The gene for curly/straight hair in guinea pigs is located on the X chromosome. The dominant "R" allele results in curly hair. The pedigree shows a guinea pig family with a history of curly hair. Filled-in shapes indicate individuals who have curly hair. I. II. III. Part 1. The blue shaded male guinea pig mates with a female guinea pig who has straight hair. Write out the genotypes of each parent and all possible offspring from this cross. Remember, the gene is on the X chromosome.

The gene for curly/straight hair in guinea pigs is located on the X chromosome. The dominant "R" allele results in curly hair. The pedigree shows a guinea pig family with a history of curly hair. Filled-in shapes indicate individuals who have curly hair. I. II. III. Part 1. The blue shaded male guinea pig mates with a female guinea pig who has straight hair. Write out the genotypes of each parent and all possible offspring from this cross. Remember, the gene is on the X chromosome.

Name: 9 The gene for curly/straight hair in guinea pigs is located on the X
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Description: 9 The gene for curly/straight hair in guinea pigs is located on the X chromosome. The dominant "R" allele results in curly hair. The pedigree shows a guinea pig family with ahistory of curly hair. Filled-in shapes indicate individuals who have curly

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter4: Pedigree Analysis In Human Genetics

Section: Chapter Questions

Problem 3QP: Pedigree Analysis Is a Basic Method in Human Genetics Using the pedigree provided, answer the...

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1 II 1 4 6. II 1 2 4 5 6. 8. IV The above image shows a pedigree for a monogenic inherited disease. Although this trait is only observed in males in this family, the pattern of inheritance of this disease is autosomal recessive. Use the pedigree to explain why the inheritance of this disease cannot be autosomal dominant. If this trait is X-linked recessive, what would be the genotypes of the people in Row I? 2. 2. 3. 2. 3.
The allele for color-blindness is carried on the X chromosome. Making color blindness (a recessive trait) an X - linked trait. A colorblind make and a carrier female for color blindness. (But is not colorblind herself) have a child. Show your work! A) what is the % chance that their son will be color blind? B) what is the % chance that their daughter will be color blind?
Below is a pedigree of a family with a history of X-linked recessive color blindness. We will use XB to represent the wild-type allele and Xxb to represent the mutant allele of the gene that leads to color blindness. The color vision status of the individuals with a question mark (?) is unknown. Part 1 Drag the correct genotype for each individual to the boxes under the pedigree symbols for the first two generations. O I. II. O1/4 O 1/2 O 3/4 xBxBxbxbxby xbxB XBXB or xbxB xBy O 0 Part 2 What is the probability that the female child in Generation III will be color-blind? Ⓒ1/4 1/2 O 3/4 000 O 0 0 Part 3 What is the probability that the male child in Generation III will be color blind? ? Autosomal dominant Autosomal recessive ? C Part 4 Are the first two generations of this pedigree consistent with the following modes of inheritance? ✓ No Yes
An individual comes into your genetics clinic to be tested for any anomalies. When looking at their karyotype, you notice they have three X chromosomes and a Y chromosome. What information would you be able to relay to this individual? O They have Turner syndrome, are genetically female, and have two Barr bodies per cell. O They have Klinefelter syndrome, are genetically female, and have two Barr bodies per cell. O They have Klinefelter syndrome, are genetically male, and have two Barr bodies per cell. O They have Klinefelter syndrome, are genetically male, and have three Barr bodies per cell. O They have Turner syndrome, are genetically male, and have three Barr bodies per cell.
A woman with no phenotype is known to have a 14:21 translocation. Please answer questions 1 and 2. 1. With respect to only chromosomes 14 and 21, how many distinct chromosome combinations will happen in her eggs? What portion will be viable? 2. If she has children with a normal man (no translocations), what is the probability that they have a daughter with Down Syndrome or a son with no phenotype?
Glucose-6-phosphate dehydrogenase (G6PD) deficiency is a disorder that affects the normal function of red blood cells and can eventually lead to anemia. The trait is controlled by a recessive allele found on 4. the X chromosome. An affected son was born to a man and woman who were unaffected. The woman's mother was affected while the father was normal. a. Indicate the gene notation. b. Give the genotypes of the affected boy's parents. Derive the genotypic and phenotypic ratios for the offspring. Show and label your solutions properly. What is the probability that they will have a phenotypically normal daughter as their first child? C. d.
My Question is what is the probability their first child will have hemophilia and drawn pedigrees for family members with genotypes. My explantion so far: A man has both X and Y chromosomes as sex chromosomes in his body. Here, though the brother of the man is hemophiliac, a man can’t be a carrier of hemophilia. So, it can be said that his chromosome is “XnY”.Here, the “n” stands for “normal”.Though the paternal uncle is hemophiliac, a man cannot be a carrier of hemophilia, his niece will not be a career. So it can be said that the woman is also not a carrier and has the “XnX” chromosome.So, as the mother is not a carrier, their first child does not have a chance of having hemophilia. This can be determined as it is known that there is no hidden carrier of hemophilia in the family.
Two mothers give birth to sons at the same time at a busy urban hospital. The son of mother 1 is afflicted with hemophilia, a disease caused by an X-linked recessive allele. Neither parent has the disease. Mother 2 has a normal son, despite the fact that the father has hemophilia. Several years later, couple 1 sues the hospital, claiming that these two newborns were swapped in the nursery following their birth. As a genetic counselor, you are called to testify. What information can you provide the jury concerning the allegation?
Draw a Punnett square for the dihybrid cross described below (it is the same story as given for question 8, above) and use it to fill in the blanks correctly in the text that follows. NOTE: Please type in whole numbers, no symbols. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and…
Congenital hypertrichosis (CH) is a very rare X-linked dominant inherited condition. CH is characterized by the growth of dark hair over the body. CH is so rare, only 50 cases have been identified since the Middle Ages. The incidence of this condition is considerably higher in a small Mexican village (from which the partial pedigree below is derived) than the rest of the human population. I II III Use the following information to answer the two questions. IV D II-4 8 9 IV-6 0=10~ 11 1. Using appropriate nomenclature, identify the genotypes for the following 2 individuals: 12 13 your response must include an appropriate legend/key to identify allele symbols. 2. Show how a Punnett square (using the allele symbols from the previous question) is used to determine the probability in percent of individuals III-11 and III-12 next offspring has CH?
A woman who is heterozygous for gene B has brown eyes. B is a dominant allele for brown pigmentation, while b is recessive allele for blue pigmentation. The woman has a patch of blue color in her left eye. Give THREE (3) reasons how this might occur.
An abnormality of the large intestine called intestinal polyposis (IP) is dependent on dominant gene A. A nervous disorder called Huntington’s chorea (HC) is determined by dominant gene H, a lethal gene the effects of which appear on a mean age of 40 years. A and H are on nonhomologous chromosomes. A man carrying the gene A marries a woman carrying the gene H. If this couple had 7 children, what is the chance that at least 2 of their children will survive up to old age? What are the genotypes of the man and his wife?