When allyl bromide is refluxed with magnesium metal in ether solvent, the product formed is 1,5-hexadiene. (C6H10). What is the curved arrow mechanism for this reaction?
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When allyl bromide is refluxed with magnesium metal in ether solvent, the product formed is 1,5-hexadiene. (C6H10). What is the curved arrow mechanism for this reaction?
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- 4. Draw structural formulas for all possible monohalogenation products that might be formed in the following reactions, then assign them IUPAC names. (a) + Cl₂ lightWhich alkene reacts with a red-brown solution of bromine to form 1,2-dibromo-1-ethylcyclohexane.10) For the reaction between isopropyl 1-propyl (or 'n-propyl') ether and HBr, which type of reaction best matches the expected products? A) Acid-catalyzed dehydration B) Nucleophilic substitution reaction C) Ether cleavage reaction D) Nucleophilic addition-elimination reaction
- When alkyne A is treated with NaNH2 followed by CH3I, a product having molecular formula C6H10O is formed, but it is not compound B. What is the structure of the product, and why is it formed?Addition of HBr to allene (CH2 = C = CH2) forms 2-bromoprop-1-ene rather than 3-bromoprop-1-ene, even though 3-bromoprop-1-ene is formed from an allylic carbocation. Considering the arrangement of orbitals in the allene reactant, explain this result.Acid-catalyzed dehydration of 3,3-dimethyl-2-butanol gives three alkenes: 2,3-dimethyl-2-butene, 3,3-dimethyl- 1-butene, and 2,3-dimethyl-1-butene. Draw the structure of the carbocation intermediate leading to the formation of 2,3-dimethyl-2-butene. • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • If more than one structure fits the description, draw them all. • Separate structures with + signs from the drop-down menu. / H₂C CH₂ CH3 CH3 ChemDoodleⓇ On []
- Addition of HBr to allene (CH2=C=CH2) forms 2-bromoprop-1-ene rather than 3-bromoprop-1-ene, even though 3-bromoprop-1-ene is formed from an allylic carbocation. Considering the arrangement of orbitals in the allene reactant, explain this result.8. a) b) Provide structure(s) for the starting material(s), reagent(s) or the major organic product(s) of each of the following reactions. OEt COOH CH3 CH; 0 OH 1. LiAlH4, ether 2. HO OH ند (CH3COO NaOH, H₂O 5 CH 3 ClDraw the line-angle formula of the enol formed in the following alkyne hydration reaction and then draw the structural formula of the carbonyl compound with which this enol is in equilibrium. -C=CH 1. (sia)2BH 2. NaOH/H₂O₂ an enol carbonyl compound • You do not have to consider stereochemistry. • Draw both the enol and the carbonyl forms. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate structures using the sign from the drop-down menu. ChemDoodleⓇ <
- Acid-catalyzed dehydration of 3,3-dimethyl-2-butanol gives three alkenes: 2,3-dimethyl-2-butene, 3,3-dimethyl-1-butene, and 2,3-dimethyl-1- butene. Draw the structure of the carbocation intermediate leading to the formation of 2,3-dimethyl-2-butene. • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. If more than one structure fits the description, draw them all. Separate structures with + signs from the drop-down menu. C P opy aste ChemDoodle >Draw the bond-line (skeletal) structure of the compound with molecular formula C₂H₁3Br that gives the following alkene as the exclusive product of E2 elimination. Click and drag to start drawing a structure. C X C Ś c+When the alkene A was treated first with Hg(OAc)2 in MeOH and second with NaBH4 the product was the ether B. Using curved arrows please give the mechanism for the first step of (Hg(OAc)2 in MeOH) this reaction, including any regioselectivity or stereoselectivity. H3C 1. Hg(OAc)2, MeOH H3C O-CH3 =CH2 ✓ -CH3 H3C 2. NaBH H3C A B