Organic Chemistry: Structure and Function
Organic Chemistry: Structure and Function
8th Edition
ISBN: 9781319079451
Author: K. Peter C. Vollhardt, Neil E. Schore
Publisher: W. H. Freeman
bartleby

Concept explainers

Question
Book Icon
Chapter 3, Problem 20P

(a) H

Interpretation Introduction

Interpretation:The number of constitutional isomeric monohalogenated products that can form from butane should be determined.

Concept introduction: The carbon linked to one alkyl/carbon while other three are termed primary carbon. Thus, hydrogen linked to such carbon is referred as primary.

The carbon linked to two alkyl/carbons and two H is termed secondary carbon. Thus, hydrogen linked to such carbon is referred as secondary.

The carbon linked to three alkyl groups/carbons and one H is termed tertiary carbon. Thus, hydrogen linked to such carbon is referred as tertiary.

(b)

Interpretation Introduction

Interpretation:The number of constitutional isomeric monohalogenated products that can form from pentane should be determined.

Concept introduction:The carbon linked to one alkyl/carbon while other three H are termed primary carbon. Thus, hydrogen linked to such carbon is referred as primary.

The carbon linked to two alkyl/carbons and two H is termed secondary carbon. Thus, hydrogen linked to such carbon is referred as secondary.

The carbon linked to three alkyl groups/carbons and one H is termed tertiary carbon. Thus, hydrogen linked to such carbon is referred as tertiary.

(c)

Interpretation Introduction

Interpretation:The number of constitutional isomeric monohalogenated products that can form from 3methylpentane should be determined.

Concept introduction:The carbon linked to one alkyl/carbon while other three H are termed primary carbon. Thus, hydrogen linked to such carbon is referred as primary.

The carbon linked to two alkyl/carbons and two H is termed secondary carbon. Thus, hydrogen linked to such carbon is referred as secondary.

The carbon linked to three alkyl groups/carbons and one H is termed tertiary carbon. Thus, hydrogen linked to such carbon is referred as tertiary.

(d)

Interpretation Introduction

Interpretation:The number of constitutional isomeric monohalogenated products that can form from 1methylcyclopentane should be determined.

Concept introduction: The carbon linked to one alkyl / carbon while other two H are termed primary carbon. Thus, hydrogen linked to such carbon is referred as primary.

The carbon linked to two alkyl /carbons and one H is termed secondary carbon. Thus, hydrogen linked to such carbon is referred as secondary.

The carbon linked to three alkyl groups/carbons and no H is termed tertiary carbon. Thus, hydrogen linked to such carbon is referred as tertiary.

Blurred answer
Students have asked these similar questions
The energy difference between a tert-butyl group going from equatorial to axial in a cyclohexane is 18.3 kJ/mol. When two of the carbon atoms are replaced with oxygen atoms (molecule B) the energy difference between the two chair conformations drops to 5.9 kJ/mol. Explain this difference. (Hint: Consider what makes putting groups axial unfavorable).
Examine the ungraded ball-and-stick model to determine the three-dimensional structure of the molecule. On the corresponding 2D structure, draw one wedge bond and one dash bond over two existing bonds to indicate the same arrangement of atoms in space. The narrow part of each wedge-and-dash bond should be towards the same central carbon atom. Click on the three-dimensional molecular structure of (S)-1-chloro-2,3-dimethylbutane and drag to rotate it, or use the controls provided. 80 F3 $ 4 R F 000 COD F4 D V % 5 C T G MA F5 B OH 6 CL MacBook Pro Y Fo H & 7 N da F7 U * 00 8 M DII FO - Change two bonds to stereobonds. K Select Draw Rings More ////// 3 ( 9 H CH₂ */ CH₂ G DD F9 H O V H,C ) O command F10 P A C - H F11 Q2Q Cl { option + = F12 Erase = ] (1) dele
4.) For each of the following pairs, give the relationship between the two compounds. You many ignore conformational isomerism here, and any conformers may be considered to be identical compounds. H H. a. H H H. H F F CH, b. он CH3 он c. CH, он он CH3 d. CHs CH3 CH, CH3 CH, .CH2 Br H. H. Br CH3 CH3 Br Br f. CH, H. CH3 он H. H Br Br H. OH 2
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Cengage Learning