EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M
6th Edition
ISBN: 9781305687875
Author: Gilbert
Publisher: CENGAGE LEARNING - CONSIGNMENT
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Chapter 3.3, Problem 22E
a)
Interpretation Introduction
Interpretation:Difference in melting points of sample with sample tube has height of
Concept introduction:Melting point is temperature that involves conversion of substance from solid to liquid state. Both liquid and solid phases are present in equilibrium with each other at this temperature.
b)
Interpretation Introduction
Interpretation:Source of error in measurement of melting point of
Concept introduction:Melting point is temperature that involves conversion of substance from solid to liquid state. Both liquid and solid phases are present in equilibrium with each other at this temperature.
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You were tasked to separate the components of a mixture containing silica, sodium chloride and charcoal. TNāCI
dissolves in water while silica and charcoal are not water-soluble. Only charcoal dissolves in carbon disulfide.
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b. Given the following data, determine the percentage of charcoal, sodium chloride and silica.
Mass (g)
Mass of beaker
100.000
Mass of beaker + mixture
110.000
mass of evaporating dish
62.000
mass of evaporating dish + solid after
evaporation of water
65.000
Mass of beaker + charcoal + silica after evaporation of
excess water
117.000
mass of beaker + silica after decanting dissolved charcoal
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113.545
Two samples have the exact same melting points. Are they the same compound? How could you tell for sure?
A group of students performed a melting point experiment to study the physical properties of ionic and covalent solids. The data collected are shown in the table.
Solid Sample
Melting Point (oC)
Time Elapsed (min)
Table Sugar (sucrose)
186
18
Table Salt (sodium chloride)
500 (not observed)
30
Paraffin Wax
37
4
Vegetable Lard
50
>5
Using the information contained in the table, what is the BEST explanation for the results?A The melting point of sodium chloride was not observed because ionic solids do not melt, whereas sugar, wax, and lard melted because they are softer than salt.B The melting points of covalently bonded solids tend to be lower than ionic solids. The melting point of sucrose was greater than the wax or the lard because sucrose has stronger bonds than wax or lard.C The melting point of sodium chloride was not observed because ionic solids are composed of positive and negative ions that do not melt; whereas, the…
Chapter 3 Solutions
EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M
Ch. 3.2 - Prob. 1ECh. 3.2 - Prob. 2ECh. 3.2 - Prob. 3ECh. 3.2 - Prob. 4ECh. 3.2 - Prob. 5ECh. 3.2 - Prob. 6ECh. 3.2 - Prob. 7ECh. 3.2 - Prob. 8ECh. 3.2 - Prob. 9ECh. 3.2 - Prob. 10E
Ch. 3.2 - Prob. 11ECh. 3.2 - Prob. 12ECh. 3.2 - Prob. 13ECh. 3.2 - Prob. 14ECh. 3.2 - Prob. 15ECh. 3.2 - Prob. 16ECh. 3.2 - Prob. 17ECh. 3.2 - Prob. 18ECh. 3.2 - Prob. 19ECh. 3.2 - Prob. 20ECh. 3.2 - Prob. 21ECh. 3.2 - Prob. 22ECh. 3.2 - Prob. 23ECh. 3.2 - Prob. 24ECh. 3.2 - Prob. 25ECh. 3.2 - Prob. 26ECh. 3.2 - Prob. 27ECh. 3.2 - Prob. 28ECh. 3.2 - Prob. 29ECh. 3.2 - Prob. 30ECh. 3.2 - Prob. 31ECh. 3.2 - Prob. 32ECh. 3.2 - Prob. 34ECh. 3.3 - Prob. 1ECh. 3.3 - Prob. 2ECh. 3.3 - Prob. 3ECh. 3.3 - Prob. 4ECh. 3.3 - Prob. 5ECh. 3.3 - Prob. 6ECh. 3.3 - Prob. 7ECh. 3.3 - Prob. 8ECh. 3.3 - Prob. 10ECh. 3.3 - Prob. 11ECh. 3.3 - Prob. 12ECh. 3.3 - Prob. 13ECh. 3.3 - Prob. 14ECh. 3.3 - Prob. 15ECh. 3.3 - Prob. 16ECh. 3.3 - Prob. 17ECh. 3.3 - Prob. 18ECh. 3.3 - Prob. 19ECh. 3.3 - Prob. 21ECh. 3.3 - Prob. 22ECh. 3.3 - Prob. 23ECh. 3.3 - Prob. 24ECh. 3.3 - Prob. 25ECh. 3.3 - Prob. 26E
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- General Chemistry 4th Edition McQuarrie • Rock • Gallogly Consider the data in the table. Compound HF University Science Books presented by Macmillan Learning Melting point (°C) AHfus (kJ/mol) Boiling point (°C) AHvap (kJ/mol) -83.11 4.577 19.54 25.18 HCl -114.3 1.991 -84.9 17.53 HBr -86.96 2.406 -67.0 19.27 HI -50.91 2.871 Using the data in the table, calculate ASfus and ASvap for HCl. ASfus = ASvap = -35.38 21.16 Determine the entropy change when 6.10 mol HCl(g) condenses at atmospheric pressure. AS = J/(K. mol) J/(K⚫ mol) J/Karrow_forwardChoose the correct answer choice. Given the statement below, which choice best accounts for these observations?arrow_forwardksp CaCO3 3.36×10-9 Ca(OH)2 5.02×10-6arrow_forward
- Discuss some applications of simple distillation and steam distillation. Explain why you can use each method for the chosen applicationarrow_forwardDescribe the fractional distillation curve/grapharrow_forwardHow could melting point be used to determine if a compound is the same or different if the melting point is the same?arrow_forward
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