(a)
The moment about origin
(a)
Answer to Problem 3.19P
The moment about origin
Explanation of Solution
Write an expression to calculate the moment of the force at the origin
Here
Write an expression to represent force vector.
Here,
Write an expression to represent position vector of point
Here,
Write an expression to calculate the moment of force.
Conclusion:
Substitute
Thus, the moment about origin
(b)
The moment about origin
(b)
Answer to Problem 3.19P
The moment about origin
Explanation of Solution
Write an expression to calculate the moment of the force at the origin
Write an expression to represent force
Write an expression to represent position vector of point
Write an expression to calculate the moment of force.
Conclusion:
Substitute
Thus, the moment about origin
(c)
The moment about origin
(c)
Answer to Problem 3.19P
The moment about origin
Explanation of Solution
Write an expression to calculate the moment of the force at the origin
Write an expression to represent force vector.
Write an expression to represent position vector of point
Write an expression to calculate the moment of force.
Conclusion:
Substitute
Thus, the moment about origin is
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Chapter 3 Solutions
Vector Mechanics for Engineers: Statics and Dynamics
- The moment of the force F=1440-lb about the point O in Cartesian vector form is. F 1 ft> 4 ft' 2 ft 4 ft. Select one: O a. Mo = 2400j – 4800k а. O b. Mo = -200j + 400k O c. Mo = -200j – 400k O d. Mo = 200j + 400karrow_forward2. Determine the moment of a 90 N force about point C for the condition 0 = 15°. 600mm B A 90N 800mmarrow_forwardDetermine the moment about the origin of the 13 lb force whose line of action passes through points A( – 3, 6, – 6) and B( – 4, 4, 7) - M, = ( i + j+ k) lbarrow_forward
- The moment of the force F=180-lb about the point O in Cartesian vector form is. 1 ft 4 ft 2 ft 4 ft. Select one: O a. Mo = 300j – 600OK O b. Mo = -200j + 400k O . Mo = -200j – 400k O d. Mo = 2003 + 400karrow_forwardThe line of action of force F passes through points A and D. Find the component of the moment of force F about axis BC, given: F = 300 N, AX = 7 m, AY = 9 m, AZ = 9 m, BX = 6 m, BY = 6 m, BZ = 6 m, CX = 8 m, CY = 10 m, CZ = 9 m, DX = 4 m, DY = 5 m, DZ = 4 marrow_forwardThe moment of the 400 N force about point O is equal to. 0.2 m 0.4 m 30 F=400 Narrow_forward
- Given the Position vector Ř=i+0j+ k (m) and the Force vector F = 2i + 2j + 2k (kN) Determine the angle in degrees between the two vectors. Answer:arrow_forwardmy choice The moment of the force F=720-lb about the point O in Cartesian vector form is. 1 ft B 4 ft 2 ft AC A 4 ft Select one:arrow_forwardGiven the Position vector R= 5i + 4j + 3k (m) and the Force vector F = 4i – 5j+3k (kN) Determine the angle in degrees between the two vectors. Answer:arrow_forward
- The line of action of force F1 = 3TT N is passing through point A(+2,+3,+1) towards B(+5,+5,+4), while that of force F2 = 4QQ N is through point C(+3,+1, –1) towards D(–2, –3, –4). Use a right-handed coordinate system. a. Determine the moment of force F1 about the origin. b. Determine the moment of force F2 about the origin. c. Determine the magnitude of the resultant moment of forces F1 and F2 about segment OE. Point O is the origin and point E is at (+5,+5,–3). Where: Q=2 T=6arrow_forwardThe moment of the force F=480-lb about the point O in Cartesian vector form is. 1 ft> 4 ft 2ft 4 ft Select one:arrow_forwardF1 F2 a F3 A d. F4 E Consider the following values: - F5 a = 25 m;b = 5 m; c = 25 m; d = 5 m3; F1 = 5 kN; F2 = 6 kN; F3 = 7 kN; F4 8 kN; F5 9 kN; a = 30° , 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 78.4 kN.m b) 82.7 kN.m c) - 54.6 kN.m d) 92.9 kN.m e) 24.1 kN.m f) - 47.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 8.8 kN.m b) - 201.6 kN.m c) 131.6 kN.m d) - 128.9 kN.m e) 215.4 kN.m f) - 144.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) - 186.7 kN.m b) 211.1 kN.m c) -209.1 kN.m d) 127.9 kN.m e) -174.1 kN.m f) 35.3 kN.marrow_forward
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