For questions 1 through 9, the following units apply: Hemoglobin: g/L, Hematocrit: L/L andRBC: x 10¹2 cells/L.Part CCalculate the MCV given the following information:1. Hct. 0.21, RBC count = 3.22. Hct. 0.45, RBC count = 4.53. Hct.= 0.33, RBC count = 2.7Calculate the MCH given the following information:4. Hgb. 100, RBC count = 3.05. Hgb. 180, RBC count = 3.76. Hgb. = 140, RBC count 3.3Calculate the MCHC given the following information:7. Hgb.160, Hct. = 0.368. Hgb. 50, Hct. = 0.159. Hgb. 150, Hct. = 0.45

Hematocrit is the percentage of RBC in blood. MCV is the volume of RBC. Detailed solution in step…

Answered: For questions 1 through 9, the…

Human Physiology: From Cells to Systems (MindTap Course List)

9th Edition

ISBN:9781285866932

Author:Lauralee Sherwood

Publisher:Lauralee Sherwood

Chapter11: The Blood

Section: Chapter Questions

Problem 3SQE

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For questions 1 through 9, the following units apply: Hemoglobin: g/L, Hematocrit: L/L and RBC: x 1012 C cells/L. Calculate the MCV given the following information: = 0.21, RBC count = 3.2 2. Hct.= 0.45, RBC count = 4.5 3. Hct. = 0.33, RBC count = 2.7 1. Hct. Calculate the MCH given the following information: 4. Hgb. 100, RBC count = 3.0 5. Hgb. 180, RBC count = 3.7 6. Hgb. = 140, RBC count 3.3 Calculate the MCHC given the following information: 7. Hgb. = 160, Hct. = 0.36 8. Hgb. = 50, Hct. = 0.15 9. Hgb. = 150, Hct. = 0.45
For another patient, the following results are obtained: RBC count = 3.20 x 1012/L HGB = 5.8 g/dL. HCT = 18.9% (0.19 L/L) 1. Calculate the red blood cell indices. 2. How would you describe the red blood cell volume and hemoglobin concentration based on these indices? 3. How should you verify this?
Given: RBC count = 8 x 10 12/L Hematocrit = ht of PCV = 38 mm; = ht of WB = 100 mm Hemoglobin = 124 g/L 1. Check the results using the rule of three (expected Hct and Hb range based on the rule of three) 2. Compute for MCV (Mean Corpuscular Volume), Mean corpuscular hemoglobin (MCH), and mean corpuscular hemoglobin concentration (MCHC 3. Describe the RBCs expected to be seen on the PBS 4. Are the values reportable? Why?
Calculate the number of RBC per 1 mm3. The volume of 1R is 0.004 mm3, the RBC count in 5R equals to 250, and the dilution factor is 1:200 O5 million cells/mm3 2.5 million cells/mm3 25 million cells/mm3 1.25 million cells/mm3 OOO
An 80-year-old man is seen for an annual physical examination. He complains of shortness of breath on exertion and is often tired. His stool is black. Laboratory data are: Hemoglobin: 8.2 g/dL Hematocrit: 30% White cell count: 4.2 × 109/L White cell differential: Neutrophils: 60% Lymphocytes: 31% Monocytes: 7% Eosinophils: 2% Basophils: 0% Red cell count: 4.0 × 1012/L RDW: 20% Platelet count: 400 × 109/L Reticulocyte count: 1.2% Stool occult blood: Positive 1. What is the most probable type of anemia seen in this patient? 2. What is the cause of the anemia seen in this patient?
An 80-year-old man is seen for an annual physical examination. He complains of shortness of breath on exertion and is often tired. His stool is black. Laboratory data are: Hemoglobin: 8.2 g/dL Hematocrit: 30% White cell count: 4.2 × 109/L White cell differential: Neutrophils: 60% Lymphocytes: 31% Monocytes: 7% Eosinophils: 2% Basophils: 0% Red cell count: 4.0 × 1012/L RDW: 20% Platelet count: 400 × 109/L Reticulocyte count: 1.2% Stool occult blood: Positive Critical Thinking Questions 1. What is the most probable type of anemia seen in this patient? 2. What is the cause of the anemia seen in this patient?
Give the relative abundance of the nine different cells( as mentioned below) in one cubic centimeter of blood sample. a. The human erythrocytes b. Granulocytes 1. neutrophil 2. eosinophil 3. basophils c.agranulocytes 1. Lymphocytes 2. Monocytes 3 platelets 4. Frog erythrocytes 5. Frog thrombocytes
1/ The volume of blood in an average-sized person (70 kg; 154 Ibs) is approximately 6 L. WHAT IS Erythrocyte volume ?[NORMAL Ht 47%] A/ 3 L B/ 2.5 L C/6L D/2.82 L 2/ WBC = 4.3 Neutrophils = 50% differential neutrophil count [ANC]? A/ ANC of 2,150 B/ ANC of 6,150 C/ ANC of 150 D/ ANC of 16,1 50
Given that: Hb= 13.0g/ L, Hct=39% , RBC=4.5×10^12. Calculate: a: MCH. b: MCHC. c: MCV. Given: Hb=12.0g/dl, Hct=36% RBC= 4.0×10^12, Calculate: a: MCH. b: MCHC. c: MCV. Given: Hb=15.0g/ dl , Hct=45%, RBC= 5.0×10^12. Calculate: a: MCH b: MCHC. c: MCV. Name term given to these calculated values.

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