Fundamentals of Electric Circuits
6th Edition
ISBN: 9780078028229
Author: Charles K Alexander, Matthew Sadiku
Publisher: McGraw-Hill Education
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Chapter 18, Problem 31P
(a)
To determine
Find the input response
(b)
To determine
Find the input response
(c)
To determine
Find the input response
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O 180
The output of a system is y(t) = 3x(t-2), where x(t-1) is the input. The system impulse response is:
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Chapter 18 Solutions
Fundamentals of Electric Circuits
Ch. 18.2 - Prob. 1PPCh. 18.2 - Prob. 2PPCh. 18.2 - Prob. 3PPCh. 18.3 - Prob. 5PPCh. 18.3 - Prob. 6PPCh. 18.4 - Prob. 7PPCh. 18.4 - Prob. 8PPCh. 18.5 - (a) Calculate the total energy absorbed by a 1-...Ch. 18.5 - Prob. 10PPCh. 18.8 - If a 2-MHz carrier is modulated by a 4-kHz...
Ch. 18.8 - Prob. 12PPCh. 18 - Prob. 1RQCh. 18 - Prob. 2RQCh. 18 - The inverse Fourier transform of ej2+j is (a) e2t...Ch. 18 - Prob. 4RQCh. 18 - Prob. 5RQCh. 18 - Prob. 6RQCh. 18 - Prob. 7RQCh. 18 - Prob. 8RQCh. 18 - A unit step current is applied through a 1-H...Ch. 18 - Prob. 10RQCh. 18 - Prob. 1PCh. 18 - Prob. 2PCh. 18 - Prob. 3PCh. 18 - Prob. 4PCh. 18 - Prob. 5PCh. 18 - Prob. 6PCh. 18 - Prob. 7PCh. 18 - Prob. 8PCh. 18 - Prob. 9PCh. 18 - Prob. 10PCh. 18 - Prob. 11PCh. 18 - Prob. 12PCh. 18 - Prob. 14PCh. 18 - Prob. 15PCh. 18 - Prob. 16PCh. 18 - Prob. 17PCh. 18 - Given that F=Fft, prove the following results,...Ch. 18 - Prob. 19PCh. 18 - Prob. 21PCh. 18 - Prob. 22PCh. 18 - Prob. 23PCh. 18 - Prob. 24PCh. 18 - Prob. 25PCh. 18 - Prob. 26PCh. 18 - Prob. 27PCh. 18 - Prob. 28PCh. 18 - Prob. 29PCh. 18 - For a linear system with input x(t) and output...Ch. 18 - Prob. 31PCh. 18 - Prob. 32PCh. 18 - Prob. 33PCh. 18 - Prob. 34PCh. 18 - Prob. 35PCh. 18 - Prob. 36PCh. 18 - Prob. 37PCh. 18 - Prob. 38PCh. 18 - Prob. 39PCh. 18 - Prob. 40PCh. 18 - Prob. 41PCh. 18 - Prob. 42PCh. 18 - Prob. 43PCh. 18 - Prob. 44PCh. 18 - Prob. 45PCh. 18 - Prob. 46PCh. 18 - Prob. 47PCh. 18 - Prob. 49PCh. 18 - Prob. 51PCh. 18 - Prob. 52PCh. 18 - Prob. 53PCh. 18 - Prob. 54PCh. 18 - Prob. 55PCh. 18 - Prob. 56PCh. 18 - Prob. 57PCh. 18 - Prob. 58PCh. 18 - Prob. 59PCh. 18 - Prob. 60PCh. 18 - Prob. 61PCh. 18 - Prob. 62PCh. 18 - Prob. 63PCh. 18 - Prob. 64PCh. 18 - Prob. 65PCh. 18 - Prob. 66PCh. 18 - Given a signal g(t) = sinc(200 t), find the...Ch. 18 - Prob. 68CPCh. 18 - Prob. 69CP
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- 1. Use the convolution integral to compute the convolution of y(t) = x(t) * h(t) for each pair of r(t) and h(t) listed below. In each case, there is no initial energy in the system before the input becomes active. a x(t) bx(t) C x(t) dx(t) = = u(t - 2), h(t) e-3t sin (6t) u(t) 3e-2t [u(t) u(t-3)], h(t) = (t − 1) [u(t) – u(t — 6)] tu(t)-2(t-3)u(t-3) + (t-6)u(t-6), h(t) = u(t-1)-u(t-7) u(t) + 2u(t-4) - 3u(t-6), h(t): = u(t-2) - u(t - 7)arrow_forward5. Derive an equation for the output voltage, vo(t), in terms of vi(t) and v₂(t). M + vi(t) R₁ M + V₂(t) I + R₂ C V.arrow_forwardThe convolution of x(t) and n(t) (shown below, A is 1 and B is 6) in the interval -6arrow_forwardThe output of a system is y(t) = 3f (t - 2), where 6(t-1) is the input. The system impulse response is: Select one: O h(t) = 3f (t – 1) O h(t) = 3u(t) h(t) = 38(t – 1) O h(t) = 3f (t + 1)arrow_forwardO h(t - 2) The output of a system is y(t) = 3f(t – 2). where 38(t-4) is the input. The system impulse response is: Select one: O h(t) = 3f(t+2) %3D O h(t) = 3u(t + 1) O h(t) = f(t – 2) O h(t) = f(t+2) %3D An LTI system has an impulse response: h(t) e 4u(t – 3) This system is: Select one: O Not causal but stablearrow_forwardJetermine the output signal y(t) for the given system such that the input signal x(t) and the impulse response h(t) of the system is as given below. x(t) h(t) x(t) = 6u(t + 3): h(t) = 4u(t + 8): u(t): Unit Step Function %3D Show all the steps for your calculations.arrow_forwardThe output of a system is y(t) = 3f(t – 2), where 6(t-1) is %3D the input. The system impulse response is: Select one: O h(t) = 3f(t – 1) h(t) = 36(t – 1) h(t) = 3f(t+ 1) %3D h(t) = 3u(t)arrow_forwardCompute the convolution y(t) = x(t) * h(t) of the following pairs of signals 1, 0≤t < 1 -1, 1≤t<2. 0, otherwise Determine the output y(t) via convolution of x(t) and h(t). h(t) = e-t[u(t) — u(t – 2)] and x(t)arrow_forwardConvolve the following continuous-time signals, assuming that Th=1 sec, and T₁ =1.5 sec Plot the result 2T, ht -1 x(1) T h(t) Tarrow_forward4. The input to a system with impulse response h(t) is x(t), both functions are given below. Find the output of the system. -21 h(t)=5e*u(t) x(1) =u (t)arrow_forwardb)find the following convolution y(t)=u(t) * 8(t – 3) – u(t – 4) * 8(t + 1) теаns convolutionarrow_forwarda)A system with impulse response h(t) as below , Is the system BIBO stable (1.5) u(t – 1) h(t) = t2arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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