Concept explainers
The circuit in Figure 24-2 is connected to a 60-Hz line. The apparent power in the circuit is 48.106 VA. The resistor has a resistance of 12
The missing values in the table.
Answer to Problem 3PP
ET = 23.99 V | ER = 23.99 V | EL = 23.99 V | EC = 23.99 V |
IT = 2.004 A | IR = 1.999 A | IL =0.399 A | IC =0.533 A |
Z = 11.973 Ω | R = 12 Ω | XL = 60 Ω | XC = 45 Ω |
VA = 48.106 | P = 47.96 W | VARSL = 9.575 | VARSC = 12.791 |
PF = 99.725 % | ∠θ = 4.25° | L = 0.159 H | C = 58.94 µF |
Explanation of Solution
Given data :
The value of the inductor is given by,
The value of the capacitor is given by,
The impedance of the parallel circuit is given as,
To determine the value of total voltage across the parallel R-L-C circuit,
Since the circuit is parallel R-L-C circuit,
The total current flowing through the parallel RLC circuit will be,
The current flowing through the resistor in the parallel RLC circuit will be,
The current flowing through the inductor in the parallel RLC circuit will be,
The current flowing through the capacitor in the parallel RLC circuit will be,
The true power in the parallel circuit will be,
The reactive power of the inductor is given by,
The reactive power of the capacitor is given by,
The Power factor of the circuit is calculated as,
Power factor angle θ will be,
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Chapter 24 Solutions
Delmar's Standard Textbook Of Electricity
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