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Draw a Punnett square for the dihybrid cross described below (it is the same story as given for question 8, above) and use it to fill in the blanks correctly in the text that follows. NOTE: Please type in whole numbers, no symbols. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage. ANSWER: In the dihybrid cross described above Blank 1 percent of the female offspring are expected to be blue eyed. Blank 2 percent of the offspring are expected to show polydactyly as a result of inheriting the X linked mutation. The couple in the story above have eight children of which Blank 3 would be expected to have blue eyes. Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer

Draw a Punnett square for the dihybrid cross described below (it is the same story as given for question 8, above) and use it to fill in the blanks correctly in the text that follows. NOTE: Please type in whole numbers, no symbols. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage. ANSWER: In the dihybrid cross described above Blank 1 percent of the female offspring are expected to be blue eyed. Blank 2 percent of the offspring are expected to show polydactyly as a result of inheriting the X linked mutation. The couple in the story above have eight children of which Blank 3 would be expected to have blue eyes. Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer

Human Biology (MindTap Course List)
Human Biology (MindTap Course List)
11th Edition
ISBN:9781305112100
Author:Cecie Starr, Beverly McMillan
Publisher:Cecie Starr, Beverly McMillan
Chapter20: Chromosomes And Human Genetics
Section: Chapter Questions
Problem 2CT: Human sex chromosomes are XX for females and XY for males. a. With respect to an X-linked gene, how...
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Draw a Punnett square for the dihybrid cross described below (it is the same story as given for question 8, above) and use it to fill in the blanks correctly in the text that follows. NOTE: Please type in whole numbers, no symbols. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage. ANSWER: In the dihybrid cross described above Blank 1 percent of the female offspring are expected to be blue eyed. Blank 2 percent of the offspring are expected to show polydactyly as a result of inheriting the X linked mutation. The couple in the story above have eight children of which Blank 3 would be expected to have blue eyes. Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer
Transcribed Image Text:Draw a Punnett square for the dihybrid cross described below (it is the same story as given for question 8, above) and use it to fill in the blanks correctly in the text that follows. NOTE: Please type in whole numbers, no symbols. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage. ANSWER: In the dihybrid cross described above Blank 1 percent of the female offspring are expected to be blue eyed. Blank 2 percent of the offspring are expected to show polydactyly as a result of inheriting the X linked mutation. The couple in the story above have eight children of which Blank 3 would be expected to have blue eyes. Blank 1 Add your answer Blank 2 Add your answer Blank 3 Add your answer
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