Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN: 9781305389892
Author: Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher: Cengage Learning
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Chapter 12, Problem 7TYK
In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw× Aa Ww?
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Mouse fur color is affected by TWO unlinked loci. GG or Gg mice are agouti. Mice with genotype gg are albino since all pigment production is blocked, regardless of the phenotype at the second locus. At the other locus, the F allele (agouti coat) is dominant to the f allele (black coat). How many black mice would result from a cross between two agouti mice of genotype GgFf? (just write in the numeral)
In chickens, a dominant hereditary abnormality (e.g., creepers) causes death when the genotype is homozygous (CC). The recessive condition (cc) at this locus produces a normal phenotype. Another gene locus with co dominant alleles is known to govern feather color such that the
genotype FF = black, ff = splashed white, and Ff = blue. Also, a completely dominant gene W produces white skin. Yellow skin is produced by the homozygous genotype ww.
QUESTIONS:
In CcFfWw x ccffWw, what proportion of the offspring is:
b.2 normal, white feathered, white skinned
b.3 yellow skinned
In mice, the presence of AA alleles give rise to the agouti fur color, AAY gives rise to a yellow fur color, and AYAY is lethal, causing mice to die before birth. The B allele results in pigment formation and is dominant over the b allele. The bb genotype results in no pigment formation and gives an albino fur color irrespectively of the presence of the AA or AAY alleles.
In the following cross between a yellow and agouti mice, what would be the expected proportion of agouti fur mice among the live offspring?
AAY Bb X AA Bb
1/2
1/4
3/8
1/3
3/4
Chapter 12 Solutions
Biology: The Dynamic Science (MindTap Course List)
Ch. 12.1 - Two pairs of traits are segregating in a cross....Ch. 12.1 - If, instead, the four phenotypes in question 1...Ch. 12.2 - Palomino horses have a golden coat color, with a...Ch. 12.2 - A true-breeding rabbit with agouti (mottled,...Ch. 12 - The dominant C allele of a gene that controls...Ch. 12 - In peas, the allele Le produces tall plants and...Ch. 12 - Prob. 3TYKCh. 12 - What genotypes, and in what frequencies, will be...Ch. 12 - In addition to the two genes in problem 4, assume...Ch. 12 - Prob. 6TYK
Ch. 12 - In cats, the genotype AA produces tabby fur color;...Ch. 12 - Prob. 8TYKCh. 12 - The ability of humans to taste the bitter chemical...Ch. 12 - A man is homozygous dominant for alleles at 10...Ch. 12 - In guinea pigs, an allele for rough fur (R) is...Ch. 12 - Prob. 12TYKCh. 12 - Some recessive alleles have such a detrimental...Ch. 12 - In chickens, feathered legs are produced by a...Ch. 12 - A mix-up in a hospital ward caused a mother with O...Ch. 12 - Having malformed hands with shortened fingers is a...Ch. 12 - Prob. 17TYKCh. 12 - Design an Experiment Imagine that you are a...Ch. 12 - Prob. 19TYKCh. 12 - Prob. 1ITDCh. 12 - Prob. 2ITDCh. 12 - Half of the worlds population eats rice at least...
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- A coat color of a horse is governed by many different gene pairs. Dominant B will give the horse a black color, and homozygous b will give the horse a chestnut color. However, when a dominant W is present in the second gene pair, the horse will be white no matter what. If the second gene pair has no dominant W, then the horse will be the color of whatever the first gene pair is made of. Give the coat color of the horse of the following genotypes. 1. bbww A. Chestnut B. Black C. White 2. BbWw A. White B. Black C. Chestnut 3. bbWw A. Chestnut B. White C. Black 4. Bbww A. Black B. Chestnut C. White 5. BBWW A. Chestnut B. Black C. White PLEASE ANSWER THE ALL, THEY ARE ALL CONNECTED. THANK YOU!arrow_forwardA coat color of a horse is governed by many different gene pairs. Dominant B will give the horse a black color, and homozygous b will give the horse a chestnut color. However, when a dominant W is present in the second gene pair, the horse will be white no matter what. If the second gene pair has no dominant W, then the horse will be the color of whatever the first gene pair is made of. Give the coat color of the horse of the following genotypes: a. bbww -b. BbWw -c. bbWw -d. Bbww -e. BBWW –f. BBWw – What is the phenotypic ratio of the problem #4 if BbWw x BbWw were crossed? Label the phenotypes properly.arrow_forward) In mice, black coat color (B) is dominant over brown (b), and a solid pattern (S) is dominant to white spotted (s). Color and spotting are controlled by genes that assort independently. A homozygous black spotted mouse is crossed with a homozygous brown solid mouse. All of the F1 mice are black and solid. Give the genotypes of the parents and their F1 offspring. Parents- BBss bbSs Offspring- BbSs In biology class one day you see a black solid mouse run across your desk. You and your classmates manage to trap the mouse and decide to attempt to discover it’s genotype. In order to do this you perform a testcross with a laboratory mouse. b) What are the phenotype and genotype of the laboratory mouse that you will use for this testcross? c) What are ALL of the possible genotypes of the mouse from the classroom? d) You perform the testcross and find that ½ of the offspring from the testcross are black and solid and ½ are black and spotted. What is the genotype of…arrow_forward
- In bears fur colour can be either yellow or tan, and is determined by two alleles of the C gene. A heterozygous bear is observed to present a fur pattern of yellow and tan patches. Explain why this can occur.arrow_forward#1 a) An allele for coat color in mice, Y, produces a yellow coat color when present. The phenotypes of the F1 generation are shown. A cross between a Non-yellow mouse and yellow mouse produces half yellow and half non-yellow progeny (offsprings). Non-yellow happens to be white in this example, but it does not need to be; it can be black, grey, or some other mouse color. Identify the genotype of the "Dead" phenotype. Describe the rationale behind your genotypic selection. * Pgeneration Yellow Non-yellow Yellow Yellow Gametes Y Meiosis Fertilization 1/2 1/2 Yellow Non-yellow Fi generation Yellow Yellow Non-yellow Dead Support | Schoology Blog | PRIVACY POLICY | Terms of Use INTLarrow_forwardCoat color in mice is influenced by two genes, one for color (A) and one for the amount of pigment production (C). Mice with the wild type agouti coat color have a yellowish to brownish color. Mice also have a gene that determines the amount of pigment the hair produces. Multiple crosses were made between male and female mice that were each heterozygous for both traits (AaCc). The data table shows the number of mice of each coat type. Calculate the average F1 generation coat color to answer the question. Which of the following is the most probable interaction between the two genetic loci, A and C, based on the average F1 ratio results? A - The two loci show an epistatic pattern with the loci C epistatic to loci A.B - The two loci show a codominant pattern with both loci affecting coat color.C - The two loci interact in a Mendelian pattern with A being completely dominant over C.D - The two loci show an incomplete dominance pattern with neither loci A nor C being dominant.arrow_forward
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- In Labrador retriever dogs, two alleles (B and b) determine whether coat colour will be black (B)or brown (b). Black coat colour is dominant. A second pair of alleles, E and e, are on a separatechromosome from B and b. The homozygous recessive condition, ee, prevents the expressionof either allele B or b, and produces a dog with a yellow-coloured coat. Some examples ofgenotypes and phenotypes for Labrador retrievers are shown below.Genotype PhenotypeBBEe blackbbEe brownBbee yellow Two dogs, each with the genotype, BbEe, were crossed. What is the percentageprobability that their offspring will have yellow coat colour? (Record your answer as awhole number percentage)arrow_forwardThe B allele confers black coat color and the b allele brown coat color in Labrador dogs. When another gene, E, is inherited, the coat is golden no matter what the B phenotype is. A dog of genotype ee expresses the black phenotype. What unusual phenomenon is at work in this disorder?arrow_forwardThe presence of second allele (E) affects the coat color of Labrador. In particular, the presence of homozygous recessive ee produces yellow Labrador. Supposed a male Lab, homozygous dominant for both alleles, is crossed with a female Lab, homozygous recessive for both alleles, what would be the phenotypic ratio of the F1 offspring?arrow_forward
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