MODFLOW (or SWAT+) for groundwater contaminant transport and fate modeling
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- PROBLEM #5 gaa is being air film at & total 'pressure of 1:l bar- The paitial att 'one boundang at the other, The partial pressure remains com tant a transfered across a staghant pressure of the gas is' 0.45 bar of the film and 0. 12 bar a Find: an) effect m diffusiom coefficient if mass transfer rate'doubles bi) total pressure mass transter rate heeded to dowble the of the gasSubject: Air Pollution Formation and Control Do not just copy and paster other online answers Estimate the total volumetric flow rate gas and the total mass emission rate of the particles in Fig 4.3. Ans : (a) volumetric flowrate = 1.9E3 ft3/s or 1.1E5 acfm ; (b) mass flowrate = 58 lbm/hr55°C methanol flows over a 4m long 2m width flat plate with temperature of 25 C. The velocity of methanol is 1.08 km/h. Determine the total drag force and the rate of heat transfer from the entire plate. What is the value of x_ and what does it mean?
- 300°C steam flows in a stainless-steel (ss.) pipe with thermal conductivity of 50 W/m.K. The pipe has internal diameter (ID) of 40 cm, and outer diameter (OD) of 42 cm. The pipe is placed in another ss. pipe with ID and OD 44 cm and 44.2 cm, respectively. The gap between the pipes is filled with steel air (use air properties at 160°C from appendix). The convection heat transfer coefficient at the inner and the outer surfaces of the pipe is hi = 40 W/m2. K and h2= 15 W/m?. K. Determine the rate of heat loss if the length of the pipe %3! is 10 m. Also determine the temperature at inside, intermediate and outer surfaces.Topic: Heat transfer Completely solve and box the final answer. 5. Water flows at 5m/s is passed through a tube of 2.5 cm diameter, it is found to be heated from 20degC to 60degC. The heating is achieved by condensing steam on the surface of the tube and subsequently the surface temperature of the tube is maintained at 90degC. Water properties are as follows: density=995kg/m3, kinematic viscosity=.657x10-6 m2/s, Pr=4.43, k=.628W/mK, cp=4178J/kgK. Find the thermal coefficient.Topic: Heat transfer Completely solve and box the final answer. 6. Water flows at 5m/s is passed through a tube of 2.5 cm diameter, it is found to be heated from 20degC to 60degC. The heating is achieved by condensing steam on the surface of the tube and subsequently the surface temperature of the tube is maintained at 90degC. Water properties are as follows: density=995kg/m3, kinematic viscosity=.657x10-6 m2/s, Pr=4.43, k=.628W/mK, cp=4178J/kgK. What is the heat absorbed by the water?
- The Air on 1 ATM on T. 250 K And the free flow rate is 30 meters It flows across a diameter cylinder 2,5 cm The cylinder 'surface is guarded on temperature 350 k, count : *) The rate of heat transfer is 1 meter long Cylinder >The Air on 1st atmosphere on T = 250 K And the free flow rate is 30 meters It flows across a diameter cylinder 2,5 cm The cylinder 'surface is guarded on temperature 350 k.count : coefficient heat transfers.Differantial Equations
- No card B a m OO ON 95)1:45 mlms.hu.edu.jo/mod/qu P Flag question Air is contained in a piston cylinder device, it expands first isothermally (1=>2) then isobaric expansion takes place (2=>3). The processes on the T-v diagram will be: Select one: A. (1-2) Horizontal line, (2- 3) Inclined line with Positive slope. B. (1-2) Horizontal line, (2- 3) Inclined line with Negative slope. O c. (1-2) Inclined line with Positive slope, (2-3) Horizontal line. D. (1-2) Horizontal line, (2- 3) Vertical line downward. E. (1-2) Inclined line with Negative slope, (2-3) Horizontal line. F. (1-2) Horizontal line, (2- 3) Vertical line upward. ...Specific Heat, Cp Water Thermal Thermal Content, Temperature, T Density, p Conductivity, k Ibm/ft3 Diffusivity, a ft2/s Food %(mass) °F Btu/h-ft.°F Btu/lbm-R Fruits/Vegetables Apple juice Apples Apples, dried Apricots, dried Bananas, fresh 1.51 x 10-6 1.47 x 10-6 87 68 62.4 0.323 0.922 85 32-86 52.4 0.242 0.910 41.6 73 53.4 0.127 1.03 x 10-6 0.650 1.22 x 10-6 1.51 × 10-6 43.6 73 82.4 0.217 0.662 76 41 61.2 0.278 0.856 Broccoli 21 35.0 0.223 | 1.42 x 10-6 Cherries, fresh Figs Grape juice 92 32-86 65.5 0.315 0.952 40.4 73 77.5 0.179 1.03 x 10-6 0.642 1.51 × 10-6 1.51 × 10-6 89 68 62.4 0.328 0.934 Peaches 36-90 2-32 59.9 0.304 0.934 Plums 3 38.1 0.143 | Potatoes 32-158 0-70 65.7 0.288 1.40 x 10-6 0.868 Raisins 32 73 86.2 0.217 1.18 x 10-6 0.592 Meats Beef, ground Beef, lean 67 43 59.3 0.235 1.40 x 10-6 0.802 74 37 68.0 0.272 1.40 x 10-6 0.844 Beef fat 95 50.5 0.110 72 95 73 Beef liver 0.259 0.832 1.18 x 10-6 1.40 x 10-6 Cat food 39.7 71.2 0.188 0.638 Chicken breast 75 32 65.5 0.275 0.850A fluid at 0.7 bar occupying 0.09m³ is compressed reversibly to a pressure of (a) 3.5 bar according to a law pv" = constant. The fluid is then heated reversibly at constant volume until the pressure is 4 bar: the specific volume is then 0.5m³/kg. A reversible expansion according to a law pv = constant restores the fluid to its initial state. Sketch the cycle on a p-v diagram and calculate: i) the mass of the fluid present; ii) the value of n in the first process; 1. iii) the net work of the cycle.