
0.00
1.00
2.00
3.00
4.00
Initial concentration [Fe3+] (M)
0.00100
0.00100
0.00100
0.00100
0.00100
Initial concentration [SCN] (M)
0.00100
0.000800
0.000600
0.000400
0.000200
Absorbance
0.269
0.192
0.154
0.104
0.052
Equilibrium [FeSCN2+] (M)
0.000198
0.000141
0.000113
0.0000765
0.000038
Equilibrium constant Kc
Average Kc
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Q27
A 10-1 is performed on a culture of bacteria in order to perform viable plate counts. From the dilution, *0.1 mL* of solution is plated on solid media, and 265 colonies of bacteria grow on the plate.
Assuming each colony came from a single bacterium, how many bacteria are in a single mL of the original culture? Express your answer as a whole number.
Since only 0.1 mL is put on the plate, this counts as an extra dilution!!!
Any time less than 1 mL is transfered, a dilution is being performed.
Any time more than 1 mL is transfered, a concentration is being performed.
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+ > C a apclassroom.collegeboard.org/113/assessments/assignments/44514144
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4
9.
Question 9 A
CH4 (g) + 2 O2 (g) CO2 (g) + 2 H2O (g)
When CH,(g) is burned in 02(g), the reaction represented by the equation occurs.
If 32 g of CH, is burned completely, how many moles of CO, are produced? Enter the number of moles to the nearest whole number.
mol
TL
11
46
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Referonces
Use the References to access important values if needed for this question.
For the following reaction, 50.4 grams of sulfur dioxide are allowed to react with 17.9 grams of water.
sulfur dioxide (g) + water (I) sulfurous acid (H2SO3) (g)
grams
What is the maximum amount of sulfurous acid (H,SO3) that can be formed?
What is the FORMULA for the limiting reagent?
grams
What amount of the excess reagent remains after the reaction is complete?
Submit Answer
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Anna analyzed arsenic content on a fish purchased from local wet market. According to
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In this study, an average of 11.4 2.1 ng/g was obtained based on six sample replicates.
Suggest a suitable analytical instrument to be used in this analysis and draw a conclusion
on the safety of arsenic content of this fish sample.
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A direct enzyme-linked immunosorbent assay (ELISA) test on a patient's sample is shown below. Development of a strong (dark) color reaction would indicate:
1 Antibody is adsorbed to well. 2 Patient sample is added;
complementary antigen
binds to antibody.
3 Enzyme-linked antibody specific 4 Enzyme's substrate () is added,
for test antigen is added and binds and reaction produces a product
that causes a visible color change (O).
to antigen, forming sandwich.
A low concentration of a specific antigen in the patient's sample
O A high concentration of a specific enzyme in the patient's sample
The patient's antibody is specific for the enzyme's substrate
O A high concentration of a specific antigen in the patient's sample
A high concentration of a specific antibody (against the test antigen) in the patient's sample
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200406_Homework..mdahl_Chapter 04 - Saved
Homework (Chapter 4)
2019. 4. 6
Example 4.1
Calculate the molarity of a solution preparcd by dissolving 11.5 g of solid NaOH in enough water to make 1.50 L
of solution
Example 4.2
Calculate the molarity of a solution prepared by dissolving 1.56g of gascous HCl in enough water
make 26.8
mL of solution.
Ехample 4.3
Give the concentration of each type of ion in the following solutions:
(a) 0.50 M Co(NO:)
(b) 1 M Fe(ClO4)3
Example 4.4
Calculate the number of moles of Cl ions in 1.75 L of 1.0 x 10-3 M ZnCl,.
Ехample 4.5
Typical blood serum is about 0.14 M NaCl, What volume of blood contains 1.0 mg NaCl?
Example 4.6
To analyze the alcohol content of certain wine, a chemist needs 1.00 L of an aqueous 0.200 MK CrO (potassium
dichromate) solution. How much solid K CrO, must be weighed out to make this solution?
Ехample 4.7
What volume of 16 M sulfuric acid must be used
prepare 1.5 L of a 0.10 M H,SO, solution?
Ехample 4.8
Using the…
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Chemistry
5 grams of cereal was crushed and dissolved in 25 mL water and placed in a dialysis bag. This sample was dialysed over a week in a beaker which contains 500 mL of water. 5 mL of the dialysate (an aliquote from the 500 mL) was separated to determine the glucose concentration. The glucose concentration was determined as 5 mM. Calculate the amount (% w/w) of glucose present in the cereal. Hint: The molecular weight of glucose is 180.
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9 Unit 2 Olympics | S.
PowerPoint
SWYK: FFF Microscopy, Cell Theory, and Cell Processes
POSSIBLE POINT
Match the cell organelle with its function
cell membrane
mitochondrion
nucleus
chloroplast
:: controls the movement of materials in and out of a cell
:: controls all cell processes
:: carries out photosynthesis in plants and algae
: carries out cell respiration
3\
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Let me tell you about their task:
The students were provided with 5 drinks (sports/soft drinks) and they were asked to determine the glucose concentration in these drinks in the units of g/100mL. (Why these units? Well, once the students have the concentrations in g/100mL they will be able to compare their values with the nutritional values given on the drink bottles’ labels).
The samples of the five drinks were all diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for the students is that the dilution factor will have to be taken into consideration in their calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink).
The students decided to save time and form five groups where each group was…
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mal text
Arlal
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1. What is the smallest unit of life?
a. Вacteria
b. Virus
C. ameba
d. cell
I
I!!
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Write the expression for Keq for the following reactions. In each case indicate whether the reaction is homogeneous or heterogeneous.(a) N2(g) + 3 H2(g) 2 NH3(g)
Keq = PNH32 / (PN2 PH23)
Keq = (PN2) (3 PH2) / 2 PNH3
Keq = PN2 PH23 / PNH32
Keq = 2 PNH3 / ((PN2) (3 PH2))
The reaction is (b) 4 HCl(g) + O2(g) 2 H2O(l) + 2 Cl2(g)
Keq = PHCl4 PO2 / PCl22
Keq = 2 PCl2 / (4 PHCl PO2)
Keq = 4 PHCl PO2 / 2 PCl2
Keq = PCl22 / (PHCl4 PO2)
The reaction is (c) H2(g) + I2(g) 2 HI(g)
Keq = 2 PHI / (PH2 PI2)
Keq = PH2 PI2 / 2 PHI
Keq = PH2 PI2 / PHI2
Keq = PHI2 / (PH2 PI2)
The reaction is
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* HSC 258 - Major Projec X
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=55750828934189288909969212&elSBN=9781305657571&id=1061392007&nbld=21... *
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References
Use the References to access important values if needed for this question.
It is desired to produce 6.30 grams of sulfur trioxide by the following reaction. If the percent yield of
sulfur trioxide is 78.4 %, how many grams of sulfur dioxide would need to be reacted?
grams sulfur dioxide
sulfur dioxide(g) + oxygen(g)·
→ sulfur trioxide(g)
Submit Answer
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app.101edu.co
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Phthalonitrile (CHN) is produced by the ammoxidation
of o-xylene (C₂H₁) according to the following reaction:
C₂H₁ (1) + O₂(g) + NH₂(g) → C₂H₂N₂(s) + H₂O(1)
How many grams of water would be produced by the
complete ammoxidation of 3.98 moles of o-xylene?
8
Chemistry 2e - CX
.
Question 13 of 24
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Calculate the solubility of PbF, in water at 25 °C. You'll find K data in the ALEKS Data tab.
sp
Round your answer to 2 significant digits.
x10
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A water quality investigation is conducted in a suburban stream. Investigators determine
that there are high amounts of developmental malformations in the bluegill fish
population.
Which of the following statements suggests the most likely cause of this change in the
bluegill population?
A.
Surface runoff containing nitrates from animal feedlots is entering upstream of the
bluegill population.
Surface runoff containing phosphates from animal feedlots is entering upstream of the
bluegill population.
Surface runoff containing pollutants from acid precipitation is entering upstream of the
bluegill population.
Surface runoff containing endocrine disruptors is entering upstream of the bluegill
population.
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- Oceanic uptake of carbon dioxide is thus described:CO2 (g) + H2O ⇔ H2CO3, K = [H2CO3]/PCO2 = 3 x 10-2 M atm-1 H2CO3 ⇔ HCO3- + H+, K = [HCO3-][H+]/[H2CO3] = 9 x 10-7 moles/LHCO3- ⇔ CO32 - + H+, K = [CO32 -][H+]/[HCO3-] = 7 x 10-10 moles/L CaCO3 ⇔ Ca2+ + CO32- Kc = 4 x 10-9 M2 What is the full charge balance equation for this system?arrow_forwardOceanic uptake of carbon dioxide is thus described:CO2 (g) + H2O ⇔ H2CO3, K = [H2CO3]/PCO2 = 3 x 10-2 M atm-1 H2CO3 ⇔ HCO3- + H+, K = [HCO3-][H+]/[H2CO3] = 9 x 10-7 moles/LHCO3- ⇔ CO32 - + H+, K = [CO32 -][H+]/[HCO3-] = 7 x 10-10 moles/LCharge balance equation:[H+] = [OH-] + [HCO3-] + 2[CO32 ] If the CO2 concentration in the atmosphere is 300 ppm, what is the pH of the ocean?arrow_forwardIntestinal epithelial cells pump glucose into the cell against its concentration gradient using the Na+-glucose symporter. Recall that the Na+ concentration is significantly higher outside the cell than inside the cell. The symporter couples the "downhill" transport of two Na+ ions into the cell to the "uphill" transport of glucose into the cell. If the Na* concentration outside the cell ([Na*lout) is 149 mM and that inside the cell ([Na*]in) is 21.0 mM, and the cell potential is –54.0 mV (inside negative), calculate the maximum energy available for pumping a mole of glucose into the cell. Assume the temperature is 37 °C. kJ What is the maximum ratio of [glucose];n [glucose]out AGgluc = mol that could theoretically be produced if the energy coupling were 100% efficient? 3.5 x 10–4 7.96 2900 1.13 O O Oarrow_forward
- E-book - Elementary Bioorgani × My Course - Elementary Bioorg X endocrine system - Google Do X Homework 1 Matter and Materia X Question 12 of 23 - Homework X assessments.macmillanlearning.com/sac/5338340#/5338340/11/1 Update : O Assignment Score: Lx Give Up? O Hint Check Answer 52.2% Resources < Question 12 of 23 Attempt 3 Carry out the given conversions from one metric unit of length to another. 83.5 Mm = km 4.75 nm = mm * TOOLS х10 !!!arrow_forwardYou are supplied with the following: / Jy word voorsien van die volgende: NaCl(Mr= 58,443 g /mol) 2.5MTris-Cl, pH 8 solution /oplossing (1 Litre) EDTA,natriumsout(Mr= 380,2g/mol) 10% sodium dodecyl sulphate solution / natriumdodecyl sulfaat oplossing Proteïnase K solution / oplossing (50 mg dissolved / opgelos in 1 ml ddH2O) You need a digestion buffer consisting of the following: / Jy moet 'n verteringsbuffer op maak wat uit die volgende bestaan: 15m M NaCl 75 mM Tris-Cl,pH 8 16 mM EDTA,pH 8 0.8% sodium sulphate / natrium dodecyl sulfaat 0,75 mg/ml proteïnase K How will you prepare 500 ml of the digestion buffer? Show all your steps and calculations. Remember to explain exactly how you will make it up.arrow_forwardA Life Science-1803035-377210-1 A Life Science-1803035-377210-1 1803035.agilixbuzz.com/student/142171010/activity/b13bdb49b1d84a84a3aff52cc918e067 Todigy Jackson-Wonder E. E Edulastic: Formativ. RL Home Zearn Math: Top-rat. A Who was the capta. Netflix M Wes mical Reactions - Show it > Life Science-1803035-377210-15 / Unit 7: Chemical Reactions/ Week 23 - Chemical Reactions/ Monday, Lesson 107 - 2/8/21 Identifying the Parts of a Chemical Reaction. Identify the reactants and products in the chemical reaction below. Identify the reactants: CH4 + 202 --> CO2 + 2H2O Your answer re attempting to view Google Drive co ts google.com/Login If it still d new tab Identify the products: CH4 - 202 --> CO2 + 2H2O Yok an Identify the reactants: NaCi Na CI OUS ACTIVITY New version available (30 220) GET IT NOW WHAT ARE REACTIONS?A WHAT ARE REACTIONS?- READ ITarrow_forward
- You have just started working in an Urgent Care Clinic as a nurse. Mom brings in her 3 year old little boy, Brandon. Mom states that Brandon has been having fever up to 104F and he isn't eating or drinking anything because he feels very sick to his stomach, not to mention crabby! He's also been pulling a lot at his right ear and sounds congested. At the last well visit with the Pediatrician (about 2 weeks ago), Mom states that Brandon weighed 32 pounds. On exam today, his weight is 12.5 kg. Additionally his eyes are darkened and sunken, his mouth is dry with some white crusting around the lips. His temperature is 39C, other vitals signs are normal. Though he looks ill he appears to be medically stable. The doctor rushes in, quickly exams Brandon, diagnoses him with otitis media and then barks off orders to you that you then need to convey accurately to Mom. The orders include: push fluids, ibuprofen 10mg/kg every 6 hours if temp > 38C, and begin taking a 10-day course of…arrow_forward6. A 190 lb worker in a factory received an exposure to AB which has a molecular weight (MW) of 278 g/mole. AB is completely metabolized in the body to A (MW 194) and B. A is completely excreted in the urine and B is further metabolized to five different compounds. A 24-hr total urine sample was 2060 ml, Analysis showed the concentration of A in the urine was 1.28 ng/mL What was the absorbed dose of AB in ug/kg body wt?arrow_forwardSoln. 1 Soln. 2 Soln. 3 Analysis of saturated Calcium lodate "Ca(103)2" solutions Molarity of 103 Molarity of Ca²+ (mol/L) (mol/L) 7.34410-5 0.005 Moles of S2032- used 4.406x10 -4 3.694×10 Average Ksp: +4 3.204×10 Moles of 103 reacted 7.34×10 6.156 x 10-5 5.34410 5 = 0·0147 6.156X10-5 0.005 0.0123 5.34x10-5 0.005 Ksparrow_forward
- 1) Listen The Ksp value for calcium sulfate [CaSO4] is 2.40 X 10-5 and a professor made 1825 mL of a CaSO4(ag) solution but then one of his graduate student accidentally poured in a 0.125 M solution of calcium phosphate [Ca3(PO4)2] solution. You may ignore the additional volume coming from the Cag(PO4)2 solution to make the calculation simpler. Now that you have calculated the new equilibrium constant (K) with this common ion effect then which way will the chemical equilibrium shift? need more information to be determined at equilibrium chemical equilibrium will shift to the right first and then to the left chemical equilibrium will shift to the right chemical equilibrium will shift to the left 201591..docx LAB EXP. #3 -..docx Show Allarrow_forward口 Tools Window Help A 79% Wed 5:2 CHEM2-CH 6-WORKsheet 6 (2).pdf (page 3 of 6)-Edited Q Search 6. Your body deals with excess nitrogen by excreting it in the form of urea, NH2CONH2. The reaction producing it is the combination of arginine (C,H14N,O2) with water to give urea and ornithine (C;H12N2O2). OʻH + ?O*N*'H°Ɔ Urea O'NHO + HNOƆ'HN Arginine Ornithine [Molar masses: 174.2 18.02 60.06 132.2] If you excrete 95 mg of urea, what quantity of arginine must have been used? What quantity of ornithine must have been produced? 3. MacBook Airarrow_forwardGypsum (CaSO4) is one of common precipitants in brackish water desalination processes. CaSO4 ⇋ Ca2+ + SO42- Ksp = 10-4.6Assume a water containing: [Ca2+] = 10-2.1 M; [SO42-] = 10-3.2 M.(a) Find Qsp or IAP for the given water. (b) Find the solubility index (SI) and determine whether CaSO4 is under, super, or at saturation in the water.arrow_forward
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