Which is the correct equation for the chisquare statistic? Group of answer choices a)x^2 = [(observed-expected)^2]/expected b)x^2 = sum[((observed-expected)^2)/observed] c)x^2 = sum[((observed-expected)^2)/expected] d)x^2 = sum[(observed-expected)/expected] What is a "p-value"? Group of answer choices a)the threshold at which you will reject the null hypothesis b)the probability of the null hypothesis being false c) the percentage of days you are sick during the year d) the probability of the null hypothesis being true
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- page - Columbus State Uni X content/2622738/viewContent/50155728/View + Calculating the Value of Chi-Square Once you've defined the null hypothesis (and know what you're testing!), you can finally calculate the chi-square value based on your observed data and the expected distribution. There are many statistical software packages and free web-based applications that will automate the calculation for you, but it's important to understand the calculation to understand the meaning of the calculated value. Here, we'll walk through it using a calculation table. This is Mendel's historic data for the F2 generation of monohybrid cross for flower color. Recall that he expected to see in the F2 generation a ratio of 3 purple : 1 white. Chi-square calculation for data from a monohybrid cross with an expected 3 purple : 1 white ratio. Outcomes Observed (0) Expected (E) O-E (0-E)2 (O-E)²/E Purple White Totals 705 224 929 X²= The first step is to calculate the expected (E) values for purple and…You perform a chi-square test to compare observed and expected values and obtain a chi-square value of 9.4 with 3 degrees of freedom. What do you conclude? it is not likely that the difference between observed and expected values is due to random chance, since p>0.05 it is impossible to conclude anything from this information it is likely that the difference between observed and expected values is due to random chance, since p>0.05 it is likely that the difference between observed and expected values is due to random chance, since p<0.05 the experiment was done incorrectly and must be repeated it is not likely that the difference between observed and expected values is due to random chance, since p<0.05A) If other factors are held constant, how does sample variance influence the likelihood of rejecting the null hypothesis and the measure of effect size (i.e. Cohen’s d)? B) Briefly explain what least square solution is.
- Example 3.5.7 Fish Vertebrae Consider the distribution of vertebrae given in Table 3.5.1. In Exam- ple 3.5.5 we found that the mean of Y is µy = 21.49. The variance of Y is VAR(Y) = of = (20 – 21.49) x Pr{Y = 20} 21) %3D + (21 – 21.49)? x Pr{Y + (22 – 21.49)? x Pr{Y = 22} + (23 – 21.49) x Pr{Y = 23} = (-1.49) x 0.03 + (-.49) x 0.51 + (0.51) x 0.40 + (1.51)² × 0.06 = 2.2201 x 0.03 + .2401 x 0.51 + .2601 x 0.40 + 2.2801 x 0.06 = 0.066603 + 0.122451 + 0.10404 + 0.136806 = 0.4299. The standard deviation of Y is ay = V0.4299 - 0.6557. %3DDescribe in your own words what variance measures. Then explain why the variance of both samples must be used in the calculation of a t-test (In other words, explain why we have to factor in the variance when comparing the means).The confidence interval is reported as follows: Lower 95% CI < p < Upper 95% CI For this question you will be calculating the confidence interval but only reporting the Upper 95% CI using the Agresti-Coull Method. ( (you'll need to know the whole 95% CI for a future question) Do NOT use calculations from previous questions, this is a new scenario. In the Invisible Gorilla Experiment, 24 students were watching the video, only 7 noticed the gorilla. Calculate the 95% CI using the Agresti-Coull method, but only report the Upper 95% CI. Report your answer to 3 decimals.
- What does P-value indicate? In statistical analysis the results for two sets of data are presented with P < 0.01 and P<0.005. What does it mean?b. a. in a population. Hardy-Weinberg p+q=1 (Rr), and 16% white (rr). This population is in a Hardy-Weinberg equilibrium. 42. In a population of cattle, the following color distribution was noted: 36% red (RR), 48% roan baith p²+2pq+q² =1 Determine the frequencies of the R alleles and the r alleles? assumptions are met? What will be the distribution of genotypes in the next generation if the Hardy-Weinberg a. 36% red; 48% roan; 16% white b. 30% red; 50% roan; 20% white c. 30% red; 60% roan; 10% white d. 40% red; 40% roan; 20% white 10 u ti- sorIf the Chi-squared value for this system is 2.40, is.the population in Hardy-Weinberg equilibrium? Why? (note: the critical values for this test is 3.84). [Select]
- Interpret the results for each significant predictor (i. e., explain what the coefficient is telling us).If the chi-square value is 0 under the degree of freedom 1. What could be the interpretation and does it fit in the population of Hardy-Weinberg equilibrium?I'm needing help with part 1 through 3, please The data of Sugar Water and Plain Water: mean # of drops variance degrees of freedom t stat t crit (from the table) plain water 25.3 17.221 38 -4.01 2.0261 sugar water 21.3 21.256 1. Make a statement about t stat in relation to t crit. And what is the p-value? 2. Is there a statistically significant difference between the mean values (mean # of drops) of the sugar and plain water? Give your "yes" or "no" answer and the supporting evidence. 3. Hypothesis: The surface tension of plain water is higher than the surface tension of sugar water. Do these results support or refute the hypothesis about the effect of dissolving salt in water on surface tension?