Chapter 2, Problem 24E

Interpretation Introduction

(a)

Interpretation:

The following metric-English conversions are to be performed.

Concept introduction:

Metric system is a measurement system which has units of meter, liter and gram as the units for measuring length, volume and mass. Adoption of the metric system as a universal system of measurement has been resisted by several countries. In science, measurements are regularly recorded in metric units.

Answer to Problem 24E

The value of $\text{800}\text{m}$ is equal to $\text{875}\text{.27}\text{yards}$.

Explanation of Solution

The value of $\text{1}\text{yard}=\text{0}\text{.914}\text{m}$.

The conversion factor can be written as $\frac{\text{1}\text{yard}}{\text{0}\text{.914}\text{m}}$.

The conversion of $\text{800}\text{m}$ into $\text{yard}$ is given as,

$\begin{array}{rll}\text{800}\text{m}& =& \frac{\text{1}\text{yard}}{\text{0}\text{.914}\text{m}}\text{×800}\text{m}\\ & =& \text{875}\text{.27}\text{yards}\end{array}$

Conclusion

The value of $\text{800}\text{m}$ is equal to $\text{875}\text{.27}\text{yards}$.

Interpretation Introduction

(b)

Interpretation:

The following metric-English conversions are to be performed.

Concept introduction:

Metric system is a measurement system which has units of meter, liter and gram as the units for measuring length, volume and mass. Adoption of the metric system as a universal system of measurement has been resisted by several countries. In science, measurements are regularly recorded in metric units.

Answer to Problem 24E

The value of $\text{0}\text{.375}\text{kg}$ is equal to $0.826\text{lb}$.

Explanation of Solution

The value of $\text{1}\text{kg}=\text{1000}\text{g}$.

The conversion factor can be written as $\frac{\text{1000}\text{g}}{\text{1}\text{kg}}$.

The conversion of $\text{0}\text{.375}\text{kg}$ into $\text{g}$ is given as,

$\begin{array}{rll}\text{0}\text{.375}\text{kg}& =& \frac{\text{1000}\text{g}}{\text{1}\text{kg}}\text{×0}\text{.375}\text{kg}\\ & =& \text{375}\text{g}\end{array}$

The value of $\text{1}\text{lb}=\text{454}\text{g}$.

The conversion factor can be written as $\frac{\text{1}\text{lb}}{\text{454}\text{g}}$.

The conversion of $\text{375}\text{g}$ into $\text{lb}$ is given as,

$\begin{array}{rll}\text{375}\text{g}& =& \frac{\text{1}\text{lb}}{\text{454}\text{g}}\text{×375}\text{g}\\ & =& 0.826\text{lb}\end{array}$

Conclusion

The value of $\text{0}\text{.375}\text{kg}$ is equal to $0.826\text{lb}$.

Interpretation Introduction

(c)

Interpretation:

The following metric-English conversions are to be performed.

Concept introduction:

Metric system is a measurement system which has units of meter, liter and gram as the units for measuring length, volume and mass. Adoption of the metric system as a universal system of measurement has been resisted by several countries. In science, measurements are regularly recorded in metric units.

Answer to Problem 24E

The value of $\text{1250}\text{mL}$ is equal to $0.3302\text{gallon}$.

Explanation of Solution

The value of $\text{1}\text{gallon}=\text{3785}\text{.41}\text{mL}$.

The conversion factor can be written as $\frac{1\text{gallon}}{3785.41\text{mL}}$.

The conversion of $\text{1250}\text{mL}$ into $\text{gallons}$ is given as,

$\begin{array}{rll}\text{1250}\text{mL}& =& \frac{1\text{gallon}}{3785.41\text{mL}}\text{×1250}\text{mL}\\ & =& 0.3302\text{gallon}\end{array}$.

Conclusion

The value of $\text{1250}\text{mL}$ is equal to $0.3302\text{gallon}$.

Interpretation Introduction

(d)

Interpretation:

The following metric-English conversions are to be performed.

Concept introduction:

Metric system is a measurement system which has units of meter, liter and gram as the units for measuring length, volume and mass. Adoption of the metric system as a universal system of measurement has been resisted by several countries. In science, measurements are regularly recorded in metric units.

Answer to Problem 24E

The value of $\text{1}\text{.52}\times {\text{10}}^{\text{3}}\text{ds}$ is equal to $2.533\text{min}$.

Explanation of Solution

The value of $\text{1}\text{s}=\text{10}\text{ds}$.

The conversion factor can be written as $\frac{\text{1}\text{s}}{\text{10}\text{ds}}$.

The conversion of $\text{1}\text{.52}\times {\text{10}}^{\text{3}}\text{ds}$ into $\text{s}$ is given as,

$\begin{array}{rll}\text{1}\text{.52}\times {\text{10}}^{\text{3}}\text{ds}& =& \frac{\text{1}\text{s}}{\text{10}\text{ds}}\times \text{1}\text{.52}\times {\text{10}}^{\text{3}}\text{ds}\\ & =& \text{1}\text{.52}\times {\text{10}}^{\text{2}}\text{s}\end{array}$.

The value of $\text{1}\min =\text{60}\text{s}$.

The conversion factor can be written as $\frac{1\min }{60\text{s}}$.

The conversion of $\text{1}\text{.52}\times {\text{10}}^{\text{2}}\text{s}$ into $\text{min}$ is given as,

$\begin{array}{rll}\text{1}\text{.52}\times {\text{10}}^{\text{2}}\text{s}& =& \frac{1\min }{60\text{s}}\times \text{1}\text{.52}\times {\text{10}}^{\text{2}}\text{s}\\ & =& 2.533\text{min}\end{array}$.

Conclusion

The value of $\text{1}\text{.52}\times {\text{10}}^{\text{3}}\text{ds}$ is equal to $2.533\text{min}$.