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In a diploid plant species, an
a. What is the order of these three linked genes?
b. Calculate the recombination fractions between eachpair of genes.
c. Why is the recombination fraction for the outside pair of genes not equal to the sum of recombination fractions between the adjacent gene pairs?
d. What is the interference value for this data set?
e. Explain the meaning of this
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Chapter 5 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
- A male mouse that is heterozygous for a mutant Igf2 allele (Igf2/lgf2-) is crossed with a female who is homozygous for the wild-type lgf2 allele. What would be the expected outcome of this cross? Multiple Choice O O O O 1/2 the offspring would be normal; 1/2 would be dwarf All offspring would be normal because the paternal allele is expressed All offspring would be dwarf because the maternal allele is silenced All offspring would be dwarf because the paternal allele is silenced 3/4 of the offspring would be normal; 1/4 would be dwarf Aarrow_forwardIn this case a family history revealed a genetic basis for the disorder. The pedigree is shown in Fig. 1 Below. Key Ø Female: affected Female: unaffected || IV V 5600 orize 077808 15 10 9 10 CHO વ Male: affected Male: unaffected Deceased Disease status not given Dizygotic twins Monozygotic twins Fig. 1 Disease pedigree. Five generations I, II, III, IV, V are shown. Females are represented by circles, males by squares, dizygotic (non-identical) twins by diagonal lines originating from the same point, Monozygotic (identical) twins by diagonal lines originating from the same point and joined symbols and deceased by a diagonal line through the symbol. Filled symbols indicate that the individual displays the disease phenotype. Unfilled symbols indicate that the individual does not display the disease phenotype. Carriers of the disease are not indicated. Information on disease status is not known for generation I and is omitted for the individuals represented by a symbol with an asterisk.…arrow_forwardIn a diploid plant species, an F1 with the genotype Mm Rr Ss is test crossed to a pure breeding recessive plant with the genotype mm rr ss. The offspring genotypes are as follows: Genotype Number Mm Rr Ss 687 Mm Rr ss 5 Mm rr Ss 68 Mm rr ss 196 mm Rr Ss 185 mm Rr ss 72 mm rr Ss 8 mm rr ss 679 Total 1900 1. What is the gene order of these linked genes?arrow_forward
- An individual heterozygous for d e f (D/d E/e F/f) was crossed to a homozygous recessive individual (d/d e/e f/f). The following offspring were recovered.d e + 39+ e f 372d + f 7+ + f 47+ e + 5d + + 412What is the correct order of these genes? EDF DFE DEFarrow_forwardFor each genotype, indicate whether it is heterozygous (HE) or homozygous (HO) AA Bb Cc Dd Ee ff GG HH PP Pp pp Round seeds are dominant to wrinkled RR Rr rr Ii Jj kk For each of the genotypes below, determine the phenotype. Purple flowers are dominan to white flowers L1 Mm nn straight straight curly 00 Pp Brown eyes are domin BB Bb bb to blue eyes Bobtails are recessive (long tails dominant) TT Tt tt For each phenotype, list the genotypes. (Remember to use the letter of the dominant trait) Straight hair is dominant to curly. Pointed heads are dominant to round heads. pointed pointed roundarrow_forwardthree recessive genes a, b, and c in the model plant Arabidopsis are found to be linked on chromosome 4. A three point test cross is done with a homozygous recessive plant with a heterozygous for all three genes. Following is the number of progenies a b C 65 A B c 56 A B C 1267 a b c 1310 A b C 550 a B c 515 a B C 470 A b c 489 Total = 4,722 Determine the middle locus by your choice of method and after that calculate the map distance between the genes in map unit (m.u.).arrow_forward
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- In a diploid plant species, an F1 with the genotype Mm Rr Ss is test crossed to a pure breeding recessive plant with the genotype mm rr ss. The offspring genotypes are as follows: Genotype Number Mm Rr Ss 687 Mm Rr ss 5 Mm rr Ss 68 Mm rr ss 196 mm Rr Ss 185 mm Rr ss 72 mm rr Ss 8 mm rr ss 679 Total 1900 1. What is the interference value for this data set?arrow_forwardA cross between the F1 individual in Figure 21.6 and a plant with genotype B-I B-I will produce progeny with what phenotype?arrow_forwardThe result of a test cross of a yeast cell that is heterozygous for three genes are summarized in the table (below), which shows the number of offspring that inherited each combination of alleles from the heterozygous parent. Use the data collected to make a genetic map of the three genes L, Q, and D. • D-Q: o D-L: | o Q-L: | - L L I L L cM CM Alleles CM Ơ Ơ o Q o d D D d d d # 104 27 78 Report your results by entering the genetic distance between each pair of genes in the blanks below. Round to the nearest 0.1 cm. 64 28 62 106 81arrow_forward
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