EBK ORGANIC CHEMISTRY-PRINT COMPANION (
4th Edition
ISBN: 9781119776741
Author: Klein
Publisher: WILEY CONS
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Chapter 12, Problem 43PP
Interpretation Introduction
Interpretation:
The starting material is a compound with three carbon atoms, and the desired product contains six carbon atoms. Reagents for the given conversion are to be determined.
Concept Introduction:
One of the ways this reaction can be achieved is by carbon-carbon coupling with the appropriate Grignard reagent. Organometallic reagents like Grignard Reagents are most used for carbon-carbon coupling reactions. This reaction can occur in presence of dry ether or acetone and Grignard reagent. In this case, Propyl Magnesium Bromide with
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Starting from cyclohexanol, show how to prepare:
Show all reagents and molecules synthesized along the way after each step. You do not have to use curved arrows.
Aldehydes and ketones react with one molecule of an alcohol to form compounds called hemiacetals, in which there is one hydroxyl group and one ether-like group. Reaction of a hemiacetal with a second
molecule of alcohol gives an acetal and a molecule of water.
ROH, H+
OH
OR
Aldehyde/ketone
Alcohol
ROH, H+
Draw the structural formulas for the hemiacetal and the acetal formed between the following compounds:
OH
OH
OR
OR
• Use the wedge/hash bond tools to indicate stereochemistry where it exists.
+ H₂O
Predict the IUPAC Product name. (Hint: first sketch the product then name
choosing the correct IUPAC PRODUCT NAME BELOW).
OH
+ NaOH
sodium propanol
sodium butanoate
sodium propanoate
O sodium butanalone
sodium benzoate
sodium propanal
sodium butanol
Chapter 12 Solutions
EBK ORGANIC CHEMISTRY-PRINT COMPANION (
Ch. 12.1 - Prob. 1LTSCh. 12.1 - Prob. 1PTSCh. 12.1 - Prob. 2ATSCh. 12.1 - Prob. 3CCCh. 12.2 - Prob. 4CCCh. 12.3 - Prob. 8CCCh. 12.3 - Prob. 9CCCh. 12.4 - Prob. 3LTSCh. 12.4 - Prob. 10PTSCh. 12.4 - Prob. 11ATS
Ch. 12.4 - Prob. 4LTSCh. 12.4 - Prob. 12PTSCh. 12.4 - Prob. 13ATSCh. 12.6 - Prob. 14CCCh. 12.6 - Prob. 5LTSCh. 12.6 - Prob. 15PTSCh. 12.6 - Prob. 16PTSCh. 12.7 - Prob. 18CCCh. 12.9 - Prob. 6LTSCh. 12.9 - Prob. 19PTSCh. 12.9 - Prob. 20ATSCh. 12.9 - Prob. 21CCCh. 12.10 - Prob. 7LTSCh. 12.10 - Prob. 22PTSCh. 12.10 - Prob. 23ATSCh. 12.13 - Prob. 8LTSCh. 12.13 - Prob. 24PTSCh. 12.13 - Prob. 25ATSCh. 12.13 - Prob. 26CCCh. 12.13 - Prob. 9LTSCh. 12.13 - Prob. 27PTSCh. 12.13 - Prob. 28ATSCh. 12 - Prob. 29PPCh. 12 - Prob. 30PPCh. 12 - Prob. 31PPCh. 12 - Prob. 32PPCh. 12 - Prob. 33PPCh. 12 - Prob. 34PPCh. 12 - Prob. 35PPCh. 12 - Prob. 36PPCh. 12 - Prob. 37PPCh. 12 - Prob. 38PPCh. 12 - Prob. 39PPCh. 12 - Prob. 40PPCh. 12 - Prob. 41PPCh. 12 - Prob. 42PPCh. 12 - Prob. 43PPCh. 12 - Prob. 44PPCh. 12 - Prob. 45PPCh. 12 - Prob. 46PPCh. 12 - Prob. 47PPCh. 12 - Prob. 48PPCh. 12 - Prob. 49PPCh. 12 - Prob. 50PPCh. 12 - Prob. 51PPCh. 12 - Prob. 52PPCh. 12 - Prob. 53ASPCh. 12 - Prob. 54ASPCh. 12 - Prob. 55ASPCh. 12 - Prob. 62IPCh. 12 - Prob. 64IPCh. 12 - Prob. 65IPCh. 12 - Prob. 66IPCh. 12 - Prob. 67IPCh. 12 - Prob. 68IPCh. 12 - Prob. 69IPCh. 12 - Prob. 74IP
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