? SAQ 11-3 Draw the Fischer projections for the enantiomers of the following molecules. b. H₂C-CH-COOH T Br 2-bromopropanoic acid H₂C-CH-COOH NH₂ alanine HOCH2 - CHỊ CHO 1 OH glyceraldehyde
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- Two sugars differing in configuration at a single asymmetric carbon atom are known as epimers. D-mannose is a C-2 epimer of glucose (Structure I), while D-galactose is a C-4 epimer of glucose. Structure Il and IIl are H- -OH но- -H H OH HO H но- H HO H H -OH H- -OH HO OH H -OH H- -OH H OH HO. HO, OH II II Which of the following represents an aldopentose? OH H O HO O HO H но н HO H но- HO H HO H HO- H OH H OH H OH H OH OH HO Он of но" HO O OH он III IV These are chemical messengers that are secreted by endocrine glands and carried through the bloodstream to target tissues. prostaglandin deoxysugar glycoside hormones Which of the following is NOT correctly paired? cellulose: beta-1,4-glycosidic linkage amylose: alpha-1,4-glycosidic linkage chitosan: alpha-1,4-glycosidic linkage cellubiose: beta-1,4-glycosidic linkage6 is the stereocenter S? MCAT prepThe corresponding positions for the functional groups of the Haworth projection for D-Psicose are: OA. Carbon 3: Down Carbon 4: Down Carbon 5: Up OH functional group for the beta anomer: Down OB. Carbon 3: Down Carbon 4: Down Carbon 5: Down OH functional group for the beta anomer: Down OC Carbon 3: Down Carbon 4: Down Carbon 5: Up OH functional group for the beta anomer: Up O D.Carbon 3: Down Carbon 4: Up Carbon 5: Up OH functional group for the beta anomer: Down O E. Carbon 3: Down Carbon 4: Up Carbon 5: Up OH functional group for the beta anomer: Up O F. Carbon 3: Up Carbon 4: Down Carbon 5: Down OH functional group for the beta anomer: Down O G.Carbon 3: Up Carbon 4: Down Carbon 5: Down OH functional group for the beta anomer: Up O H.Carbon 3: Down Carbon 4: Down Carbon 5: Down OH functional group for the beta anomer: Up
- What is the relationship between the following molecules? CHO CH2OH H- -HO- H- -HO- но - H. HO -- H- OH H. OH но H- HO H. CH2OH CHO O identical O epimers diastereomers enantiomers Thanter 20 Home ndf 工5. Identify the chirality center as R- or S- HN OH __)-pindolol beta-blocker (5-HT antagonist) a. Constitutional isomers b. Stereoisomers _)-nicotine binds to nicotinic acetylcholine receptors i. Enantiomers ii. Diastereomers Ph Ph 6a. Draw 1-ethyl-3-iodocyclohexane in all possible R/S ways (RR, SS, RS, SR). 6b. Of this set (4 molecules), which are A. Isomers C _)-methadone an opioid use to treat addiction to other opioidss. What? (opioid agonist)Use your knowledge of condensation reactions to complete the following tasks. Protein: Draw a condensation reaction where a molecule of cysteine combines with a molecule of lysine, showing all reactants and products, and labeling a peptide linkage in your final product. Make sure the structures you draw include all hydrogens (leave every bond labeled and included in your drawing; don't use shorthand). Carbohydrate: Draw two ringed a-D glucose monomers forming a disaccharide (maltose). Make sure to label the glycosidic linkage formed.
- 8) Identifique la relación existente (diastereoisómeros, enantiómeros, isómeros estructurales o moléculas idénticas) entre cada uno de los siguientes pares de compuestos. b) H₂C-H CH₂ H-OH H₂C Brac-cl CH₂ OHC HO CH₂CH₂ CH₂CH₂ Br "CH H₂C HO₂0 COH OH H₂C- H- 9) Especifique la configuración absoluta para cada estereocentro en las siguientes moléculas. CH₂ CH₂CH₂ -H -OH CH₂ H₂CH₂CC CH₂ CICI Br H₂CH H₂N 27 H₂C COOH * -CH₂CH(CH₂) CH₂ ço, "HN-TH CH₂CH₂CO₂Na a co₂(c) Label the following pair of molecules as homomer, enantiomer or diastereomer 2+1 ÇO,H ÇO,H Me () н. LOME Cl- "Ph and Cl and Ме H- -OMe H Ph Ét EtWhich of the molecules shown are meso/ mesomeric? b. NH HN NH HN HO d. SCH, HO,C SCH, All four molecules are meso. Molecules b and d. Molecules a, b, and d. Molecules c and d. Molecules a and d.
- VII. Place asterisks at all the chirality centers in the molecule below. O || CH;CHCNH NH₂ cephalexin N S. CO₂H CH36) Which of the following compounds is meso? H3C H HO OH H₂C -C-H CH3 H CH3 HS F. F SH Br ä Br HPh car OH. ОН 0= 1 enantiomer (1 chiral compound) 1:1 mix of enantiomers mixture of diastereomers achiral