Explanation Given Information: The provided equation is I = 0.05 V , where I is current in an electrical circuit is I , (in amps) and V is in volts. Graph: Consider the equation, I = 0.05 V Non-negative values of V means the positive values of V . Calculate the values of current I at positive values of volts V . Substitute V = 0 in the equation I = 0.05 V . I = 0.05 ( 0 ) = 0 Substitute V = 10 in the equation I = 0.05 V . I = 0.05 ( 10 ) = 0.5 Substitute V = 20 in the equation I = 0.05 V . I = 0.05 ( 20 ) = 1 Substitute V = 30 in the equation I = 0.05 V . I = 0.05 ( 30 ) = 1.5 The table provided below shows the values of current I at different values of voltage V . V I = 0

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ISBN: 9781337630580

Author: Dale Ewen

Publisher: Cengage Learning

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Chapter 8.2, Problem 44E

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To graph: The equation I=0.05V for nonnegative values of V if the current in an electrical circuit is I, (in amps) and V is in volts.

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Chapter 8.2, Problem 43E

Chapter 8.2, Problem 45E

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To graph: The equation I = 0.05 V for nonnegative values of V if the current in an electrical circuit is I , (in amps) and V is in volts.

Solution Summary: The author illustrates the equation I=0.05V for non-negative values of V if the current in an electrical circuit is volts and amps.

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To graph: The equation I=0.05V for nonnegative values of V if the current in an electrical circuit is I, (in amps) and V is in volts.

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