There are two separate phases, one of which is 12% phenol and the other is 60% phenol, from a 210 gram phenol-water mixture at a temperature of 60°C with a composition of 35% phenol. Calculate the masses of these phases.
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- Aniline, C6H5NH2, and hexane, C6H14 , form partially miscible liquid - liquid mixtures at temperatures below 69. 1 °C. When 42.8 g of aniline and 75 .2 g of hexane are mixed together at a temperature of 67.5 °C, two separate liquid phases are formed, with mole fractions of aniline of 0.308 and 0.618.(a) Determine the overall mole fraction of aniline in the mixture. (b) Use the lever rule to determine the relative amounts of the two phases.The table below shows temperature/composition data collected for a mixture of methylbenzene (M) and octane (O) at 1 atm. Recall that x stands for the mole fraction in the liquid and y stands for the mole fraction in the vapor in equilibrium. The boiling points for methylbenzene (M) and octane (O) are 110.60C and 125.60C, respectively. Construct the phase diagram with Temperature vs. xM. What is the composition of the vapor in equilibrium with the liquid of composition (a) xM = 0.250 and (b) xO = 0.250. T (0C) 110.9 112.0 114.0 115.8 117.3 119.0 121.1 123.0 xM 0.908 0.795 0.615 0.527 0.408 0.300 0.203 0.097 yM 0.923 0.836 0.698 0.624 0.527 0.410 0.297 0.164There are two separate phases, one with a composition of 12% phenol and the other with a composition of 60% phenol, from a 210 gram phenol-water mixture at 60 °C with a composition of 35% phenol. Calculate the masses of these phases.
- The binary water-phenol diagram is given below, in molar fraction, under the total pressure Pt = 1 atm. 1) How many phases are there in the domain marked "I"? 2) From which temperature the mixture become miscible in all proportions? How do you call that temperature? 3) At a temperature T = 50 °C, in a controlled temperature container containing water. Phenol is then poured at the same temperature until the molar fraction of phenol in the mixture XC2H50H is equal to 0.05. Then, we continue to add the phenol gradually, at a constant temperature, to XC2H5OH of phenol in the mixture is XC2H5OH = 0.8. = 0.4. Then finally we stop adding phenol when the molar fraction a. How many phases are present at each one of the three mixture compositions in the container during the addition of the phenol? b. What is the composition of the phases when the fraction of phenol is XC2H5OH = 0.4? c. What is the proportions of the phases with respect to each other when XC2H5OH = 0.4? (Show your calculations)…The vapor pressure of pure dichloromethane at 298 K is 57.3 kPa. What is its vaporpressure above its mixture with chloroform with 8:2 molar ratios of dichloromethane to chloroform (consider their mixture an ideal solution).Aniline, C6H5NH2, and hexane, C6H14, form partially miscible liquid–liquid mixtures at temperatures below 69.1 °C. When 42.8 g of aniline and 75.2 g of hexane are mixed together at a temperature of 67.5 °C, two separate liquid phases are formed, with mole fractions of aniline of 0.308 and 0.618. (i) Determine the overall mole fraction of aniline in the mixture. (ii) Use the lever rule to determine the relative amounts of the two phases.
- There are two separate phases, one with a composition of 12% phenol and the other with a composition of 60% phenol, from a 210 gram phenol-water mixture with 35% phenol at 60oC. Calculate the masses of these phases.Figure 1 shows the phase diagram for two partially miscible liquids , which can be taken to be that for water (A) and 2-methyl-1-propanol (B). Describe what will be observed when a mixture of composition b3 is heated, at each stage giving the number, composition, and relative amounts of the phases present.(b) Surface sanitizers were prepared using ethyl alcohol/water and isopropyl alcohol/water solutions. An experiment was done to determine which composition would be most effective and as such two solutions were formulated: 70 % v/v ethyl alcohol and 70 % v/v isopropyl alcohol. Calculate the vapour pressure of these solutions and use your answer to reason which combination would stay on the surface longer. P° (Ethyl alcohol) = 12.4 kPa P° (Isopropyl alcohol) = 4.4 kPa P° (Water) = 2.4 kPa
- Based on the ternary phase diagram, a binary mixture of furfural and water will always split into two liquid phases: 1) 95 % furfural, 5 % H2O and 2) 92 % H2O, 8 % furfural. Neither true nor false True False The actual composition depends on other experimental parameters.Phenol and water form non-ideal liquid mixtures. When 7.32 g of phenol and 7.95 g of water are mixed together at 60 °C they form two immiscible liquid phases with mole fractions of phenol of 0. 0 42 and 0 .161 . (a) Calculate the overall mole fraction of phenol in the mixture. (b) Use the lever rule to determine the relative amounts of the two phases .There is a 15.85% by mass aqueous KCl (molecular weight 74.5513 g mol–1) solution at 25 °C. The density of the solution is that of pure water (dsolution = 1.000 g mL–1). The ebullioscopic constant (Kb) for water is 0.513 °C m–1. The cryoscopic constant (Kf) for water is 1.86 °C m–1. The vapor pressure of pure water is 0.0313 atm. Could you please find osmotic pressure?