15.00 pH (a) 7.08 14.50 ΔΡΜΙΔΝ 12 10 8 0 (b) 0 0.450 12 10 0 0 5 10 15 20 25 5 10 15 20 25 Volume of titrant (ml) Volume of titrant (mL) 1 mol CH3COOH=: 1mol NaOH, M11(205)=0,0998-15 M1=0073_m=0073*60_5=0.0905 14.88 Δ'ΡΜΙΔV» 30 20 10 0 -10 -20 -30 (c) 1.19 5 10 15 20 25 Volume of titrant (ml)
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- 3:21 1 4 7 +/- Question 7 of 10 In the titration of 230.0 mL of 0.4000 M HONH₂ with 0.2000 M HBr, how many mL of HBr are required to reach the equivalence point? 2 5 8 mL 3 60 9 O Submit Tap here or pull up for additional resources XU x 100Answer if true or false , if false, put the correct answer 1. There is 11.34 mmol in 0.2011 of 0.5604 M HgCl2 2. The x axis of sigmoidal titration curve is p function of the analyte or titrant 3.The concentration of the secondary standard is relative to a primary standard 4. There is 110 mmol in 79.8 mL of 0.1379 M NH4VO3 (116.98 g/mol)WARIARTAM 2. 1.2589 g of a certain brand of milk powder required 25.89 mL of 0.01873M EDTA to titrate the calcium contained in the sample. (a) What is the percent calcium in the sample? (b) Would the true result be higher, lower, or not be affected if the milk powder sample has been slightly wet?
- 5. A 300.0 mg sample containing Na,CO3, NaHCO3 and NaOH and inert material either alone or in some combination was dissolved and titrated with 0.1000 M HCI the titration required 24.41 mL to reach the phenolphthalein endpoint. And an additional 8.67 mL to reach the methyl red endpoint. Determine the composition of the sample and calculate the percent of each titrated component.Salt MgCO3 Mg(OH)2 Theoretical Ksp 3.5 x 10-8 1.8 x 10-11 For the standardization of the HCI titrant, 5.230 mg Na2CO3 (98.9% purity, MW = 105.99 g/mol) required 24.4 mL of the titrant to reach the phenolphthalein endpoint. After isolating and precipitating the magnesium salt A, a portion was dissolved in distilled water in order to make a 250.0-mL saturated solution. The titration of a 50.0-mL aliquot of the saturated solution required 8.20 mL of HCl titrant to reach the phenolphthalein endpoint. Meanwhile, dissolving this magnesium salt in 250.0 mL of 0.0200 M MgCl2 required 1.51 mL of the same HCl titrant to titrate a 100.0-mL solution. a. What is the molarity of the HCI titrant? b. Comparing the data in distilled water with the two possible solids, which is the most likely identity of the magnesium salt? Show your full solutions in getting your conclusion. Note: Don't forget to factor in stoichiometry c. What is the average experimental Ksp for both solvents (distilled water and…Part A: Standardization of a Sodium Hydroxide Solution Titration 1 Titration 2 Titration 3 Mass of 125 mL flask 45.849g 46.715g 44.953g Mass of flask and KHP 46.849g 47.745g 46.003g Initial buret reading (mL) 0.5 ml 0.5 ml 0.5 ml Final buret reading (mL) 27.8 ml 26.5 ml 26.7 ml Volume of NaOH used (mL) 45.11 ml 45.06 ml 45.14 ml Calculations Titration 1 Titration 2 Titration 3 Moles of KHP Moles of NaOH Molarity of NaOH Average Molarity of NaOH: _______________
- 12Electrodes of the first kind have poor precision The answer is either true or false 16Voltammetry consumes greater amount of analyte than coulometry 3. The equivalence point is located at the center of the steep part of the titration curve in case of equimolar reaction stoichiometry. 나 18The equivalence point is at the center of the steep part of the titration curve only if the reaction stoichiometry was 1:2. Time 19The second kind electrodes can respond to the activities of both anions and cations that form sparingly soluble precipitates In voltammetry-we measure the current as a change in timeReductant/ Analyte Standardizing Indicator reagent Titration Titrant Oxidant COD BOD INDIRECT TITRATIONData Table 3: Complexometric Titration of Soft Water 5 ml of water 1ml of buffer Hard Water Trial 1 Hard Water Trial 2 Hard Water Trial 3 Initial Syringe Reading (mL) 1ml 1ml 1ml Final Syringe Reading (mL) 77ml 79ml 75ml Volume of EDTA Consumed (mL) .23ml .21ml .25ml Water Hardness ppm CaCO3 (mg/L) Average ppm CaCO3 (mg/L):
- A 0.1510 g KHP (MW = 204.22 g/mol) sample required a volume of 57.04 mL of NaOH solution to reach a phenolphthalein end point. Calculate the molarity of NaOH titrant. (A) 0.02593 М (В) 0.01012 М 0.006481 M D) 0.01296 MConcentration sodium thiosulfate solution used: 0.056 mol L-1 ACCURATE TITRATION VOLUME OF SODIUM THIOSULFATE SOLUTION USED Volume titration 1, (ml) Volume titration 2, (mL) Your Group 15.80 15.75 Group 1 16.05 15.70 Group 2 16.30 16.25 ANALYSIS Average volume used, (mL) Standard deviation Unrounded value Rounded value5. A 300.0 mg sample containing Na,CO3, NaHCO, and NaOH and inert material either alone or in some combination was dissolved and titrated with 0.1000 M HCI the titration required 24.41 ml to reach the phenolphthalein endpoint. And an additional 8.67 mL to reach the methyl red endpoint. Determine the composition of the sample and calculate the percent of each titrated component.