Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN: 9781305632134
Author: J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher: Cengage Learning
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Chapter 7, Problem 7.32P
To determine
The circuit breaker for the given line.
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Data obtained from a short circuit test on a 132 kV 3-phase circuit breaker with earthed neutral are as follows:
-the power factor fault was 0.3.
-the recovery voltage was 0.75 of the full line value.
-the breaking current was symmetrical.
-the restriking transient had a natural frequency of 1600 Hz.
Estimate the rate rise of the recovery voltage. Assume that the fault is grounded.
In a short circuit test on 132 kV, 3-phase system, the breaker gives the following results: Power factor of the fault = 0.45. Recovery voltage 0.9 time of full line voltage. The breaking current is symmetrical.
The restriking transient has a natural frequency of 15 kHz. Calculate the rate of rise of restriking voltage (RRRV) in the following types of faults: (1) Grounded fault (2) Undergrounded fault.
7.In a line-to-ground fault we can expect that
A) There are no currents to ground.
B) The voltages at the fault point with respect to ground are zero in all three phases.
C) The current in the faulted phase flows to ground.
D) There are short circuit currents in all three phases.
E) N. A.
Chapter 7 Solutions
Power System Analysis and Design (MindTap Course List)
Ch. 7 - Even though the fault current is not symmetrical...Ch. 7 - The amplitude of the sinusoidal symmetrical ac...Ch. 7 - Equipment ratings for the four-bus power system...Ch. 7 - Equipment ratings for the five-bus power system...Ch. 7 - Prob. 7.22PCh. 7 - A three-phase circuit breaker has a 15.5-kV rated...Ch. 7 - Prob. 7.32P
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- 7.1 Phase a of a three-phase 4.16 kV ungrounded system is solidly grounded. For this fault, calculate the magnitude of the positive-, negative-, and zero-sequence volt- ages at the fault. Explain your answers with reference to the sequence networks and interconnections used to calculate line-to-ground faults on three-phase systems.arrow_forward4.In a double line-to-ground fault we can expect thatImmersive reader A) There are currents in the ground connections. B) The current values in the ground connections are zero. C) Short-circuit currents exist in all three phases. D) The currents in the faulted phases are equal. E) N. A.arrow_forwardcomplet The equivalent reactance of the double circuit line under post fault condition is................than fault condition.arrow_forward
- In a short-circuit test on a 3-pole, 220 kV circuit breaker. Power factor of the fault = 0.8 Recovery voltage, 1.90 times (full line voltage) The breaking current was symmetrical the restriking transient had a natural frequency of 30000 c/s. Determine the average rate of rise of restriking voltage. (The natural is grounded and the fault involves earth).arrow_forwardProblem 7. Three-phase Balanced Fault Analysis. For the two-generator system below, a three-phase short occurs at point A. Ignoring prefault currents and assuming a prefault bus voltage of 1.0 p.u., determine the fault current, in kA, contributed from generator G1. Assume base values of 50 MVA and 50 kV on transmission line side. 25 kV 50 MVA, 2.5% 50 MVA, 20% G 1:2 A G. 25 kV Z = 2+ j20 AY Z, 75 MVA, 15% Z, = 0.4% Figure 1arrow_forward3.On a double line-to-ground faultImmersive reader A) The short-circuit currents in the faulted phases are equal. B) The voltages at the fault point on the faulted phases are zero. C) The phase not involved in the fault has a zero voltage at the fault point. D) There are no circulating currents through the neutrals to ground. E) N. A.arrow_forward
- In a short-circuit test on a 3-pole, 110 kV circuit breaker. Power factor of the fault= 0.4. Recovery voltage= 0.95 times (full line voltage) The breaking current was symmetrical the restriking transient had a natural frequency of 15000 c/s. Determine the average rate of rise of restriking voltage. (The natural is grounded and the fault involves earth). Explain in details.arrow_forwarda) In Three Phase Faults that will occur separately on A, B, C and D Busbars, Calculate the currents. b) Maximum fault currents to pass through KA, KB, KC1, KC and KD Protection devices determine. Help me please... Thank you so much.arrow_forward4. Calculate three phase voltages and currents at fault location and at Bus G for a phase-A to Ground (L-G) fault at bus H, for a system as shown in Figure 2. Also draw the positive, negative, zero sequence networks and their interconnection diagram for this particular fault. 90 MVA 90 MVA 132kV H 132kV Line section Source Source B 100 MVA 100 MVA 132/69 kV 10% 132/69 kV 10% Figure - 2arrow_forward
- estion 9 The fault current level of a circuit breaker used in a transmission line with phase voltage 2.2 kV and breaking capacity 50 MVA is yet ......kA. vered -ked out of Flag question estion 10 The voltage between lines in a transmission line is the maximum value of the sine waveform. yet vered Select one: -ked out of O True Flag question O Falsearrow_forwardThe per unit values of positive, negative and zero sequence reactances of a network at fault are 0-08, 0-07 and 0-05 respectively. Determine the fault current if fault is line-to-line-to-ground.arrow_forward8.In a line-by-line failure we can expect Immersive reader A) Currents exist in the ground connections. B) The current values at the ground connections are zero. C) Short-circuit currents exist in all three phases. D) The voltages at the fault point with respect to ground are zero in the faulted phases. E) N. A.arrow_forward
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