The purine and pyrimidine ring structures should be drawn demonstrating the metabolic sources of all the atoms in the ring. Concept Introduction : Heterocyclic aromatic organic compound purine has a pyrimidine ring fused to an imidazole ring. Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms, whereas pyrimidine is a six-membered single ring structure.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 26, Problem 1P

Interpretation Introduction

Interpretation:

The purine and pyrimidine ring structures should be drawn demonstrating the metabolic sources of all the atoms in the ring.

Concept Introduction:

Heterocyclic aromatic organic compound purine has a pyrimidine ring fused to an imidazole ring. Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms, whereas pyrimidine is a six-membered single ring structure.

Expert Solution & Answer

Explanation of Solution

Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms. In this structure, carbon-2 and carbon-8 are obtained from N¹⁰ -formyl −H₄folate and nitrogen-3 and nitrogen-9 are obtained from glutamine. There is no metabolic relation between purine and pyrimidines. Purine and Pyrimidines both have a different process for the synthesis and for the degradation. These both process of degradation and synthesis occur in all organisms. Structure of the purine is given below-

Biochemistry, Chapter 26, Problem 1P , additional homework tip 1

Pyrimidine is a six-membered single ring structure. It has two nitrogen and four carbon atoms. Nitrogen-3 and carbon-2 are obtained from carbamoyl phosphate. Carbon-4,5,6 and nitrogen-1 are obtained from aspartate. Structure for the pyrimidine is given below-

Biochemistry, Chapter 26, Problem 1P , additional homework tip 2

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

In many biochemical reactions which involves the formation of an enolate intermediate, the carbonyl oxygen of the substrate is coordinated to a divalent metal ion (usually zinc or magnesium) in the active site. Explain with structural drawings, how this ion-dipole interactions affect the acidity of the a-protons?

Histidine is frequently used as a general acid or base in enzyme catalysis. Considering the pKa value of the side chain, suggest a reason why is this so?

Draw structural formulas for the products obtained when the tripeptide Thr-Leu-Ile undergoes complete hydrolysis under acidic conditions

Answer 2

Question

Chapter 26, Problem 1P

Interpretation Introduction

Interpretation:

The purine and pyrimidine ring structures should be drawn demonstrating the metabolic sources of all the atoms in the ring.

Concept Introduction:

Heterocyclic aromatic organic compound purine has a pyrimidine ring fused to an imidazole ring. Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms, whereas pyrimidine is a six-membered single ring structure.

Expert Solution & Answer

Explanation of Solution

Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms. In this structure, carbon-2 and carbon-8 are obtained from N¹⁰ -formyl −H₄folate and nitrogen-3 and nitrogen-9 are obtained from glutamine. There is no metabolic relation between purine and pyrimidines. Purine and Pyrimidines both have a different process for the synthesis and for the degradation. These both process of degradation and synthesis occur in all organisms. Structure of the purine is given below-

Biochemistry, Chapter 26, Problem 1P , additional homework tip 1

Pyrimidine is a six-membered single ring structure. It has two nitrogen and four carbon atoms. Nitrogen-3 and carbon-2 are obtained from carbamoyl phosphate. Carbon-4,5,6 and nitrogen-1 are obtained from aspartate. Structure for the pyrimidine is given below-

Biochemistry, Chapter 26, Problem 1P , additional homework tip 2

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 26, Problem 1P

Interpretation Introduction

Interpretation:

The purine and pyrimidine ring structures should be drawn demonstrating the metabolic sources of all the atoms in the ring.

Concept Introduction:

Heterocyclic aromatic organic compound purine has a pyrimidine ring fused to an imidazole ring. Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms, whereas pyrimidine is a six-membered single ring structure.

Expert Solution & Answer

Explanation of Solution

Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms. In this structure, carbon-2 and carbon-8 are obtained from N¹⁰ -formyl −H₄folate and nitrogen-3 and nitrogen-9 are obtained from glutamine. There is no metabolic relation between purine and pyrimidines. Purine and Pyrimidines both have a different process for the synthesis and for the degradation. These both process of degradation and synthesis occur in all organisms. Structure of the purine is given below-

Biochemistry, Chapter 26, Problem 1P , additional homework tip 1

Pyrimidine is a six-membered single ring structure. It has two nitrogen and four carbon atoms. Nitrogen-3 and carbon-2 are obtained from carbamoyl phosphate. Carbon-4,5,6 and nitrogen-1 are obtained from aspartate. Structure for the pyrimidine is given below-

Biochemistry, Chapter 26, Problem 1P , additional homework tip 2

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 26, Problem 1P

Interpretation Introduction

Interpretation:

The purine and pyrimidine ring structures should be drawn demonstrating the metabolic sources of all the atoms in the ring.

Concept Introduction:

Heterocyclic aromatic organic compound purine has a pyrimidine ring fused to an imidazole ring. Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms, whereas pyrimidine is a six-membered single ring structure.

Expert Solution & Answer

Explanation of Solution

Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms. In this structure, carbon-2 and carbon-8 are obtained from N¹⁰ -formyl −H₄folate and nitrogen-3 and nitrogen-9 are obtained from glutamine. There is no metabolic relation between purine and pyrimidines. Purine and Pyrimidines both have a different process for the synthesis and for the degradation. These both process of degradation and synthesis occur in all organisms. Structure of the purine is given below-

Biochemistry, Chapter 26, Problem 1P , additional homework tip 1

Pyrimidine is a six-membered single ring structure. It has two nitrogen and four carbon atoms. Nitrogen-3 and carbon-2 are obtained from carbamoyl phosphate. Carbon-4,5,6 and nitrogen-1 are obtained from aspartate. Structure for the pyrimidine is given below-

Biochemistry, Chapter 26, Problem 1P , additional homework tip 2

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 26, Problem 1P

Interpretation Introduction

Interpretation:

The purine and pyrimidine ring structures should be drawn demonstrating the metabolic sources of all the atoms in the ring.

Concept Introduction:

Heterocyclic aromatic organic compound purine has a pyrimidine ring fused to an imidazole ring. Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms, whereas pyrimidine is a six-membered single ring structure.

Expert Solution & Answer

Explanation of Solution

Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms. In this structure, carbon-2 and carbon-8 are obtained from N¹⁰ -formyl −H₄folate and nitrogen-3 and nitrogen-9 are obtained from glutamine. There is no metabolic relation between purine and pyrimidines. Purine and Pyrimidines both have a different process for the synthesis and for the degradation. These both process of degradation and synthesis occur in all organisms. Structure of the purine is given below-

Biochemistry, Chapter 26, Problem 1P , additional homework tip 1

Pyrimidine is a six-membered single ring structure. It has two nitrogen and four carbon atoms. Nitrogen-3 and carbon-2 are obtained from carbamoyl phosphate. Carbon-4,5,6 and nitrogen-1 are obtained from aspartate. Structure for the pyrimidine is given below-

Biochemistry, Chapter 26, Problem 1P , additional homework tip 2

Answer 6

Chapter 26, Problem 1P

Interpretation Introduction

Interpretation:

The purine and pyrimidine ring structures should be drawn demonstrating the metabolic sources of all the atoms in the ring.

Concept Introduction:

Heterocyclic aromatic organic compound purine has a pyrimidine ring fused to an imidazole ring. Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms, whereas pyrimidine is a six-membered single ring structure.

Expert Solution & Answer

Explanation of Solution

Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms. In this structure, carbon-2 and carbon-8 are obtained from N¹⁰ -formyl −H₄folate and nitrogen-3 and nitrogen-9 are obtained from glutamine. There is no metabolic relation between purine and pyrimidines. Purine and Pyrimidines both have a different process for the synthesis and for the degradation. These both process of degradation and synthesis occur in all organisms. Structure of the purine is given below-

Biochemistry, Chapter 26, Problem 1P , additional homework tip 1

Pyrimidine is a six-membered single ring structure. It has two nitrogen and four carbon atoms. Nitrogen-3 and carbon-2 are obtained from carbamoyl phosphate. Carbon-4,5,6 and nitrogen-1 are obtained from aspartate. Structure for the pyrimidine is given below-

Biochemistry, Chapter 26, Problem 1P , additional homework tip 2

Answer 7

Chapter 26, Problem 1P

Interpretation Introduction

Interpretation:

The purine and pyrimidine ring structures should be drawn demonstrating the metabolic sources of all the atoms in the ring.

Concept Introduction:

Heterocyclic aromatic organic compound purine has a pyrimidine ring fused to an imidazole ring. Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms, whereas pyrimidine is a six-membered single ring structure.

Answer 8

Expert Solution & Answer

Explanation of Solution

Purine is represented in a double-ring structure which has four-nitrogen and five-carbon atoms. In this structure, carbon-2 and carbon-8 are obtained from N¹⁰ -formyl −H₄folate and nitrogen-3 and nitrogen-9 are obtained from glutamine. There is no metabolic relation between purine and pyrimidines. Purine and Pyrimidines both have a different process for the synthesis and for the degradation. These both process of degradation and synthesis occur in all organisms. Structure of the purine is given below-

Biochemistry, Chapter 26, Problem 1P , additional homework tip 1

Pyrimidine is a six-membered single ring structure. It has two nitrogen and four carbon atoms. Nitrogen-3 and carbon-2 are obtained from carbamoyl phosphate. Carbon-4,5,6 and nitrogen-1 are obtained from aspartate. Structure for the pyrimidine is given below-

Biochemistry, Chapter 26, Problem 1P , additional homework tip 2

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Ch. 26 - Prob. 1P Ch. 26 - Prob. 2P Ch. 26 - Allosteric Regulation of Purine and Pyrimidine...Ch. 26 - Inhibition of Purine and Pyrimidine Metabolism by...Ch. 26 - Prob. 5P Ch. 26 - Allosteric Regulation of Ribonucleotide Reductase...Ch. 26 - Prob. 7P Ch. 26 - Prob. 8P Ch. 26 - Prob. 9P Ch. 26 - Prob. 10P

Explanation of Solution

Want to see more full solutions like this?

Chapter 26 Solutions