Modern Physics
Modern Physics
3rd Edition
ISBN: 9781111794378
Author: Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher: Cengage Learning
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Chapter 13, Problem 7P
To determine

The energy difference.

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The electron in the hydrogen atom (in its ground state) orbits the nucleus at a distance of 0.5292 Å. (a) Calculate the gravitational force and (b) the electrostatic force of attraction between the two. (c) Comment on the magnitude and the importance of these two forces. [G, gravitational constant = 6.672 x 10-11 N m2 kg-2; 4+Єo = 1.113 x 10-10 C2 m-1 J-1]
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From far away a proton is fired directly toward the center of the nucleus of a mercury atom. Mercury is element number 80, and the diameter of the nucleus is 14.0 fm. Assume the mercury nucleus is fully-ionized, with no electrons bound to it. If the proton is fired at a speed of 3.8×107 m/s, what is its closest approach to the surface of the nucleus? Assume the nucleus remains at rest. Express your answer with the appropriate units. ► View Available Hint(s) 0 d = 2.7 Submit A fm Previous Answers ? X Incorrect; Try Again; 13 attempts remaining

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