COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 24, Problem 80QAP
To determine
What is the farthest distance that objects can be in order for Andrea to see them clearly without her glass?
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•42 Figure 34-40 gives the lateral
magnification m of an object versus
the object distance p from a lens as
the object is moved along the cen-
tral axis of the lens through a range
of values for p out to p, = 20.0 cm.
What is the magnification of the ob-
ject when the object is 35 cm from
the lens?
E 0.5
p (cm)
Figure 34-40 Problem 42.
•8 An object is placed against the
center of a spherical mirror and
then moved 70 cm from it along the
central axis as the image distance i is
measured. Figure 34-36 gives i
versus object distance p out to P. =
40 cm. What is i for p = 70 cm?
400
-400
Sam purchases +2.0-D eyeglasses which correct his faulty vision to put his near point at 25
cm. (Assume he wears the lenses 2.0 cm from his eyes.) Solve Parts 1A, 1B, 1C.
Question 2
1A) Calculate the focal length of Sam's glasses, in meters.
Question 3
1B) Calculate Sam's near point without glasses, in meters.
Chapter 24 Solutions
COLLEGE PHYSICS
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A laboratory (astronomical) telescope is used to view a scale that is 300 cm from the objective, which has a focal length of 20.0 cm; the eyepiece has a focal length of 2.00 cm. Calculate the angular magnification when the telescope is adjusted for minimum eyestrain. Note: The object is not at infinity, so the simple expression m = fo/fe is not sufficiently accurate for this problem. Also, assume small angles, so that tan = .arrow_forwardA cataract-impaired lens in an eye may be surgically removed and replaced by a manufactured lens. The focal length required for the new lens is determined by the lens-lo-retina distance, which is measured by a sonar-like device, and by the requirement that the implant provide for correct distance vision. (a) If the distance from lens to retina is 22.4 mm, calculate the power of the implanted lens in diopters. (b) Since there is no accommodation and the implant allows for correct distance vision, a corrective lens for close work or reading must be used. Assume a reading distance of 33.0 cm, and calculate the power of the lens in the reading glasses.arrow_forwardA certain childs near point is 10.0 cm; her far point (with eyes relaxed) is 125 cm. Each eye lens is 2.00 cm from the retina. (a) Between what limits, measured in diopters, does the power of this lenscornea combination vary? (b) Calculate the power of the eyeglass lens the child should use for relaxed distance vision. Is the lens converging or diverging?arrow_forward
- The accommodation limits for Nearsighted Nicks eyes are 18.0 cm and 80.0 cm. When he wears his glasses, he is able to see faraway objects clearly. At what minimum distance is he able to see objects clearly?arrow_forwardHow far from the lens must the film in a camera be, if the lens has a 35.0 mm local length and is being used to photograph a flower 75.0 cm away? Explicitly show how you follow the steps in the ProblemSolving Strategy for lenses.arrow_forwardDuring LASIK eye surgery (laser-assisted in situ keratomileusis), the shape of the cornea is modified by vaporizing some of its material. If the surgery is performed to correct for nearsightedness, how does the cornea need to be reshaped?arrow_forward
- In Example 25.7, the magnification of a book held 7.50 cm from a 10.0 cm focal length lens was found to be 3.00. (a) Find the magnification for the book when it is held 8.50 cm from the magnifier. (b) Do the same for when it is held 9.50 cm from the magnifier. (c) Comment on the trend in m as the object distance increases as in these two calculations.arrow_forwardA simple model of the human eye ignores its lens entirely. Most of what the eye does to light happens at the outer surface of the transparent cornea. Assume that this surface has a radius of curvature of 6.00 mm and that the eyeball contains just one fluid with a refractive index of 1.40. Prove that a very distant object will be imaged on the retina, 21.0 mm behind the cornea. Describe the image.arrow_forwardA severely myopic patient has a far point of 5.00 cm. By how many diopters should the power of his eye be reduced in laser vision correction to obtain normal distant vision for him?arrow_forward
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