How do I solve for the bottom two boxes.(Calculate average moles of HCl in River water, mol)(Average concentration (M) of HCl in the River water. M=mol/L 2ndaccurate titrationSample Site CFinal reading (mL)st1" accurate titration41.00 mL40.10 mLInitial Reading (mL)|1.85 mL10.95mLVolume River water added to29.15 cm3 = 0,02915 L29.15cm 0.02915the flask (L)Average volume River wateradded to the flask (L)Calculate average moles ofHCl in River water, mol29.15 cm3 = 0,02915LAverage concentration (M) ofHCl in the River water. M =mol/L

Answered: Image /qna-images/answer/182feeab-72a3-49e1-b51d-2cd6a4996ba8.jpg

Sample Site C Final reading (mL) 1 accurate titration 2nd accurate titration 41.00 mL 40.10 mL Initial Reading (mL) 11.85 mL 10.95 Volume River water added to 29.15 cm3 = 0,02915 L 29.15cm 0.02915 the flask (L) Average volume River water added to the flask (L) 29.15 cm3 = 0,02915 L Calculate average moles of HCl in River water, mol Average concentration (M) of HCl in the River water. M = mol/L

Sample Site C Final reading (mL) 1 accurate titration 2nd accurate titration 41.00 mL 40.10 mL Initial Reading (mL) 11.85 mL 10.95 Volume River water added to 29.15 cm3 = 0,02915 L 29.15cm 0.02915 the flask (L) Average volume River water added to the flask (L) 29.15 cm3 = 0,02915 L Calculate average moles of HCl in River water, mol Average concentration (M) of HCl in the River water. M = mol/L

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter21: Potentiometry

Section: Chapter Questions

Problem 21.22QAP

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