Concept explainers
(a)
Interpretation:
The given conversions have to be performed to fill the blanks. The operations have to be done without calculator or spreadsheet.
(a)
Explanation of Solution
Given,
The conversion factor used to convert centimeters to meters is
The conversion factor used to convert centimeters to millimeters is
The conversion factor used to convert centimeters to nanometers is
The given blanks can be filled as follows:
(b)
Interpretation:
The given conversions have to be performed to fill the blanks. The operations have to be done without calculator or spreadsheet.
(b)
Explanation of Solution
Given,
The conversion factor used to convert cubic centimeters to cubic decimeters is
The conversion factor used to convert cubic centimeters to milliliters is
The conversion factor used to convert cubic centimeters to liters is
The conversion factor used to convert cubic centimeters to cubic meters is
The given blanks can be filled as follows:
(c)
Interpretation:
The given conversions have to be performed to fill the blanks. The operations have to be done without calculator or spreadsheet.
(c)
Explanation of Solution
Given,
The conversion factor used to convert grams to milligrams is
The conversion factor used to convert grams to kilograms is
The given blanks can be filled as follows:
(d)
Interpretation:
The given conversions have to be performed to fill the blanks. The operations have to be done without calculator or spreadsheet.
(d)
Explanation of Solution
Given,
The conversion factor used to convert degree Fahrenheit to degree Celsius is
The conversion factor used to convert degree Fahrenheit to Kelvin is
The given blanks can be filled as follows:
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Chapter 1 Solutions
Chemistry: Principles and Practice
- 1.65 An industrial engineer is designing a process to manufacture bullets. The mass of each bullet must be within 0.2 5% of 150 grains. What range of bullet masses, in mg, will meet this tolerance? 1 grain = 64.79891 mg.arrow_forwardHow many square meters will 4.0 L (about 1 gal) of paint cover if it is applied to a uniform thickness of 8.00 102 mm (volume = thickness area)?arrow_forwardWhat is the difference between reporting the quantity nine inches as 9 inches and 9.00 inches?arrow_forward
- Although the preferred SI unit of area is the square meter, land is often measured in the metric system in hectares (ha). One hectare is equal to 10,000 m2. In the English system, land is often measured in acres (1 acre = 160 rod2). Use the exact conversions and those given in Exercise 47 to calculate the following. a. 1 ha = __________ km2 b. The area of a 5.5-acre plot of land in hectares, square meters, and square kilometers c. A lot with dimensions 120 ft by 75 ft is to be sold for 6500. What is the price per acre? What is the price per hectare?arrow_forwardVanadium metal is added to steel to impart strength. The density of vanadium is 5.96 g/cm3. Express this in SI units (kg/m3).arrow_forward0.009 hm = %3D cm 1.0023 dm = hm %3D 0.2203 daL = µL %3D 515 cm = kmarrow_forward
- Length SI Unit: meter (m) 1 meter 1.094 yards %3D 1 inch = 2.54 centimeters (exactly) %3D 1 kilometer = 0.6214 miles %3D 1 mile = 5280 ft %3D Convert 968 km/h to ft/s. Answer in decimal form, without units. Answer:arrow_forward48400 mL – 138.1 mL = 3400.mg + 25.5g + 35.467g = in correct sig figs.arrow_forwardI. Significant Figures and Conversion A. Scientific Notation 1. 58 cm → km 2. 67 W → MW 3. 196 mL L 4. 17 dm – cm 5. 299 W → TWarrow_forward
- A student needs to determine the density of an irregularly shaped object. This student prepares a solution mixture where the object is suspended. The collected data is shown in the table below. Liquid Dichloromethane Methanol 0 Density mL g mL 1.3340 0.791 Volume (mL) 9.28 Determine the density of the object. Be sure your answer has the correct number of significant digits. 6.15 0 X Sarrow_forward9.121 x 10^-2 + 9.92 x 10^-3 =. ___arrow_forward10) Solve each problem and report your answer to correct significant figure and units. Remember that units multiply, divide, add, subtract and simplify just like variables. ml 65.0 kg + 0.05 kg + 179.1 kg = 17 g x 1.08 175 cm - 22.5 cm = 9.20 g/ (1.72 cm³ + 21 cm³) = ot avlo2a 3.23 x 10=23 ma (23.0 lb/gal)(2 ft) = (2.1 x 10-10 cm)3 to 1edmun sdi enimale0 (2.23 x 103 g)(9.0 × 10-3 g) (3.1 x 104 nm²)1/2 = Jmy to. 10.1 x 10-7 s2arrow_forward
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