21st Century Astronomy
6th Edition
ISBN: 9780393428063
Author: Kay
Publisher: NORTON
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Chapter 14, Problem 44QP
To determine
The time period up to which sun would emit energy.
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Given the Sun's present rate of energy generation (i.e. its present luminosity), how long will the Sun's energy source last (from beginning to end)? Answer in years.
Let's examine how we know that the Sun cannot power itself by chemical reactions. Using the fact that an average chemical reaction between two atoms releases 1.6×10-19 J of energy, estimate how long the Sun could emit energy at its current luminosity. Compare that estimate to the known age of Earth.
THIS WAS ALREADY ASKED; just need the question labeled 1.*****
If the nuclear fusion reaction of converting 4 H → He occurs at an efficiency of 0.7%, and that mass is converted into energy according to the equation E = mc2, then estimate the Main Sequence lifetime of the Sun (spectral type G2) in years if the luminosity of the Sun is 3.83 × 1033 ergs s−1. Assume the Sun’s core (10% of the total mass) is converted from H into He. The Sun’s mass is M⊙ = 1.9891 × 1033 g.
Make the same assumptions as the previous problem; however, now estimate the lifetime of star whose spectral type is B0 if the total mass of the star is M = 17.5M⊙, and it has a total luminosity L = 5.2×104L⊙. How does the Main Sequence lifetime of the B0 type star compare to the Main Sequence lifetime you calculated for of the Sun?
Chapter 14 Solutions
21st Century Astronomy
Ch. 14.1 - Prob. 14.1ACYUCh. 14.1 - Prob. 14.1BCYUCh. 14.2 - Prob. 14.2CYUCh. 14.3 - Prob. 14.3CYUCh. 14.4 - Prob. 14.4CYUCh. 14 - Prob. 1QPCh. 14 - Prob. 2QPCh. 14 - Prob. 3QPCh. 14 - Prob. 4QPCh. 14 - Prob. 5QP
Ch. 14 - Prob. 6QPCh. 14 - Prob. 7QPCh. 14 - Prob. 8QPCh. 14 - Prob. 9QPCh. 14 - Prob. 10QPCh. 14 - Prob. 11QPCh. 14 - Prob. 12QPCh. 14 - Prob. 13QPCh. 14 - Prob. 14QPCh. 14 - Prob. 15QPCh. 14 - Prob. 16QPCh. 14 - Prob. 17QPCh. 14 - Prob. 18QPCh. 14 - Prob. 19QPCh. 14 - Prob. 20QPCh. 14 - Prob. 21QPCh. 14 - Prob. 22QPCh. 14 - Prob. 23QPCh. 14 - Prob. 24QPCh. 14 - Prob. 25QPCh. 14 - Prob. 26QPCh. 14 - Prob. 27QPCh. 14 - Prob. 28QPCh. 14 - Prob. 29QPCh. 14 - Prob. 30QPCh. 14 - Prob. 31QPCh. 14 - Prob. 34QPCh. 14 - Prob. 35QPCh. 14 - Prob. 36QPCh. 14 - Prob. 37QPCh. 14 - Prob. 38QPCh. 14 - Prob. 39QPCh. 14 - Prob. 40QPCh. 14 - Prob. 41QPCh. 14 - Prob. 42QPCh. 14 - Prob. 43QPCh. 14 - Prob. 44QPCh. 14 - Prob. 45QP
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- The total luminosity of the Sun is 4e26 Watts.a) What is the mass (in kg) that the Sun loses each second due to the conversion of nuclearbinding energy into radiation?b) The Sun has a total mass of 2e30kg and will live for 1e10 years. What fraction of theSun’s mass will be consumed in its lifetime due to nuclear fusion? Don’t forget that Wattsare measured in seconds.c) One of the interactions that takes place in the Sun’s core is the production of Deuterium.Two protons come together and one converts into a neutron. The mass of each proton is938.27209 MeV/c2. The mass of the deuteron is 1875.61294 MeV. How much energy isreleased during this process?d) During this process, the new nucleus releases two other particles. The initial particles,two protons, each have a quantum spin of +1/2 and an electric charge of +1. Now you havea proton, a neutron, a particle X, and particle Y. If the particle X has no electric charge,what is the electric charge of particle Y? If particle Y has a spin of…arrow_forwardThe Sun’s luminosity (or power) is 4 x 1026 Watts (=J/s). How many kilograms of hydrogen must be fused every second to maintain this luminosity? (hint: work backwards from the energy per second to the mass released to the amount of hydrogen required, using the results from the previous question.) The Sun’s mass is ~2x1030 kg. If 10% of this is Hydrogen available in the core, how long will the Sun be able to continue fusing hydrogen at this rate? This is considered the Sun's "lifetime". If the Sun is 4.6 billion years old (and assuming it's power output is constant), how many years does it have left?arrow_forwardIf the nuclear fusion reaction of converting 4 H → He occurs at an efficiency of 0.7%, and that mass is converted into energy according to the equation E = mc2, then estimate the Main Sequence lifetime of the Sun (spectral type G2) in years if the luminosity of the Sun is 3.83 × 1033 ergs s−1. Assume the Sun’s core (10% of the total mass) is converted from H into He. The Sun’s mass is M⊙ = 1.9891 × 1033 g.arrow_forward
- Why do you suppose so great a fraction of the Sun’s energy comes from its central regions? Within what fraction of the Sun’s radius does practically all of the Sun’s luminosity originate (see Figure 16.16)? Within what radius of the Sun has its original hydrogen been partially used up? Discuss what relationship the answers to these questions bear to one another. Figure 16.16 shows how the temperature, density, rate of energy generation, and composition vary from the center of the Sun to its surface.arrow_forwardShow that the statement that 92% of the Sun’s atoms are hydrogen is consistent with the statement that 73% of the Sun’s mass is made up of hydrogen, as found in Table 15.2. (Hint: Make the simplifying assumption, which is nearly correct, that the Sun is made up entirely of hydrogen and helium.)arrow_forwardModels of the Sun indicate that only about 10% of the total hydrogen in the Sun will participate in nuclear reactions, since it is only the hydrogen in the central regions that is at a high enough temperature. Use the total energy radiated per second by the Sun, 3.81026 watts, alongside the exercises and information given here to estimate the lifetime of the Sun. (Hint: Make sure you keep track of the units: if the luminosity is the energy radiated per second, your answer will also be in seconds. You should convert the answer to something more meaningful, such as years.)arrow_forward
- From the information in Figure 15.21, estimate the speed with which the particles in the CME in parts (c) and (d) are moving away from the Sun. Figure 15.21 Flare and Coronal Mass Ejection. This sequence of four images shows the evolution over time of a giant eruption on the Sun. (a) The event began at the location of a sunspot group, and (b) a flare is seen in far-ultraviolet light. (c) Fourteen hours later, a CME is seen blasting out into space. (d) Three hours later, this CME has expanded to form a giant cloud of particles escaping from the Sun and is beginning the journey out into the solar system. The white circle in (c) and (d) shows the diameter of the solar photosphere. The larger dark area shows where light from the Sun has been blocked out by a specially designed instrument to make it possible to see the faint emission from the corona. (credit a, b, c, d: modification of work by SOHO/EIT, SOHO/LASCO, SOHO/MDI (ESA & NASA))arrow_forwardUsing the results from above (1.29^29 kg), how much total energy is available to the Sun via nuclear fusion over its lifetime? (HINT: only 0.71% of the total mass of the available H in the core is converted into energy)arrow_forwardAssume that Hydrogen comprises 79% of the Sun's mass. How much mass is this? 1.57e+30 kg Only about 11% of the initial Hydrogen in the Sun is in the core where it is hot enough to burn. What was the total mass of the inital H in the core of the Sun? Hint: Use the answer above and the percent in the core to determine the total mass. Using the results from above, how much total energy is available to the Sun via nuclear fusion over its lifetime? (HINT: only 0.71% of the total mass of the available H in the core is converted into energy) Hint: E = m c^2arrow_forward
- Using solar units, we find that a star has 4 times the luminosity of the Sun, a mass 1.25 times the mass of the Sun, and a surface temperature of 4090 K (take the Sun's surface temperature to be 5784 K for the sake of this problem). This means the star has a radius of.................... solar radii and is a .................... star (use the classification).arrow_forwardThe Sun is estimated to have about 5.00 billion years left in it’s “normal” (main sequence) lifetime. Assume the average “burn” rate that you computed in question #1, what % of the Sun’s current mass will have been converted at the end of it’s estimated 5.00 billion years of additional life? Actually, the Sun will lose more mass due to the solar wind, CMEs, the neutrio flux etc. the answer to number one was 3.683x10^14arrow_forward1 Solar constant, Sun, and the 10 pc distance! The luminosity of Sun is + 4- 1026 W - 4- 1033ergs-1, The Sun is located at a distance of m from the Earth. The Earth receives a radiant flux (above its atmosphere) of F = 1365W m- 2, also known as the solar constant. What would have been the Solar contact if the Sun was at a distance of 10 pc ? 1AU 1 1.5-+ 1011arrow_forward
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