Essentials of Genetics (9th Edition) - Standalone book
9th Edition
ISBN: 9780134047799
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Chapter 3, Problem 13PDQ
When working out genetics problems in this and succeeding chapters, always assume that members of the P1 generation are homozygous, unless the information or data you are given require you to do otherwise.
How many different types of gametes can be formed by individuals of the following genotypes? What are they in each case? (a) AaBb, (b) AaBB, (c) AaBbCc, (d) AaBBcc, (e) AaBbcc, and (f) AaBbCcDdEe?
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When working out genetics problems in this and succeeding chapters, always assume that members of the P1 generation are homozygous, unless the information or data you are given require you to do otherwise.HOW DO WE KNOW? we focused on the Mendelian postulates, probability, and pedigree analysis. We also considered some of the methods and reasoning by which these ideas, concepts, and techniques were developed. On the basis of these discussions,
what answers would you propose to the followingquestion.
Question: Since experimental crosses are not performed in humans, how do we know how traits are inherited?
Question 1
What are the haploid genotypes of the gametes and frequencies/proportions of those gametes that can be formed in individuals of each of the following diploid genotypes? (DON’T do a cross. Just predict the different haploid gamete genotypes that could be produced by each diploid genotype below.) Proportions can be expressed in ratio form or fractional form.
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Mm Nn Rr ZZ
Question 6
Which of the Pedigree Diagrams below is most likely to show a family with Becker muscular dystrophy?
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Chapter 3 Solutions
Essentials of Genetics (9th Edition) - Standalone book
Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 - CASE STUDY | To test or not to test Thomas first...Ch. 3 -
CASE STUDY | To test or not to test
Thomas...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...
Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 -
When working out genetics problems in this and...Ch. 3 - When working out genetics problems in this and...Ch. 3 - Prob. 26PDQCh. 3 -
When working out genetics problems in this and...
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- 11:42 Cancel Markup Done Name: Date: Monohybrid practice problems In pea plants, the traits below exhibit the following dominance patterns: Recessive Expression: Wrinkled Dominant Expression: Round Purple |Yellow Inflated Green Trait: 1. Seed shape (R) 2. Flower color (P) 3. White Green |Constricted Yellow Terminal Short Color of seed coat (Y) Form of ripe pods (I) 4. 5. |Color of unripe pods (G) 6. Position of flowers (A) 7. Length of stem (T) Axial Tall Record the genetvnes f-Der-- = foltrawino deserintins (The first one has been done for you): а. дg A plant with yellow poás- EplancteOZygous for ereen pods N 0)e Owers С. A plant homozvaoue ycilow seeds A plant with white flowers TA piamt wilh areen seeds. Complete the Punnett Square showing the eress between a pea plant with pure round seeds and a plant with wrinkled seeds. Summanze the phenotypes and genotypes for the offspring. Genolynic PorcentadCS. Parental cross PhenolypicPerceniageS 3A pea plant with pure velow seeds is erossed…arrow_forwardPLease help, double and triple check your answers, im using this to study, these questions are NOT graded they are PRACTICE problems. Please help with all 4 parts of this question!!!!!!! A. Your maternal grandpa is colorblind but both your mom and dad are not affected. What are the chances of your sister being colorblind? What are the chances of your brother being colorblind? (Colorblindness is X-linked recessive) B. Regarding the problem above, if your sister’s husband is colorblind, what are the chances that their first son will be colorblind? C. Two genes, A and X, exhibit incomplete linkage. The frequency of each parental gamete (AX and ax) is 45%. What is the approximate frequency of the Ax gamete? D. There are three genes located in the gene order A--B--C on a chromosome. Would you expect the recombination frequency to be higher between A and B or A and C?arrow_forwardRule of Segregation Only one gene of the two alleles that you have is put into each gamete that you make. Alleles are located on homologous chromosomes, and since homologous chromosomes are segregated during meiosis, the genes are also segregated. Numerous gametes are formed during gamete production, and if the alleles are different (heterozygous), 50% of the gametes will carry one gene and 50% of the gametes will carry the other. When alleles are the same (homozygous), 100% of the gametes will carry the same allele. 1. A parent possesses two copies of each gene. When this parent passes on its alleles for a gene, how many does it contribute to each of the offspring? 2. How many copies of a gene does the other parent contribute to each offspring? 3. How many copies of each gene for the trait does each offspring receive?arrow_forward
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- QUESTION 6 In Drosophila, sepia eyes (se) and stubble bristles (sb) are recessive to the wildtype eyes and bristles (se* and sb+). A female heterozygous for both genes was test crossed to a male homozygous recessive for both genes. The progeny of this cross are given below: Phenotypes wildtype eyes and wildtype bristles (set, sbt) # of Progeny 334 widltype eyes and stubble bristles (set, sb) 162 sepia eyes and wildtype bristles (se, sb+) 158 sepia eyes and stubble bristles (se, sb) 346 What is the genetic distance (in map units) between these two genes? Are the alleles in the heterozygous female in the cis (coupling) or trans (repulsion) conformation? Are the two genes in this problem unlinked, completely linked or incompletely linked?arrow_forwardPart 4: Answer each of the following questions. You must include a Punnett square to support each answer!! 18. In fruit flies, brown bodies (B) are dominant to black bodies (b) Cross a black fruit fly with a heterozygous fruit fly. Determine the phenotypic and genotypic ratios of their potential offspring. "B b Brown B Black B bb Name: Linda Rivas b Bb B/BB Bb 19. In humans, dimples (D) are dominant to no dimples (d). Cross a woman who is homozygous dominant with a man who is homozygous recessive. Determine the phenotypic and genotypic ratios of their potential offspring. Same Dd x dd dd:Dd: DD 2 2 O d Dd d Dd R Heredity Unit RR dd TTT tTt dd 20. In tomatoes, red fruit (R) is dominant to yellow fruit (r). Cross a homozygous dominant fruit with a heterozygous fruit. What percentage of their offspring will have yellow fruit? R RR x Rr Red Fruit RR Bb X bb Bb: bb: BB 2 1 f Ffff f Ff ff RR: Rrirr r Rr 2 2 21. In pea plants, tall plants are dominant to dwarf plants. Two heterozygous plants…arrow_forwardWelcome, Chanel Samuels! Connection Status: Good All changes saved Question 2 of 12 - Submit Test 2021 Meiosis Genetics Common Assessment Question: 1-2 A pet rabbit named Sparky has a dark coat (D, the dominant allele) and was mated with an albino female rabbit named Lucy (d, the recessive allele). A litter of six offspring were born, all with dark coats. Lucy was then mated with a different dark coated rabbit named Elwood. Some of Elwood's and Lucy's litter were dark coated and other were albinos. What is the most probable genotype for Sparky, Lucy and Elwood? O Sparky - Dd Lucy - dd Elwood - DD O Sparky - DD Lucy- Dd Elwood - Dd O Sparky - Dd Lucy - dd Elwood - dd O Sparky - DD Lucy - dd Elwood - Dd Next Previous 11:01 AM O Type here to search 1/19/2021 prt sc deleh insert EGOarrow_forward
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