Please see attached... which of the following activation would afford 1 and 2 respectively?1. activationH₂COM HỌ2. @OCH,CH₂CH₂H₂CCH₂CH₂H.CHOCHCH CH A. PBr3 pyridine for 1, TsCl, pyridine for 2C. TSCI, pyridine for 1, PBrs, pyridine for 2E. H₂SO for 1, PBr3, pyridine for 2B. H₂SO4 for 1, TsCl, pyridine for 2D. PBr3, pyridine for 1, H₂SO4 for 2

PBr3/Py produces inversion of stereochemistry in the bromination of alcohol. TsCl/Py makes the Oh…

Answered: which of the following activation would…

which of the following activation would afford 1 and 2 respectively? HỌ 1. activation H₂CO WH 2.00CH, CH₂CH₂ CH₂CH, H₂C OCH CH₂CH₂

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter12: Chemical Kinetics

Section: Chapter Questions

Problem 63AE: For the following reaction profile, indicate a. the positions of reactants and products. b. the...

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Question

Please see attached...

which of the following activation would afford 1 and 2 respectively?
1. activation
H₂CO
M HỌ
2. @OCH,
CH₂CH₂
H₂C
CH₂CH₂
H.C
HOCH
CH CH

A. PBr3 pyridine for 1, TsCl, pyridine for 2
C. TSCI, pyridine for 1, PBrs, pyridine for 2
E. H₂SO for 1, PBr3, pyridine for 2
B. H₂SO4 for 1, TsCl, pyridine for 2
D. PBr3, pyridine for 1, H₂SO4 for 2

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Under certain conditions the reaction H2O2 + 3I + 2H*→ I3¯ + 2H2O occurs by the following series of steps: ki Step 1. H2O2+H* =H;O2" + with K (equilibrium constant) = k1/k-1 Step 2. H3O2* +I→ H2O + HOI (slow, rate constant k2) Step 3. HỘI + I→ OH¯ +I2 (fast, rate constant k3) Step 4. OH + H*→ H2O (fast, rate constant k4) Step 5. I2 + I→ 13 (fast, rate constant k5) Use approximations (RDS, eq, steady-state) if necessary The rate constant k for the reaction would be given by