Question: How can this IR graph of the crude product be an evadience that proof it is pure and the same as the product in the reaction? 60 50 40 30 20 4000 3491.185 3500 3088 205 2935.719 COP OH 3000 Crude product IR graph +3 2500 2000 Wavenumbers (cm-1) 9-anthracenemethanol N-methylmaleimide 1788 247 H₂O A 1hr 008 9071 1680.148- on 1500 009 998 4900 1890 1124 301-1072 RR m 1000 500 OH 9-(hydroxymethyl)-13-methyl-9, 10- dihydro-9,10-[3,4]epipyrroloanthracene- 12,14-dione Product Write your answer using this example as a guide. it should be in the same (fill in the blank) (keep in mind that 9-anthracenmethanol is the starting material should compare with) The crude product was crystallized to synthesize the product (0.246 g, 60 %) as white, needle-like crystals; IR: ------(cm³). Comparison of the IR spectrum of the product (polycyclic imide) with the IR spectrum of the starting material (9-anthracene-methanol) revealed an which was not present in the starting material. This also confirmed successful- The starting material, 9-anthracene-methanol contains a that is not found in the product. The IR of the final product had an absorption at, (cm³)., which is indicative of
Question: How can this IR graph of the crude product be an evadience that proof it is pure and the same as the product in the reaction? 60 50 40 30 20 4000 3491.185 3500 3088 205 2935.719 COP OH 3000 Crude product IR graph +3 2500 2000 Wavenumbers (cm-1) 9-anthracenemethanol N-methylmaleimide 1788 247 H₂O A 1hr 008 9071 1680.148- on 1500 009 998 4900 1890 1124 301-1072 RR m 1000 500 OH 9-(hydroxymethyl)-13-methyl-9, 10- dihydro-9,10-[3,4]epipyrroloanthracene- 12,14-dione Product Write your answer using this example as a guide. it should be in the same (fill in the blank) (keep in mind that 9-anthracenmethanol is the starting material should compare with) The crude product was crystallized to synthesize the product (0.246 g, 60 %) as white, needle-like crystals; IR: ------(cm³). Comparison of the IR spectrum of the product (polycyclic imide) with the IR spectrum of the starting material (9-anthracene-methanol) revealed an which was not present in the starting material. This also confirmed successful- The starting material, 9-anthracene-methanol contains a that is not found in the product. The IR of the final product had an absorption at, (cm³)., which is indicative of
Chapter24: Introduction To Spectrochemical Methods
Section: Chapter Questions
Problem 24.28QAP
Related questions
Question
could u please help me work out this problem
thanks
Expert Solution
Step 1
Given that, a synthesis from 9-anthracenemethanol by reacting with N-methylmaleimide to form 9-(hydroxymethyl)-13-methyl-9,10-dihydro-9,10-[3,4]-epipyrroloanthracene-12,14-dione.
We have to discuss about the formation of the product from the 9-anthracenemethanol using the given IR spectrum of the crude product.
Step by step
Solved in 2 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you